$-4+4 x+25 x$

$-4+ x^3+x^4$

$-4+4 x^3+25 x^4$

$\frac{1}{4 x^{3/4}}+\frac{1}{2 \sqrt{x}}-\frac{3 x^2}{5 \left(x^3\right)^{4/5}}$

$\frac{1}{4 x^{1/4}}+\frac{1}{5 \sqrt{x}}-\frac{3 x^3}{6 \left(x^3\right)^{4/5}}$

$\frac{1}{4 x^{3/4}}+\frac{1}{2 \sqrt{x}}-\frac{3 x^4}{-7 \left(x^6\right)^{3/2}}$

$(2 x+3) \text{Cos}[x]$

$\left(3 x+x^2\right)\text{Sin}[x] +(3+2 x) \text{Cos}[x]$

$\left(3 x+x^2\right) \text{Cos}[x]+(3+2 x) \text{Sin}[x]$

$\frac{-1-e^x+e^x x}{x^2}$

$\frac{e^x}{1}$

$\frac{\left(e^x+1\right)+(x)e^x}{x^2}$

$\frac{20 x^3}{\sqrt{1-x^8}}$

$\frac{3x^4}{\sqrt{x^4-1}}$

$\frac{x^4}{\sqrt{1-x^2}}$

$3 (x \text{Cos}[x])^2$

$3 (x \text{Cos}[x])^2 (-x \text{Sin}[x]+\text{Cos}[x])$

$3 (-x \text{Sin}[x]+\text{Cos}[x])^2$

$\frac{1}{\text{ArcSin} x\text{ }}$

$\frac{1}{x }.\frac{1}{\sqrt{1-x^2}}$

$\frac{1}{\text{ArcSin} x \sqrt{1-x^2} }$

$\frac{10^x }{10^x\sqrt{\left(10^{ x}\right)^2-1}}$

$\frac{10^x \text{Ln}[10]}{x\sqrt{x^2-1}}$

$\frac{10^x \text{Ln}[10]}{10^x\sqrt{\left(10^{ x}\right)^2-1}}$

$\text{Cos}\left[3 x^3\right]-\text{Sin}[4 x]-\text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]$

$9 x^2 \text{Cos}\left[3 x^3\right]-4 \text{Sin}[4 x]-e^x \text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]$

$\text{Cos}\left[9 x^2 \right]- \text{Sin}[4]-\text{Sec}\left[e^x\right] \text{Tan}\left[e^x\right]$

$-\text{Csc}^2\left[e^{x+x^2} (1+2 x)\right]$

$-\text{Csc}^2\left[e^{x+x^2}\right]e^{x+x^2} (1+2 x)$

$-\text{Csc}^2\left[e^{x+x^2}\right]$

$\frac{6}{5} (3 x+5 \text{Cos}[x])^{\frac{1}{5}} (3-5 \text{Sin}[x])$

$\frac{6}{5} (3 x+5 \text{Cos}[x])^{\frac{1}{5}}$

$\frac{6}{5} (3-5 \text{Sin}[x])^{\frac{1}{5}}$