Karteikarten
Ohne Titel
Karten in diesem Stapel (3)
- 1Find the scalar product of a = 7i + 3j and b = 4i - 2ja.b = 7(4) + 3(-2)
a.b = 28 - 6
a.b = 22 - 2Find the cosine angle between a = 3i -2j and 4i + 3j/a/ = √(9+4)
/a/ = √10
/b/ = √(16+9 )
/b/ = √25
/b/ = 5
a.b = 3(4) -2(3)
a.b = 12 - 6
a.b = 6
cos θ = a.b
/a/./b/
cosθ =6/(√10 ×5)
cos θ = 6/5√10 - 3Find the projection of the vector a on the vector b if ; a = 2i + 3j and b = 4i - 2ja = 2i + 3j and b = 4i - 2j
/b/ = √(16+4) = √20
let k be the projection of the vector a on b, then,
k = (2i + 3j) . 1/(√20)(4i - 2j)
Informationen
- Beschreibung
- Karteikarten am Ohne Titel, erstellt von Salisu Wale am 12/09/2014.
- Erstellt von
- Salisu Wale
- Aufrufe
- 5
- Bewertung