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Quiz

Standing Waves

Sally Lancaster 18 Fragen

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  1. 1Nodes:Bild zu Frage 1
    1. AZero amplitude
    2. BPoints of (total) destructive interference
    3. COccur at fixed ends
    4. DAmplitude zero => String not moving => No energy absorbed => Pattern not disturbed if touched
    5. EPoints of constructive interference
    6. FMaximum (positive/negative) amplitude
    7. GOccur at free ends
  2. 2Antinodes:Bild zu Frage 2
    1. AZero amplitude
    2. BPoints of (total) destructive interference
    3. COccur at fixed ends
    4. DMaximum (positive/negative) amplitude
    5. EPoints of constructive interference
    6. FOccur at free ends
  3. 3Speed of Standing/Stationary Waves:
    - [blank_start]Node to node[blank_end] or [blank_start]antinode to antinode[blank_end] is equal to [blank_start]1/2 λ[blank_end].
    - To calculate speed use [blank_start]v = fλ[blank_end] where [blank_start]λ[blank_end] is [blank_start]2 x[blank_end] the [blank_start]distance[blank_end] from node to node or antinode to antinode.
    Bild zu Frage 3
    1. ANode to node
    2. Bantinode to antinode
    3. C1/2 λ
    4. Dλ
    5. E2 x
    6. Fv = fλ
    7. Gdistance
  4. 4Coherence:
    - Coherent = [blank_start]constant[blank_end] [blank_start]phase[blank_end] [blank_start]relationship[blank_end].
    - Therefore, if the relationship isn't constant (i.e. source not [blank_start]coherent[blank_end]) then [blank_start]interference[blank_end] varies - a point could sometimes be [blank_start]constructive[blank_end] and sometimes be [blank_start]destructive[blank_end].
    Bild zu Frage 4
    1. Aconstant
    2. Bphase
    3. Crelationship
    4. Dcoherent
    5. Einterference
    6. Fconstructive
    7. Gdestructive
  5. 5Phase Difference:
    - Antiphase = [blank_start]180°/π radians[blank_end] out of phase with another wave.
    - In phase = [blank_start]0/360°/2π radians[blank_end] phase difference.
    Both waves need to have the same [blank_start]frequency[blank_end] to see [blank_start]interference[blank_end] (constructive and destructive) and for waves to be [blank_start]in phase or in antiphase[blank_end].
    Bild zu Frage 5
    1. A0/360°/2π radians
    2. B180°/π radians
    3. C180°/π radians
    4. D0/360°/2π radians
    5. Efrequency
    6. Fphase difference
    7. Ginterference
    8. Hwaves
    9. Iin phase or in antiphase
    10. Jcoherent
  6. 6To produce a standing wave you need (for the 2 waves):
    1. Same f[blank_start]requency[blank_end].
    2. Same a[blank_start]mplitude[blank_end].
    3. Same m[blank_start]edium[blank_end].
    4. Waves travelling in [blank_start]opposite[blank_end] directions.
    Bild zu Frage 6
    1. Arequency
    2. Bmplitude
    3. Cedium
    4. Dopposite
  7. 7Increasing Frequency of a Standing Wave:
    - As frequency increases, wavelength [blank_start]decreases[blank_end].
    - At [blank_start]most[blank_end] frequencies there is [blank_start]no standing wave[blank_end].
    - The [blank_start]higher[blank_end] the frequency, the more [blank_start]nodes and antinodes[blank_end] of the standing wave.
    - [blank_start]Amplitude[blank_end] decreases as number of nodes [blank_start]increases[blank_end].
    Bild zu Frage 7
    1. Ano standing wave
    2. Bmost
    3. Cnodes and antinodes
    4. Dhigher
    5. Edecreases
    6. Fincreases
    7. GAmplitude
  8. 8What are the lengths of the harmonics?Bild zu Frage 8
    1. AL = 1/2 λ
    2. BL = λ
    3. CL = 3/2 λ
    4. DL = 2 λ
  9. 9Open and Closed Pipes:
    E.g. for the fundamental frequency/first harmonic.
    - You need an [blank_start]antinode[blank_end] at the [blank_start]open[blank_end] end to hear maximum amplitude.
    - The closed end is a [blank_start]fixed[blank_end] end so it will be a [blank_start]node[blank_end].
    - Going from open to closed the frequency h[blank_start]alves[blank_end] because the [blank_start]closed[blank_end] end becomes a node making the length go from [blank_start]1/2[blank_end] λ to 1/4 λ (fundamental frequency only).
    In general, the other [blank_start]harmonics[blank_end] can be formed from the various overtones by using open and closed pipes. You can calculate the f[blank_start]requency[blank_end] and w[blank_start]avelength[blank_end] of each overtone in each type of pipe.
    Bild zu Frage 9
    1. Aantinode
    2. Bopen
    3. Cfixed
    4. Dnode
    5. Eclosed
    6. F1/2
    7. Gharmonics
    8. Hrequency
    9. Iavelength
    10. Jalves
  10. 10Strobe Lamp:
    - A strobe lamp needs to [blank_start]capture[blank_end] the string [blank_start]twice[blank_end] per [blank_start]cycle[blank_end] in order to see the [blank_start]2[blank_end] positions of the standing wave (at maximum and minimum [blank_start]amplitude[blank_end] preferably).
    - Therefore maximum frequency of the strobe lamp must be [blank_start]2[blank_end] x f[blank_start]requency[blank_end] of vibration generator.
    - There is a maximum because any higher frequency will [blank_start]capture[blank_end] the string at points [blank_start]other[blank_end] [blank_start]than[blank_end] the maximum amplitude.
    Bild zu Frage 10
    1. Atwice
    2. Bcapture
    3. Ccycle
    4. D2
    5. Eamplitude
    6. F2
    7. Gother
    8. Hthan
    9. Icapture
    10. Jrequency

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Beschreibung
AS - Level Sally's Physics (Waves and Particle Nature of Light) Quiz am Standing Waves, erstellt von Sally Lancaster am 11/03/2016.
Sprache
English
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