GoConqr hat ein neues Design! Sag uns, wie es dir gefällt.

Karteikarten

PH10053 - Sergey's Theory

Noah Bryan Englisch 5,0Durchschnittliche Bewertung 5,0 von 5 (1 Bewertung) 18 Karten

Karten in diesem Stapel (18)

  1. 1Define Periodic MotionMotion of an object that regularly repeats - An the object returns to given position after a fixed time interval - A feature of Simple Harmonic Motion
  2. 2Name the Force that acts to reduce displacement of an object and return the system to equilibrium.Restoring Force
  3. 3SHM occurs when...The Restoring Force is linearly proportional to the displacement from from equilibrium and opposite to the direction of the displacement.
  4. 4A general rule for SHM is:Restoring Force=-k(x)
  5. 5Name two assumptions:1) No Friction
    2) Mass of spring is negligibly small in comparison to the mass of the block.
  6. 6When an object is displaced, the spring exerts a ...... ...... equal to ....Restoring Force ; (-kx) where k is the force constant.
  7. 7What's the differential equation for simple harmonic motion? What's its general solution?(d^2x/dt^2)+(w^2)x=0
    x=Acos(wt+d)
  8. 8Quantities: Period (T) Frequency (f) Angular Frequency (w)Equations and Units: Period (s)
    Frequency --> f=1/T (Hz)
    Angular Frequency --> w=2πf (rad/s)
  9. 9Differentiating the general solution: x=Acos(wt+d) gives: v=... and a=...v=-Awsin(wt+d)
    a=-A(w^2)cos(wt+d) = -(w^2)x
  10. 10Phase difference of Velocity and Displacementπ/2
  11. 11Velocity is maximum when...Displacement is 0 (Eqm position)
  12. 12Velocity is 0 when...Displacement is maximum (Amplitude of oscillation)
  13. 13The frequency and period are related to the stiffness (k) of the spring and the particle mass; where w= sqrt(k/m)f=w/2π=(sqrt(k/m))/2π
    T=1/f= 2π(sqrt(m/k))
  14. 14When is the spring constant not constant?When oscillations are large
  15. 15What's the equation for the vertical displacement in equilibrium when a mass is attached to a spring?y.=mg/k
  16. 16y' for vertical oscillations is the...Amplitude of oscillations about the equilibrium position of the system when the mass is attached.
    Where y'=y-y., where y is the total amplitude from the eqm position without the mass attached
  17. 17Eqm Position: y.=mg/k Hence, mg-ky.=0 Write the equation for vertical oscillations:mg-ky.=ma
    by Newton's (II) Law
    This translates to:
    m((d^2)y/d(t^2))+ky.=mg
    (x(1/m)) --> ((d^2)y/d(t^2))+ (k/m)y.=g;
    where (k/m) = w
  18. 18—

Informationen

Beschreibung
Simple Harmonic Motion- Damped Oscillations - Harmonics
Erstellt von
Noah Bryan · Okt 2017
Aktualisiert
30 Okt 2017
Aufrufe
9
Bewertung
Durchschnittliche Bewertung 5,0 von 5 (1 Bewertung)

Feedback

Worum geht es?

Wie gefällt dir das neue Design?

Dein Eindruck