Created by emma.martin18
over 11 years ago
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2.5,4.5,6.5,8.5
nth term=?
-7, -4, -1, 2, 5
nth term=?
rearrange to get x by itself...
x+b=e
multiply out... 2(x+1)+3(x+3)
multiply out... 2(4x+3)+4(3x+4)
rearrange to make x the subject...
ax=b
multiply out... 3(4x+5)
multiply out... 5(6x-1)
rearrange to make x the subject...
ux-h=m
multiply out... 4x+5(2x+1)
rearrange to make x the subject...
xa+k=m²
multiply out... 8(1+2x)-5
rearrange to make x the subject...
d(x+e)=f
rearrange to make x the subject...
d(x+e)=f
rearrange to me x the subject...
m(x+m)=n²
rearrange to make x the subject...
m(b+x)=e
rearrange to make x the subject...
x/p=a
multiply out... 4(3x-2)-10x
rearrange to make x the subject...
x/a=(b+c)
solve... 10n=3n+21
rearrange to make x the subject...
x/h=c/d
solve... 1+3n=n+2
solve... 5n-4=n
p=6q+5
Find p when q=13
solve... 3(x+2)=2(x+5)
solve... 5(x-2)=3(x+2)
180(n-2)
n=6
solve... 6x-10=2(x+7)
solve... 4(2x-1)=3(x+1)-2
solve... 6+3(x+2)=2(x+5)+4
p=100+2x
x=3
solve... 3x+2(x+1)=3x+12
solve... 4x-2(x+4)=x+1
p=100+2x
x=1/2
form and solve this equation...
think of a number, multiply by 3, add 1, the answer is 19.
n(n+1)/2
n=99
z=3(2x+5)
x=2
t=5a+2n
a=3 n=4
form and solve this equation...
think of a number, add 5, multiply by 4, the answer is 58.
the length of a rectangle is double the width... the perimeter of the rectangle =30cm... find the width
2(n²)+2n
n=2
v=3r²h
r=5 h=4
c=mx+7
m=5 x=1
t=a²+3a-5
a=10
t=a²+3a-5
a=1
simplify 3b-3a-5c+4b
simplify 5x+3y-6x+4y+3z
factorise... 6x²+9x
factorise... 10x⁵-15x³
expand... (x+2)(x+7)
expand... (2x-4)²
expand... (x-3)(x+3)
3, 7, 11, 15
nth term=?
expand... (3x+4)(x-2)
(x+4)²
(2x+1)²
expand... (x+2)²+(2x+1)²
expand... (x-3)²-(x+1)²
x=3y+2
Find x when y=4
a=4b=1
Find a when b=5
c=d/5+3
Find c when d=15
e=f/2-4 Find e when f=8