Karteikarten
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Karten in diesem Stapel (8)
- 1TTHERE IS AN ELECTRIC FIELD AROUND A CHARGED OBJECT
- 2AANY OBJECT WITH CHARGE HAS AN ELECTRIC FIELD AROUND IT -- THE REGION WHERE IT CAN ATTRACT OR REPEL OTHER CHARGES
- 3FEE1. ELECTRIC CHARGE Q IS MEASURED IN COULOMBS AND CAN EITHER BE POSITIVE OR NEGATIVE
- 4FO2. OPPOSITELY CHARGED PARTICLES ATTRACT EACH OTHER, LIKE CHARGES REPEL
- 5FI3. IF A CHARGED OBJECT IS PLACED IN AN ELECTRIC FIELD IT WILL EXPERIENCE A FORCE
- 6COULOMB'S LAWCOULOMB'S LAW STATES THAT THE FORCE BETWEEN TWO ELECTRICALLY CHARGED BODIES WHICH ARE SMALL COMPARED WITH THEIR SEPARATION IS INVERSELY PROPORTIONAL TO THE SQUARE OF THEIR SEPARATION AND PROPORTIONAL TO THE PRODUCT OF THEIR CHARGES
- 7COULOMB'S EQUATIONTHE EQUATION USED TO CALCULATE THE FORCE IN COULOMB'S LAW IS:
F = (Q_1*Q_2)/(4*\pi*e_0*r^2)
where e_0 is called the permitivitty of free space/vacuum and is measured in Fm^{-1} (Farad meter).
Q_1,Q_2 are the two charges in question. If they are alike then F is positive, otherwise it is negative. The charges are measured in C for Coulomb.
r is the separation of the charges in m, meters. - 8PERMITIVITTYSO AS WE SAW, THE FORCE BETWEEN CHARGES DEPENDS ON E, THE PERMITIVITTY OF THE MEDIUM THEY ARE SITUATED IN. IN A VACUUM THIS IS DENOTED E_0 AND CAN BE SHOWN BY EXPERIMENT TO BE 8.854*10^{-12} FM^{-1}.
ON THE OTHER HAND, THE PERMITIVITTY OF AIR IS 1.0005*E_0 AND THUS FOR MOST PRACTICAL PURPOSES WE MAY ASSUME E_AIR=E_0.
BUT E_WATER IS A WHOPPING 80*E_0 AND THUS THE FORCE BETWEEN TWO CHARGED PARTICLES SITUATED IN WATER IS 80 TIMES LESS THAN IF THEY WERE IN AIR OR A VACUUM. THIS IS WHY SALT DISSOLVES IN WATER: THE FORCES BETWEEN THE ELECTRONS IN THE SALT PARTICLES IS REDUCED AND THEY FLOAT AWAY FROM EACH OTHER.
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- Karteikarten am Ohne Titel, erstellt von John Perpendicular am 01/05/2015.
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