Substitution Reactions

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AS Level F322: Chemistry (Alkanes) Mind Map on Substitution Reactions, created by anndjan21 on 28/02/2015.
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Mind Map by anndjan21, updated more than 1 year ago
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Substitution Reactions
  1. Alkanes
    1. Alkanes - inert compounds - lack of polarity. C + H have v. similar electronegativities - alkanes non-polar molecules. Not readily attacked by common chemical reagents.
      1. E.g. water, acids, alkalis + many oxidisiding + reducing agents are polar + usually initiate reactions by attraction to polar groups in other compounds. Such polar reagents don't react with alkanes.
        1. Some non-polar reagents will react with alkanes - halogens. In prescence of UV light - will subsitute H atoms in alkane with halogen atoms. E.g. when Cl mixed with methane + exposed to sunlight, chloromethane formed + hydrogen Cl gas evolved:
          1. CH₄(g) + Cl₂(g) → CH₃Cl(g) + HCl(g)
            1. Because reaction requires ultraviolet light - called photochemical reaction.
              1. Further substitution possible, producing dichloromethane, trichloromethane + tetrachloromethane. Other halogens e.g. Br produces similar substitution products. E.g. hexane, Br produces bromohexane:
                1. C₆H₁₄(l) + Br₂(l) → C₆H₁₃Br(l) + HBr(g)
            2. Substitution Mechanism
              1. Sequence of stages known as mechanism of reaction. E.g. mechanism of UV light sufficient to break Cl-Cl bond. Absorption of light energy causing bond to break known as photodissociation.
                1. Homolytic fission occurs + 2 Cl atoms formed, each having 7 electrons in outer shell. Cl atoms each have 1 unpaired electron + thus free radicals.
                  1. Free radicals react v. rapidly with other molecules/chemical species. As homolytic fission of Cl product molecule must occur before any chloromethane can be formed.
                    1. Initiation
                      1. Cl₂(g) → Cl∙(g) + Cl∙(g)
                    2. Propagation
                      1. Reaction of Cl free radical with methane molecule produces hydrogen chloride + CH₃∙ (methyl) radical. Dot indicates unpaired electron. C atom in this CH₃∙ fragment also has 7 electrons in its outer shell.
                        1. Methyl free radical can react with Cl molecule to produce chloromethane + new Cl free radical:
                          1. Cl∙(g) + CH₄(g) → HCl(g) + CH₃∙(g)
                            1. CH₃∙(g) + Cl₂(g) → CH₃Cl(g) + Cl∙(g)
                          2. 2 steps enable reaction to continue. 1st step, Cl radical used up. 2nd step releases new Cl free radical - allows repetition of 1st step. Reaction will continue as long as there's supply of methane molecules + undissociated Cl molecules.
                            1. 2 steps constitute chain reaction + known as propagation steps of reaction. More propagation steps can occur; involving products of earlier propagation steps:
                              1. Cl∙(g) + CH₃Cl(g) → HCl(g) + CH₂Cl∙(g)
                                1. CH₂Cl∙(g) + Cl₂(g) → CH₂Cl₂(g) + Cl∙(g)
                            2. Termination
                              1. Reaction to form various substituted chloromethanes + hydrogen chloride ceases when supply of reagents is depleted. Variety of possible termination steps - take place when 2 free radicals meet:
                                1. Cl∙(g) + CH₂Cl∙(g) → CH₂Cl₂(g)
                                  1. CH₂Cl∙(g) + CH₂Cl∙(g) → C₂H₄Cl₂(g)
                                2. Also include recombination of 2 Cl free radicals to form Cl molecules. Alternatively, 2 methyl free radicals can combine to form ethane molecule:
                                  1. Cl∙(g) + Cl∙(g) → Cl₂(g)
                                    1. CH₃∙(g) + CH₃∙(g) → CH₃CH₃(g)
                                  2. These/any other termination steps will remove free radicals + disrupt propagation steps - stopping chain reaction. Mixture of products obtained, making free radical reactions unsuitable for preparation of pure product.Reaction = free-radical substitution.
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