ГОС по БД #1

Questão 1 de 89

1

Define a degree of a relation

Selecione uma das seguintes:

How many rows a table has
how long each tuple is, or how many columns the table has
how many different tuples there are
how many different datatypes table has

Explicação

Questão 2 de 89

1

Define a cardinality of a relation

Selecione uma das seguintes:

how long each tuple is
how many columns the table has
how many different tuples there are, how many rows a table has
how many different datatypes table has

Explicação

Questão 3 de 89

1

Which of the following refers to union-compatibility requirements ?

Selecione uma das seguintes:

Same number of columns
Same number of rows
Same number of tuples
Different domains

Explicação

Questão 4 de 89

1

Which of the following refers to union-compatibility requirements ?

Selecione uma das seguintes:

Corresponding columns have the same domains
Same number of rows
Same number of tuples
Corresponding columns have the same fields

Explicação

Questão 5 de 89

1

Define a domain

Selecione uma das seguintes:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
minimality of the attribute

Explicação

Questão 6 de 89

1

Define a foreign key

Selecione uma das seguintes:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
minimality of the attribute

Explicação

Questão 7 de 89

1

Define a primary key

Selecione uma das seguintes:

restrict the possible values a tuple can assign to each attribute
relations to each other
uniquely identifies each tuple that appears in a relation
datatypes of attributes

Explicação

Questão 8 de 89

1

Define restrict

Selecione uma das seguintes:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explicação

Questão 9 de 89

1

Define cascade

Selecione uma das seguintes:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explicação

Questão 10 de 89

1

Define set default

Selecione uma das seguintes:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explicação

Questão 11 de 89

1

Define set null

Selecione uma das seguintes:

stop the user from doing it
let the changes flow on
make referencing values the default for their column
make referencing values null

Explicação

Questão 12 de 89

1

Define Data Definition Language

Selecione uma das seguintes:

Specify database format
Specify access controls (privileges)
Specify and retrieve database contents
Specify table attribute uniqueness

Explicação

Questão 13 de 89

1

Define Data Control Language

Selecione uma das seguintes:

Specify access controls (privileges)
Specify database format
Specify and retrieve database contents
Specify table attribute uniqueness

Explicação

Questão 14 de 89

1

Define Data Manipulation Language

Selecione uma das seguintes:

Specify table attribute uniqueness
Specify database format
Specify access controls (privileges)
Specify and retrieve database contents

Explicação

Questão 15 de 89

1

Which of the following does not refer to DBMS tools

Selecione uma das seguintes:

Oracle
PostgreSQL
MySQL
Python

Explicação

Questão 16 de 89

1

Which of the following is used to provide privilege to only a particular attribute?

Selecione uma das seguintes:

Grant select on employee to finance
Grant update(salary, rate) on employee to finance
Grant update(salary) on employee to finance
Grant delete to finance

Explicação

Questão 17 de 89

1

Which of the following statement is used to remove the privilege from the user finance?

Selecione uma das seguintes:

Remove update on employee from finance
Delete select on employee from finance
Revoke update on employee from finance
Grant update on employee from finance

Explicação

Questão 18 de 89

1

Which of the following is true regarding views?

Selecione uma das seguintes:

The user who creates a view cannot be given update authorization on a view without having update authorization on the relations used to define the view.
If a user creates a view on which no authorization can be granted, the system will allow the view creation request.
A user who creates a view receives all privileges on that view.

Explicação

Questão 19 de 89

1

If we wish to grant a privilege and to allow the recipient to pass the privilege on to other users, we append the __________ clause to the appropriate grant command.

Selecione uma das seguintes:

With grant
Grant user
With grant option
Grant pass privelege

Explicação

Questão 20 de 89

1

Which of the following is used to avoid cascading of authorizations from the user?

Selecione uma das seguintes:

Granted by current role
Revoke grant option for select on department from finance;
Revoke select on employee from finance, cashier restrict;
Revoke select on department from finance, cashier cascade;

Explicação

Questão 21 de 89

1

Privileges are granted over some specified parts of a database, such as a

Selecione uma das seguintes:

Schema
Environment
Relation Or view
Query statement

Explicação

Questão 22 de 89

1

Prevention of access to the database by unauthorized users is referred to as:

Selecione uma das seguintes:

Integrity
Productivity
Security
Reliability

Explicação

Questão 23 de 89

1

Database Authentication refers to:

Selecione uma das seguintes:

methods of restricting user access to system
controlling access to portions of database
all of the answers mentioned
controlling the operation on the data

Explicação

Questão 24 de 89

1

A set of possible data values is called

Selecione uma das seguintes:

attribute
degree
domain
tuple

Explicação

Questão 25 de 89

1

A functional dependency between two or more non-key attributes is called

Selecione uma das seguintes:

Partial transitive dependency
Functional dependency
Transitive dependency
Partial functional dependency

Explicação

Questão 26 de 89

1

__ refers to the correctness and completeness of the data in a database.

Selecione uma das seguintes:

Database security
Data constraint
Data integrity
Data independence

Explicação

Questão 27 de 89

1

Which of the following creates a virtual relation for storing the query?

Selecione uma das seguintes:

Function
Procedure
View
None of the mentioned

Explicação

Questão 28 de 89

1

Which of the following is the syntax for views where v is view name?

Selecione uma das seguintes:

Create view v as “query name”;
Create “query expression” as view;
Create view v as “query expression”;
Create view “query expression”;

Explicação

Questão 29 de 89

1

Updating the value of the view

Selecione uma das seguintes:

Will not change the view definition
Will not affect the relation from which it is defined
Will affect the relation from which it is defined
Cannot determine

Explicação

Questão 30 de 89

1

Create view faculty as: Select ID, name, dept name from instructor; Find the error in this query.

Selecione uma das seguintes:

Instructor
Select
None of the mentioned
View …as

Explicação

Questão 31 de 89

1

Which of the following is a basic form of grant statement?

Selecione uma das seguintes:

Grant ‘privilege list’ on ‘user/role list’ to ‘relation name or view name’;
Grant ‘privilege list’ to ‘user/role list’;
Grant ‘privilege list’ on ‘relation name or view name’ to ‘user/role list’;
Grant ‘privilege list’ on ‘relation name or view name’ on ‘user/role list’;

Explicação

Questão 32 de 89

1

Retrieve all data from the table OFFICE { id,room, name}

Selecione uma das seguintes:

Select *from office;
Select from office;
Select name from office;
Select *form office;

Explicação

Questão 33 de 89

1

Retrieve office name from the table OFFICE {id, room, name}

Selecione uma das seguintes:

Select *from office;
Select from office;
Select name from office;
Select *form office;

Explicação

Questão 34 de 89

1

Retrieve office id from the table OFFICE {id, room, name}

Selecione uma das seguintes:

Select *from office;
Select id from office;
Select name from office;
Select id form office;

Explicação

Questão 35 de 89

1

Retrieve office id and room from the table OFFICE {id, room, name}

Selecione uma das seguintes:

Select *from office;
Select id, room from office;
Select room name from office;
Select id form office;

Explicação

Questão 36 de 89

1

Retrieve quantity of offices in the office table - OFFICE {id, rom, name}

Selecione uma das seguintes:

Select avg (id) from office;
Select count (id) from office;
Select sum (id) from office;
Select max (id) from office;

Explicação

Questão 37 de 89

1

Retrieve total number scholarship in the students table – STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select avg (scholarship) from office;
Select count (scholarship) from office;
Select sum (scholarship) from office;
Select max (scholarship) from office;

Explicação

Questão 38 de 89

1

Retrieve quantity of students in the students table – STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select avg (id) from office;
Select count (id) from office;
Select sum (id) from office;
Select max (id) from office;

Explicação

Questão 39 de 89

1

Sort students name by descending order - STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select name from students order by desc;
Select name from students group by desc;
Select *from students order by desc;
Select name form students order by desc;

Explicação

Questão 40 de 89

1

Find an average scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select sum (scholarship) from students;
Select max (scholarship) from students;

Explicação

Questão 41 de 89

1

Find maximum scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select sum (scholarship) from students;
Select max (scholarship) from students;

Explicação

Questão 42 de 89

1

Find minimum scholarship of students - STUDENTS {id, name, scholarship, registereddate, tutorid}

Selecione uma das seguintes:

Select avg (scholarship) from students;
Select count (scholarship) from students;
Select min (scholarship) from students;
Select max (scholarship) from students;

Explicação

Questão 43 de 89

1

Retrieve offices’ name and tutors’, who work in CSSE department. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, OFFICEID (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name = ‘CSSE’
Select o.name, t.name from office o join tutor t on o.id=t.id where o.name = ‘CSSE’
Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name = ‘csse’
Select o.name, t.name from office o join tutor t on o.id=t.officeid where o.name ‘CSSE’

Explicação

Questão 44 de 89

1

Retrieve all offices’ name and tutors’, who work in departments. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

Select o.name, t.name from office o left join tutor t on o.id=t.officeid;
Select o.name, t.name from office o left join tutor t on o.id=t.id ;
Select o.name, t.name from office o right join tutor t on o.id=t.officeid;
Select o.name, t.name from office o right join tutor t on o.id=t.id ;

Explicação

Questão 45 de 89

1

Retrieve students’ name, who have more than average scholarship. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select s.name from students s where s.scholarship > (select avg (scholarship)from students);
select s.name from students s where s.scholarship > (select scholarship from students);
select s.name from students s where s.scholarship > avg (scholarship);
select s.name from students s where s.scholarship < avg (scholarship);

Explicação

Questão 46 de 89

1

Retrieve students’ name, who registered in 10th of Jan 2016. Tables: STUDENTS {id (PK), name, scholarship, registereddate, tutorid }.

Selecione uma das seguintes:

select name from students where registereddate = '2016-01-10';
select name from students where registereddate = '2016-10-10';
select name from students where registereddate = 2016-10-10;
select name from students where registereddate = '2016-01-01';

Explicação

Questão 47 de 89

1

Retrieve tutors’ name, who have more than experience others along with their students name . Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select t.name, s.name from tutor t join students s on t.id=s.tutorid where experience = (select max (experience) from tutor);
select t.name, s.name, max(experience) from tutor t join students s on t.id=s.tutorid;
select t.name, s.name from tutor t join students s on t.id=s.id where experience = (select max (experience) from tutor);

Explicação

Questão 48 de 89

1

Retrieve tutors’ name, who have less experience than others along with their students name. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select t.name, s.name from tutor t join students s on t.id=s.tutorid where experience = (select min (experience) from tutor);
select t.name, s.name, min(experience) from tutor t join students s on t.id=s.tutorid;
select t.name, s.name from tutor t join students s on t.id=s.id where experience = (select min (experience) from tutor);

Explicação

Questão 49 de 89

1

Increase tutors experience and students’ scholarship twice. Retrieve experience and scholarship along with their names. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join students s on t.id=s.tutorid;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join students s on t.id=s.id;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join tutor s on t.id=s.tutorid;
select t.name,t.experience*2, s.name, s.scholarship*2 from tutor t join tutor s on t.id=s.id;

Explicação

Questão 50 de 89

1

Retrieve office, tutor and students name, but tutors name should have y value. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o o.id=t.officeid join students st on t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st t.id=st.tutorid where t.name like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.id where t.name like '%y%';

Explicação

Questão 51 de 89

1

Retrieve office, tutor and students name, but tutors name should not have y value. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutored (FK references tutor (id))}.

Selecione uma das seguintes:

select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o o.id=t.officeid join students st on t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st t.id=st.tutorid where t.name not like '%y%';
select o.name, t.name, st.name from tutor t join office o on o.id=t.officeid join students st on t.id=st.id where t.name not like '%y%';

Explicação

Questão 52 de 89

1

Retrieve students name and scholarship along with their department name, who have scholarship between 4000 and 5000. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select s.name, s.scholarship, o.name from office o join tutor t on o.id=t.officeid join students s on t.id=s.tutorid where s.scholarship between 4000 and 5000;
select s.name, s.scholarship, o.name from office o join tutor t on o.id=t.officeid join students s on t.id=s.tutorid where s.scholarship 4000 and 5000;
select s.name, s.scholarship, o.name from tutor t join students s on t.id=s.tutorid where s.scholarship between 4000 and 5000;
select s.name, s.scholarship, o.name from tutor t join students s on t.id=s.tutorid where s.scholarship >=4000

Explicação

Questão 53 de 89

1

Retrieve information about office and their tutors as well. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.d

Selecione uma das seguintes:

select *from office o join tutor t on o.id=t.officeid;
select *from office o join tutor t in o.id=t.officeid;
select *form office o join tutor t on o.id=t.officeid;
select *from office o join tutor t on o.id=t.id;

Explicação

Questão 54 de 89

1

Retrieve office name and tutor name, which have maximum experienced tutors. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select max (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select min (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select high (experience) from tutor);
select o.name, t.name from office o join tutor t on o.id=t.officeid where t.experience = (select low (experience) from tutor);

Explicação

Questão 55 de 89

1

Retrieve all tutors and students names. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select t.name, s.name from tutor t full join students s on t.id=s.tutorid;
select t.name, s.name from tutor t full join students s t.id=s.tutorid;
select t.name, s.name from tutor t full join students s t.id=s.id;
select t.name, s.name from tutor t full join students s on t.id=s.id;

Explicação

Questão 56 de 89

1

Retrieve tutors’ name and the number of students for each of them. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.tutoridgroup by t.name;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.tutorid;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.idgroup by t.name;
select count (s.name) as numberofstudents, t.name from tutor t join students s on t.id=s.id;

Explicação

Questão 57 de 89

1

Retrieve office name and the number of students for each of them. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))}.

Selecione uma das seguintes:

select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.tutoridjoin office o on o.id=t.officeid group by o.name;
select count (s.name) as numberofstudents, o.name from students s on join office o on o.id=s.id group by o.name;
select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.tutoridjoin office o o.id=t.officeid group by o.name;
select count (s.name) as numberofstudents, o.name from tutor t join students s on t.id=s.idjoin office o on o.id=t.id group by o.name;

Explicação

Questão 58 de 89

1

Retrieve all students’ name and scholarship, tutors name except students who have scholarship 3000$. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship <> 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship = 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship < 3000;
select s.name, t.name from students s join tutor t on s.tutorid=t.id where s.scholarship is 3000;

Explicação

Questão 59 de 89

1

How many types of anomalies exist?

Selecione uma das seguintes:

1
2
3
4

Explicação

Questão 60 de 89

1

Which of the following anomaly does not exist?

Selecione uma das seguintes:

Creation anomaly
Deletion anomaly
Insertion anomaly
Modification anomaly

Explicação

Questão 61 de 89

1

When an insertion anomaly occurs?

Selecione uma das seguintes:

we are prevented from inserting some data into a relation until other data can be supplied
deletion leads to an unintended loss of data
it is possible that not all data needs to be changed will always be changed
it does not occur

Explicação

Questão 62 de 89

1

When a modification anomaly occurs?

Selecione uma das seguintes:

it is possible that not all data needs to be changed will always be changed
we are prevented from inserting some data into a relation until other data can be supplied
deletion leads to an unintended loss of data
it does not occur

Explicação

Questão 63 de 89

1

When a deletion anomaly occurs?

Selecione uma das seguintes:

deletion leads to an unintended loss of data
it is possible that not all data needs to be changed will always be changed
we are prevented from inserting some data into a relation until other data can be supplied
it does not occur

Explicação

Questão 64 de 89

1

Define inner join

Selecione uma das seguintes:

selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1), with the matching rows in the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1) and from the right table (2)

Explicação

Questão 65 de 89

1

Define left join

Selecione uma das seguintes:

returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1) and from the right table (2)

Explicação

Questão 66 de 89

1

Define right join

Selecione uma das seguintes:

returns all rows from the right table (2), with the matching rows in the left table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1) and from the right table (2)

Explicação

Questão 67 de 89

1

Define full join

Selecione uma das seguintes:

returns all rows from the left table (1) and from the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)
selects all rows from both tables as long as there is a match between the columns in both tables

Explicação

Questão 68 de 89

1

Define an union

Selecione uma das seguintes:

сombines the result set of two or more select statements
returns all rows from the left table (1) and from the right table (2)
returns all rows from the right table (2), with the matching rows in the right table (1)
returns all rows from the left table (1), with the matching rows in the right table (2)

Explicação

Questão 69 de 89

1

INNER JOIN and JOIN are the same

Selecione uma das opções:

VERDADEIRO
FALSO

Explicação

Questão 70 de 89

1

Define self join

Selecione uma das seguintes:

returns all rows from the table that references to yourself
returns all rows from the right table (2), with the matching rows in the right table (1)
selects all rows from both tables as long as there is a match between the columns in both tables
returns all rows from the left table (1) and from the right table (2)

Explicação

Questão 71 de 89

1

How many types of functional dependencies exist

Selecione uma das seguintes:

1
2
3
0

Explicação

Questão 72 de 89

1

Which of the following does not to the functional dependency

Selecione uma das seguintes:

equational
full
transitive
partial

Explicação

Questão 73 de 89

1

Which of the following represent a full dependency?

Selecione uma das seguintes:

it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
x->y dependency in relation R and x, y , z are columns in R. X->Y and Y>Z in R. Final: X->Y
all above mentioned

Explicação

Questão 74 de 89

1

Which of the following represent a partial dependency?

Selecione uma das seguintes:

if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
x->y dependency in relation R and x, y , z are columns in R. X->Y and Y>Z in R. Final: X->Y
all above mentioned

Explicação

Questão 75 de 89

1

Which of the following represent a transitive dependency?

Selecione uma das seguintes:

x->y dependency in relation R and x, y , z are columns in R. X->Y and Y->Z in R. Final: X->Y
if there exists an attribute A that is part of X that can be removed from X and the dependency still holds
it exists in relation if there is no attribute A that can be removed from X and the dependency still holds
all above mentioned

Explicação

Questão 76 de 89

1

When was first normalization developed?

Selecione uma das seguintes:

1970
1972
1973
1974

Explicação

Questão 77 de 89

1

When was second normalization developed?

Selecione uma das seguintes:

1971
1972
1973
1974

Explicação

Questão 78 de 89

1

When was Boyce–Codd normalization developed?

Selecione uma das seguintes:

1974
1972
1973
1971

Explicação

Questão 79 de 89

1

Who is an inventor of relational model?

Selecione uma das seguintes:

Edgar F.Codd
Raymond Boyce
Marine Jone
John Salamondor

Explicação

Questão 80 de 89

1

Which of the following refers to the requirement of 1NF

Selecione uma das seguintes:

Each cell should be single valued
Entries in a column are same type
Rows uniquely identified
All above mentioned

Explicação

Questão 81 de 89

1

Which of the following refers to the requirement of 2NF

Selecione uma das seguintes:

All attributes (non-key columns) dependent on the key
Each cell should be single valued
All fields (columns) can be determined only by the key in the table and no other column
All above mentioned

Explicação

Questão 82 de 89

1

Which of the following refers to the requirement of 3NF

Selecione uma das seguintes:

All fields (columns) can be determined only by the key in the table and no other column
All attributes (non-key columns) dependent on the key
Each cell should be single valued
All above mentioned

Explicação

Questão 83 de 89

1

Define avg function

Selecione uma das seguintes:

Returns average value
Returns total value
Returns the first value
Converts to lowercase

Explicação

Questão 84 de 89

1

Which function is used to retrieve quantity of rows

Selecione uma das seguintes:

count
sum
max
avg

Explicação

Questão 85 de 89

1

Retrieve avg scholarship of students. Tables: office {id (PK), locations, name}, tutor {id (PK), name, officeid (FK references office (id)), experience}, students {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select avg (scholarship) from students;
select aveg (scholarship) from students;
select avr (scholarship) from students;
select avgr (scholarship) from students;

Explicação

Questão 86 de 89

1

Retrieve students’, scholarship and teacher's’ name, who have more than average scholarship. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select s.name, s.scholarship, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> (select avg(scholarship) from students)
select s.name, s.scholarship, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> avg(scholarship)
select s.name, s.scholarship, t.name from students s, tutor t where s.scholarship> (select avg(scholarship) from students)
select s.name, avg(s.scholarship), t.name from students s, tutor t

Explicação

Questão 87 de 89

1

Retrieve students’, scholarship and teacher's’ name, who have more than average scholarship AND increase those students twice. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select s.name, s.scholarship*2, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> (select avg(scholarship) from students)
select s.name, s.scholarship*2, t.name from students s, tutor t where t.id=s.tutorid and s.scholarship> avg(scholarship)
select s.name, s.scholarship*2, t.name from students s, tutor t where s.scholarship> (select avg(scholarship) from students)
select s.name, avg(s.scholarship)*2, t.name from students s, tutor t

Explicação

Questão 88 de 89

1

Retrieve students and mentors name, but mentors registration date should be before students registration date. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select s.name, m.name from students s join students m on s.tutorid=m.tutorid where s.registereddate<m.registereddate;
select s.name, m.name from students s join students m on s.tutorid=m.tutorid where s.registereddate>m.registereddate;
select s.name, m.name from students s join students m on s.tutorid=m.tutorid;
select s.name, m.name from students s join students m on s.registereddate=m.registereddate;

Explicação

Questão 89 de 89

1

Retrieve the highest experience from tutor. Tables: OFFICE {id (PK), locations, name}, TUTOR {id (PK), name, officeid (FK references office (id)), experience}, STUDENTS {id (PK), name, scholarship, registereddate, tutorid (FK references tutor (id))

Selecione uma das seguintes:

select max (experience) from tutor;
select min (experience) from tutor;
select max (t.experience) from tutor t group by t.name;
select min (t.experience) from tutor t group by t.name;

	Criado por хомяк убийца aproximadamente 5 anos atrás

God Philosophy Quiz sobre ГОС по БД #1, criado por хомяк убийца em 23-03-2019.

ГОС по БД #1

Questão 1 de 89

Define a degree of a relation

Selecione uma das seguintes:

Explicação

Questão 2 de 89

Define a cardinality of a relation

Selecione uma das seguintes:

Explicação

Questão 3 de 89

Which of the following refers to union-compatibility requirements ?

Selecione uma das seguintes:

Explicação

Questão 4 de 89

Which of the following refers to union-compatibility requirements ?

Selecione uma das seguintes:

Explicação

Questão 5 de 89

Define a domain

Selecione uma das seguintes:

Explicação

Questão 6 de 89

Define a foreign key

Selecione uma das seguintes:

Explicação

Questão 7 de 89

Define a primary key

Selecione uma das seguintes:

Explicação

Questão 8 de 89

Define restrict

Selecione uma das seguintes:

Explicação

Questão 9 de 89

Define cascade

Selecione uma das seguintes:

Explicação

Questão 10 de 89

Define set default

Selecione uma das seguintes:

Explicação

Questão 11 de 89

Define set null

Selecione uma das seguintes:

Explicação

Questão 12 de 89

Define Data Definition Language

Selecione uma das seguintes:

Explicação

Questão 13 de 89

Define Data Control Language

Selecione uma das seguintes:

Explicação

Questão 14 de 89

Define Data Manipulation Language

Selecione uma das seguintes:

Explicação

Questão 15 de 89

Which of the following does not refer to DBMS tools

Selecione uma das seguintes:

Explicação

Questão 16 de 89

Which of the following is used to provide privilege to only a particular attribute?

Selecione uma das seguintes:

Explicação

Questão 17 de 89

Which of the following statement is used to remove the privilege from the user finance?

Selecione uma das seguintes:

Explicação

Questão 18 de 89

Which of the following is true regarding views?

Selecione uma das seguintes:

Explicação

Questão 19 de 89

If we wish to grant a privilege and to allow the recipient to pass the privilege on to other users, we append the __________ clause to the appropriate grant command.

Selecione uma das seguintes:

Explicação

Questão 20 de 89

Which of the following is used to avoid cascading of authorizations from the user?