Question 1
Question
Why are 'step climbs' used on long distance flights ?
Answer
-
Step climbs do not have any special purpose for jet
aeroplanes; they are used for piston engine aeroplanes only.
-
To respect ATC flight level constraints.
-
To fly as close as possible to the optimum altitude as
aeroplane mass reduces.
-
Step climbs are only justified if at the higher altitude less
headwind or more tailwind can be expected.
Question 2
Question
If the take-off mass of an aeroplane is brake energy
limited a higher uphill slope would
Answer
-
have no effect on the maximum mass for take-off.
-
decrease the required take-off distance.
-
increase the maximum mass for take-off.
-
decrease the maximum mass for take-off.
Question 3
Question
The approach climb requirement has been established
so that the aeroplane will achieve:
Answer
-
manoeuverability during approach with full flaps and gear
down, all engines operating.
-
minimum climb gradient in the event of a go-around with one
engine inoperative.
-
obstacle clearance in the approach area.
-
manoeuverability in the event of landing with one engine
inoperative.
Question 4
Question
In which of the following distances can the length of a
stopway be included?
Answer
-
In the accelerate stop distance available.
-
In the one-engine failure case, take-off distance
-
In the all-engine take-off distance
-
In the take-off run available
Question 5
Question
For jet aeroplanes which of the following statements is
correct?
Answer
-
When determining the maximum allowable landing mass at
destination, 60% of the available distance is taken into
account, if the runway is expected to be dry.
-
In any case runway slope is one of the factors taken into
account when determining the required landing field length.
-
An anti-skid system malfunction has no effect on the
required landing field length.
-
The required landing field length is the distance from 35 ft to
the full stop point.
Question 6
Question
On a dry runway the accelerate stop distance is
increased
Question 7
Question
With regard to a unaccelerated horizontal flight, which
of the following statement is correct?
Answer
-
The minimum drag is independant of the aircraft mass.
-
The minimum drag is proportional to the aircraft mass.
-
The minimum drag is a function of the pressure altitude.
-
The minimum drag is is a function of the density altitude.
Question 8
Question
With an true airspeed of 194 kt and a vertical speed of 1
000 ft/min, the climb gradient is about :
Question 9
Question
Concerning the landing gear, which of the following
factors would limit the take-off mass?
Answer
-
Nitrogen pressure in the strut and brake temperature.
-
Rate of rotation of the wheel at lift off and brake energy
-
Tyre pressure and brake temperature.
-
Rate of rotation of the wheel and tyre pressure.
Question 10
Question
Which of the following speeds can be limited by the
'maximum tyre speed'?
Answer
-
Lift-off groundspeed
-
Lift-off IAS.
-
Lift-off TAS.
-
Lift-off EAS.
Question 11
Question
The maximum operating altitude for a certain aeroplane
with a pressurised cabin
Answer
-
is dependent on aerodynamic ceiling
-
is dependent on the OAT.
-
is only certified for four-engine aeroplanes
-
is the highest pressure altitude certified for normal operation
Question 12
Question
A higher outside air temperature (OAT)
Answer
-
decreases the brake energy limited take-off mass.
-
increases the field length limited take-off mass.
-
increases the climb limited take-off mass.
-
decreases the take-off distance.
Question 13
Question
The stalling speed or the minimum steady flight speed
at which the aeroplane is controllable in landing
configuration is abbreviated as
Question 14
Question
If the take-off mass of an aeroplane is tyre speed limited,
downhill slope would
Answer
-
increase the maximum mass for take-off.
-
increase the required take-off distance
-
have no effect on the maximum mass for take-off.
-
decrease the maximum mass for take-off.
Question 15
Question
What will be the effect on an aeroplane's performance if
aerodrome pressure altitude is decreased?
Answer
-
It will increase the take-off distance required.
-
It will increase the take-off ground run.
-
It will increase the accelerate stop distance.
-
It will decrease the take-off distance required
Question 16
Question
An aeroplane carries out a descent from FL 410 to FL
270 at cruise Mach number, and from FL 270 to FL 100 at
the IAS reached at FL 270.
How does the angle of descent change in the first and in
the second part of the descent?
Assume idle thrust and clean configuration and ignore
compressibility effects.
Answer
-
Increases in the first part; is constant in the second
-
Increases in the first part; decreases in the second.
-
Is constant in the first part; decreases in the second.
-
Decreases in the first part; increases in the second.
Question 17
Question
A constant headwind component
Answer
-
increases the angle of flight path during climb
-
increases the best rate of climb.
-
decreases the angle of climb.
-
increases the maximum endurance
Question 18
Question
Higher gross mass at the same altitude decreases the
gradient and the rate of climb whereas
Question 19
Question
In case of an engine failure which is recognized at or
above V1
Answer
-
the take-off should be rejected if the speed is still below VR.
-
the take-off must be continued
-
the take-off must be rejected if the speed is still below VLOF.
-
a height of 50 ft must be reached within the take-off
distance.
Question 20
Question
When flying the "Backside of Thrustcurve" means
Answer
-
a lower airspeed requires more thrust.
-
the thrust required is independent of the airspeed.
-
a thrust reduction results in an acceleration of the aeroplane
-
a lower airspeed requires less thrust because drag is
decreased.
Question 21
Question
VR cannot be lower than:
Question 22
Question
Given:
VS= Stalling speed
VMCA= Air minimum control speed
VMU= Minimum unstick speed (disregarding engine
failure)
V1= take-off decision speed
VR= Rotation speed
V2 min.= Minimum take-off safety speed
VLOF: Lift-off speed
The correct formula is:
Answer
-
VR< VMCA< VLOF
-
VMU<= VMCA< V1
-
V2min< VMCA> VMU
-
VS< VMCA< V2 min