Algebra

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This is a simple Algebra A Level GCSE Questions to test yourself
MaryJo Lynn Hefferon
Flashcards by MaryJo Lynn Hefferon, updated more than 1 year ago More Less
Alex Maraio
Created by Alex Maraio over 10 years ago
MaryJo Lynn Hefferon
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Resource summary

Question Answer
Factorise \[3x^2 +12x\] \(3x(x+4)\)
Expand \((x+2)^2\) \(x^2+4x+4\)
Factorise \[x^2-3x-18\] \((x-6) (x+3)\)
Expand \[(2a+5)(2a-5)\] \[4a^2-25\]
Factorise \[a^2-9\] \[(a+3)(a-3)\]
Simplify \[ \frac{x+2}{3} + \frac{x-3}{4}\] \[\frac{7x-1}{12}\]
Simplify \[\frac{2(x+1)}{x^2+2x-3} + \frac{3(x+3)}{x^2+2x-3} \] \(\frac{5x+7}{x^2+2x-3} \)
Expand \[(a^2-4)(a-2)\] \(a^3-2a^2-4a+8\)
Remember \[FOIL\] \[First\] \[Outsides\] \[Insides\] \[Last\]
Simplify \[\frac{3a}{a^2-4} + \frac{2}{a-2} \] \(\frac{5a^2-6a-8}{a^3-2a^2-4a+8} \)
Find \(X\) \[\frac{5x-3}{2} + \frac{x+7}{3} \] \[=15\] \(x=5\)
Find \(X\) \[\frac{2}{x+8} + \frac{1}{x-2}\] \[=\frac{1}{3}\] \(x = 7 or -4\)
What's the quadratic formula?
Simplify \[\sqrt{48}\] \[4\sqrt{3}\]
Simplify \[\sqrt{50}\] \(5\sqrt{2}\)
Simplify \[\sqrt{120}\] \(2\sqrt{30}\)
Simplify \[\sqrt{45} + \sqrt{20}\] \(5\sqrt{5}\)
Rationalise the denominator of \[\frac{2}{\sqrt{3}}\] \(\frac{2\sqrt{3}}{3}\)
\(125^\frac{4}{3}\) \(625\)
\(3^{-2}\) \(\frac{1}{9} or \dot{0.1} \)
\(81^\frac{3}{4}\) 9
Solve \[x^\frac{1}{2} = 3\] \(x=9\)
Solve \[x^\frac{1}{2} = \frac{1}{3}\] \(x=\frac{1}{9}\)
Solve \(3a-b=17\) \[a+2b=1\] \( a=5, b=-2 \)
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