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Fragen in diesem Quiz (20)
1The term z with subscript((α/2))((σ/sqrt(n))) describes the underbar
- Amaximum error of estimate
- Bunbiased estimator
- Cinterval estimate
- D confidence interval
2A sample of size n = 20 is drawn from an approximately normal population whose standard deviation is σ = 5.5. The sample mean is overbar(x) = 52.4. Construct a 95% confidence interval for μ.
- A35.69 < μ < 69.11
- B49.99 < μ < 54.81
- C52.40 < μ < 54.81
- D51.37 < μ < 53.43
3An economics professor randomly selected 100 millionaires in the United States. The average age of these millionaires was 54.8 years. If the standard deviation of the entire population of millionaires is 7.9 years, find the 95% confidence interval for the mean age of all United States millionaires.
- A53.5 < μ < 56.1
- B52.8 < μ < 56.8
- C54.0 < μ < 55.6
- D53.3 < μ < 56.3
4A college admissions officer takes a simple random sample of 100 entering freshmen and computes their mean mathematics SAT score to be 459. Assume the population standard deviation is σ = 103.
Construct a 99% confidence interval for the mean mathematics SAT score for the entering freshmen class.- A434 < μ < 484
- B 356 < μ < 562
- C456 < μ < 462
- D432 < μ < 486
5What is the value of α used in describing the confidence interval shown below.
graphic(blueman_-B72861614)- A0.05
- B0.02
- C0.01
- D0.04
6Find t with subscript((α/2)) when n = 12 for the 95% confidence interval for the mean.
- A2.92
- B1.80
- C1.52
- D2.20
7A sample of size n = 11 has a sample mean overbar(x) = 15.6 and sample standard deviation s = 2.4. Construct a 95% confidence interval for the population mean μ.
- A14.3 < μ < 16.9
- B14.6 < μ < 16.6
- C14.0 < μ < 17.2
- D15.1 < μ < 16.1
8A sample of 125 tobacco smokers who recently completed a new smoking-cessation program were asked to rate the effectiveness of the program on a scale of 1 to 10, with 10 corresponding to "completely effective" and 1 corresponding to "completely ineffective". The average rating was 4.1 and the standard deviation was 4.0.
Construct a 95% confidence interval for the mean score.- A0 < μ < 4.1
- B3.7 < μ < 4.5
- C3.4 < μ < 4.8
- D3.8 < μ < 4.4
9 A sample of size n = 21 is drawn from a normal population. Find the critical value t with subscript((α/2)) needed to construct a 90% confidence interval.
- A1.325
- B1.645
- C1.725
- D1.721
10A food snack manufacturer samples 11 bags of pretzels off the assembly line and weighs their contents. If the sample mean is 15.2 oz. and the sample standard deviation is 0.50 oz., find the 95% confidence interval of the true mean.
- A15.0 < μ < 15.4
- B12.9 < μ < 17.5
- C14.9 < μ < 15.5
- D14.1 < μ < 16.3
11 In a study of 100 new cars, 29 are white. Find hat( p ) and hat(q), where hat( p ) is the proportion of new cars that are white.
- Ahat( p ) = 0.29, hat(q) = 0.29
- Bhat( p ) = 0.71, hat(q) = 0.29
- Chat( p ) = 0.71, hat(q) = 0.71
- Dhat( p ) = 0.29, hat(q) = 0.71
12Use the given data to construct a confidence interval of the requested level.
x = 98, n = 223, confidence level 99%- A0.406 < p < 0.473
- B0.362 < p < 0.517
- C0.354 < p < 0.525
- D0.219 < p < 0.660
13In a survey of 246 registered voters, 132 of them wished to see Mayor Waffleskate lose her next election. Find a point estimate for the proportion of registered voters who wish to see Mayor Waffleskate defeated.
- A132
- B0.537
- C0.032
- D0.463
14A recent study of 750 internet users in Europe found that 35% of internet users were women. What is the 95% confidence interval of the true proportion of women in Europe who use the internet?
- A0.309 < p < 0.391
- B0.321 < p < 0.379
- C0.349 < p < 0.351
- D0.316 < p < 0.384
15A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence interval for the true proportion of women shoppers who shop on impulse?
- A0.144 < p < 0.196
- B0.136 < p < 0.204
- C0.139 < p < 0.201
- D0.167 < p < 0.173
16What is the value for χ and ((2) over (right)) for a 98% confidence interval when n = 12?
- A21.920
- B27.688
- C24.725
- D26.217
17 Find the values for χ and ((2) over (left)) and χ and ((2) over (right)) when α = .05 and n = 27.
- A13.844 and 41.923
- B14.573 and 43.194
- C16.151 and 40.113
- D15.379 and 38.885
18What is the 90% confidence interval for the variance of exam scores for 28 algebra students, if the standard deviation of their last exam was 12.7?
- A10.4 < σ to power of ((2)) < 16.4
- B123.7 < σ to power of ((2)) < 312.7
- C108.6 < σ to power of ((2)) < 269.6
- D122.8 < σ to power of ((2)) < 316.5
19Scores on the math SAT are normally distributed. A sample of 28 SAT scores had a standard deviation s = 75. Construct a 99% confidence interval for the population standard deviation σ.
- A54.57 < σ < 110.40
- B56.87 < σ < 108.60
- C55.31 < σ < 113.41
- D55.58 < σ < 112.42
20For a random sample of 23 European countries, the variance on life expectancy was 7.3 years. What is the 95% confidence interval for the variance of life expectancy in all of Europe?
- A28.9 < σ to power of ((2)) < 115.0
- B27.2 < σ to power of ((2)) < 118.3
- C4.4 < σ to power of ((2)) < 14.6
- D5.6 < σ to power of ((2)) < 10.3
Informationen
- Beschreibung
- Quiz am Ohne Titel, erstellt von Jess Todd am 20/02/2015.
- Autor
- Jess Todd
- Sprache
- English
- Aufrufe
- 3
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