Mindmap
Eigenvalues & Eigenvectors

Inhalt der Mindmap
Eigenvalues & Eigenvectors
Concepts
- Eigenvalues are also called proper values, characteristic values, latent values
- Eigenvector cannot be 0, but eigenvalue possible to be 0
Eigenspaces
- if A is an n x n matrix with an eigenvalue and corresponding eigenvectors, then every nonzero scalar multiple of eigenvector is also an eigenvector of A
- Also true that if eigenvectors are corresponding to the same eigenvalues, then their sum is also an eigenvector corresponding to eigenvalue
- Set of all eigenvectors of a given eigenvalues, zero vectors, is the subspace of which is called the eigenspace of eigenvalue (lambda)
- if A is an n x n matrix with an eigenvalue and corresponding eigenvectors, then every nonzero scalar multiple of eigenvector is also an eigenvector of A
Finding Eigenvalues & Eigenvectors
- Has nonzero solutions iff the coefficient matrix is not invertible ; det = 0
- Let A be n x n matrix A
- An eigenvalue of A is scalar lambda
- characteristic equation of A
- expanded ; characteristic polynomial of A
- Eigenvectors of A corresponding to lambda are nonzero solutions of :
- An eigenvalue of A is scalar lambda
- The determinant
- Characteristic polynomial of A
- characteristic equation of A
- Matrix A is singular iff lambda = 0 is an eigenvalue of A
- The eigenvalues of A =[aij] are the roots of the characteristic polynomial of A
- The eigenvalues problem in general case
- since is nonzero, then it has a nontrivial solution if
- The null space of is called the eigenspace of A corresponding to the eigenvalue lambda
Method to Obtain the Bases of Eigenspace A
- Step 1 : FInd all eigenvalues of A
- Step 2 : Find a basis for null space by solving the homogeneous system
- Step 1 : FInd all eigenvalues of A
Finding Eigenvalues of A^k
- Let lambda be an eigenvalue of A and x bar the corresponding eigenvector
- Which means that lambda^3 is an eigenvalue of A^3 and x bar is the corresponding vector
- A square matrix A is invertible iff lambda = 0 is not an eigenvalue of A
- Assume that A is a square matrix with eigenvalues
- Let lambda be an eigenvalue of A and x bar the corresponding eigenvector
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- Mindmap am Eigenvalues & Eigenvectors, erstellt von SITI NUR SYAFIQAH NORDIN am 24/07/2021.
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- SITI NUR SYAFIQAH NORDIN
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