188843
Description
Flashcards by Sally Davis, updated more than 1 year ago
|
Created by Sally Davis
over 10 years ago
|
|
| Question | Answer |
| When multiplying do you times or add powers? \(x^3\) x \(x^5\) = ? | Add \(x^3\) x \(x^5\) = \(x^8\) |
| Solve ( \(x^3\) ) \(^3\) | x = 9 Powers times together normally |
| Solve (3\(x^3\) )\(^3\) | 27\(x^9\) It's 3 x3 x3 |
| Solve \[\frac{x^9}{x^7}\] | \(x^2\) You subtract powers if they're in a fraction |
| Simplify \[\frac{15x^2y}{12xy^4}\] | \[\frac{5x}{4y^3}\] Find what goes into both numbers and find common letters |
| Simplify \[\frac{(3p^2q)^3 x (2pq^2)^2}{54p^7q^8}\] | \[\frac{2p}{q}\] Don't forget to simplify! |
| Adding fractions Solve: \(\frac{x}{3}\)+ \(\frac{y}{2}\) | \[\frac{2c+3y}{6}\] Upside down BBQ table |
| Multiplying fractions Solve: \(\frac{ab}{d^2}\)x\(\frac{4a}{3b}\) | \[\frac{4a^2}{3d^2}\] You just turn letters into powers and don't forget to simplify at the end!! |
| Dividing fractions Solve: \(\frac{6p^2q}{7p}\)% \(\frac{2p^3}{3q}\) | Swap the last fraction around and turn it into multiplication \[\frac{9q^2}{7p^2}\] |
| *TIP* EXPAND QUADS IN A PUNNET SQUARE! | SO MUCH EASIER :D |
| Expand this quad: (x+2)(x-7) | \(x^2\)-5x-14 You times everything together quadruple rainbow |
| Expand: (x-5)\(^2\) | (x-5)(x-5) Put into brackets |
| Factorise: \(x^2\)+7x+10 | (x+2)(x+5) Something that adds to the x factor and multiples to make the end number |
| \(x^2\)-49 | (x-7)(x+7) Add together to make 0, Pretend there is a 0x in the middle |
| Solve: \(x^2\)=27 | x=3 3%3%3 |
| Make n the subject: 6( \(\frac{n}{4}\)-5) | n=4( \(\frac{d}{6}\)+5) move the six first, then five, move the four but make sure the others are in a bracket. |
| Factorise: \(x^2\)+30x+200=2000 | (x+6)(x-3) - Make it equal 0 - Factorise |
| A wire frame is made so its length is 'l' is 4cm longer than its width 'w'. It's height 'h' is 1cm shorter than it's width. Write an expression for both height and length | h=w-1 l=w+4 |
Want to create your own Flashcards for free with GoConqr? Learn more.