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646360
Exam 2
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ch 5-8
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Resumo de Recurso
Exam 2
CH 5: Circular Motion and Gravitation
period of motion =T= (2 pi r)/v
centripetal acceleration = ac = (v^2)/r
spinning rate = w = v/r
used in many cases
planet orbits, satellite orbits
theme park ride: turns, loops and hills
CH 6: Work and Energy
Work= Force multiplied by the difference of x multiplied by cos of the angle
Work is measure in Joules (J)
W= Fxcos(angle)
Energy: Kinetic and Potential
Kinetic Energy (KE)= 1/2 mv^2
Potential Energy (PE)= mgh
Mechanical Energy= mgh + 1/2 mv^2
E1 = E2
KEi + PEi = KEf + PEf
CH 8: Rotational Motion
Anexos:
Exam 1
Describing rotational motion
Rotational Quantities
Angular position = theta
theta = (s/r) where s is arc length, r is radius
Angular velocity = lowercase omega (fancy w)
omega = theta/time
Angular acceleration = alpha
alpha = omega/time
Radians
360 degrees = 2(pi) rad
Torque and Newton's Laws for rotational motion
torque = Force * radius
sigma torque = I * alpha
moment of inertia = I = dependent upon object and shape
Newton's second law for rotational motion
Rotational Equilibrium
total torque = 0
Rotational Dynamics
delta theta = (angular velocity)(delta time) + 1/2(alpha)(delta time ^2)
final angular velocity = (initial ang velocity) + (alpha)(delta time)
(ang velocity final ^2) = (ang velocity initial ^2) + 2(alpha)(delta theta)
Combined Rotational and Translational Motion
Arises in many cases
a rolling wheel
motion of a baseball bat
Rolling Motion
angular v * R = v = 2(pi)R / T
a = alpha * R
base ball bat scenario
more complex than rolling motion
involves linear and rotational:
quantities, dynamics, and center of mass
Chapter 7 - Momentum, impulse, and collisions
Momentum
Momentum(P) = mass x velocity
Momentum is conserved during collisions
Impulse
Impulse is the change in time multiplied by the force in question. This is the same as the change in momentum.
Collisions
Elastic collisions
Kinetic energy is conserved
KE1f+KE2f = KEi1+KEi2
momentum is conserved
Inelastic collisions
Kinetic energy is not conserved
KE1f+KE2f not equal to KE1i+KE2i
Vf = (m1v1i + m2v2i)/(m1+m2)
momentum is conserved
Kinetic energy = 1/2 mv
completely inelastic collisions
objects stick together after collisions
momentum still conserved
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