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Quiz

Lenses

Sally Lancaster 18 Fragen

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  1. 1Converging Lenses:
    - Converging lenses bulge [blank_start]outwards[blank_end].
    - Rays parallel to the principle axis of the lens converge onto a point called the [blank_start]principal[blank_end] [blank_start]focus[blank_end].
    - [blank_start]Parallel[blank_end] rays that aren't parallel to the principle axis converge somewhere else on the [blank_start]focal[blank_end] p[blank_start]lane[blank_end].
    - The [blank_start]focal[blank_end] [blank_start]length[blank_end], f, is the distance between the lens [blank_start]axis[blank_end] and the focal [blank_start]plane[blank_end].
    - f is p[blank_start]ositive[blank_end] for a converging lens because it is [blank_start]in[blank_end] [blank_start]front[blank_end] of the lens.
    Bild zu Frage 1
    1. Aoutwards
    2. Bprincipal
    3. Cfocus
    4. DParallel
    5. Efocal
    6. Ffocal
    7. Glength
    8. Haxis
    9. Iplane
    10. Jositive
    11. Kin
    12. Lfront
    13. Mlane
  2. 2Lenses change the direction of light rays by [blank_start]refraction[blank_end].Bild zu Frage 2
    1. Arefraction
  3. 3Diverging Lenses:
    - Diverging lenses cave [blank_start]inwards[blank_end].
    - The principal focus of a diverging lens is at a point [blank_start]behind[blank_end] the lens.
    - The principal focus is the point that rays from a [blank_start]distant[blank_end] object, assumed to be [blank_start]parallel[blank_end] to the principal axis, appear to have [blank_start]come[blank_end] from.
    - The dotted lines in the diagram show [blank_start]virtual[blank_end] rays. The light doesn't actually follow this path, but [blank_start]appears[blank_end] to have done so.
    - The focal length, f, is the distance between the [blank_start]lens[blank_end] axis and the [blank_start]principal[blank_end] focus.
    - f is n[blank_start]egative[blank_end] for a diverging lens because it is [blank_start]behind[blank_end] the lens.
    Bild zu Frage 3
    1. Ainwards
    2. Bbehind
    3. Cdistant
    4. Dparallel
    5. Ecome
    6. Fvirtual
    7. Gappears
    8. Hlens
    9. Iprincipal
    10. Jegative
    11. Kbehind
  4. 4Real and Virtual Images:
    - A [blank_start]real image[blank_end] is formed when light rays from a point on an object are made to pass through [blank_start]another[blank_end] point in space. The light rays are [blank_start]actually[blank_end] there, and the image [blank_start]can[blank_end] be captured on a [blank_start]screen[blank_end].
    - A virtual image is formed when light rays from a point on an object [blank_start]appear[blank_end] to have come from another point in space. The light rays [blank_start]aren't really[blank_end] where the image appears to be, so the image [blank_start]can't[blank_end] be captured on a screen.
    - Converging lenses can form [blank_start]both real and virtual[blank_end] images, depending on [blank_start]where[blank_end] the object is. If the object is further than the focal length away from the lens, the image is [blank_start]real[blank_end]. If the object's closer, the image is [blank_start]virtual[blank_end].
    - A diverging lens will always form a [blank_start]virtual image[blank_end] - the position of the object in relation to the focal length will [blank_start]not[blank_end] affect the [blank_start]type[blank_end] of image formed.
    Bild zu Frage 4
    1. Atype
    2. Banother
    3. Cactually
    4. Dcan
    5. Escreen
    6. Fcan't
    7. Gboth real and virtual
    8. Hwhere
    9. Ireal
    10. Jvirtual
    11. Kreal image
    12. Lvirtual image
    13. Mnot
    14. Nappear
    15. Oaren't really
  5. 5Ray Diagrams - Converging Lenses:
    Ray diagrams show where an [blank_start]image[blank_end] will be formed. If an object sits on the principal axis, [blank_start]so will[blank_end] the image.
    - Draw 3 rays from the [blank_start]same point[blank_end] on the object (usually the [blank_start]top[blank_end]): one [blank_start]parallel[blank_end] to the [blank_start]principal axis[blank_end] which passes through the [blank_start]principal focus[blank_end]; one passing through the [blank_start]optical centre[blank_end] so it doesn't get [blank_start]refracted[blank_end]; and one parallel to the principal axis which goes through the principal focus on the [blank_start]other side[blank_end] of the lens (this is a [blank_start]check ray[blank_end]).
    - The image will form where the 3 rays [blank_start]meet[blank_end] if the image is [blank_start]real[blank_end].
    - If the rays don't meet, the image is [blank_start]virtual[blank_end]. Extend the rays back (draw virtual rays with [blank_start]dotted[blank_end] lines) to locate where the rays [blank_start]appear[blank_end] to have come from and hence locate the virtual image.
    Bild zu Frage 5
    1. Aimage
    2. Bsame point
    3. Ctop
    4. Dso will
    5. Eparallel
    6. Fprincipal axis
    7. Gprincipal focus
    8. Hoptical centre
    9. Irefracted
    10. Jother side
    11. Kcheck ray
    12. Lmeet
    13. Mreal
    14. Nvirtual
    15. Odotted
    16. Pappear
  6. 6Ray Diagrams - Converging Lens:
    Converging lenses are represented by two arrows pointing outwards.
    Bild zu Frage 6
    1. AConverging lens
    2. BObject
    3. CImage
    4. Du
    5. Ev
    6. FPrincipal focus
    7. Gf
    8. HOptical centre
    9. ILight rays
  7. 7Ray Diagrams - Diverging Lenses:
    - Draw 3 rays from the [blank_start]same point[blank_end] on the object (usually the [blank_start]top[blank_end]): one [blank_start]parallel[blank_end] to the [blank_start]principal axis[blank_end] which refracts at the [blank_start]centre[blank_end] of the lens so that it appears to come from the [blank_start]principal focus[blank_end]; one through the [blank_start]optical centre[blank_end] without getting [blank_start]refracted[blank_end]; and one parallel to the principal axis on the [blank_start]other side[blank_end] which passes through the [blank_start]other[blank_end] principal focus.
    - Use [blank_start]dotted[blank_end] lines/virtual rays for refracted rays you have [blank_start]extended[blank_end].
    - The image will form where the real and virtual rays [blank_start]meet[blank_end] (this will be on the [blank_start]same side[blank_end] of the lens as the object).
    Bild zu Frage 7
    1. Asame point
    2. Btop
    3. Cparallel
    4. Dprincipal axis
    5. Ecentre
    6. Fprincipal focus
    7. Goptical centre
    8. Hrefracted
    9. Iother side
    10. Jother
    11. Kdotted
    12. Lextended
    13. Mmeet
    14. Nsame side
  8. 8Diverging Lens Ray Diagram:
    Diverging lenses are represented by arrows pointing inwards.
    Bild zu Frage 8
    1. ADiverging lens
    2. BObject
    3. CImage
    4. Dv
    5. Eu
    6. FPrincipal focus
    7. GLight rays
    8. Hf
  9. 9Ray Diagrams:
    f = [blank_start]focal[blank_end] length = distance between lens [blank_start]axis[blank_end] and principal [blank_start]focus[blank_end]. Positive for [blank_start]converging[blank_end] lenses and negative for [blank_start]diverging[blank_end] lenses.
    u = distance between [blank_start]object[blank_end] and lens axis.
    v = distance between [blank_start]image[blank_end] and lens axis. Positive for [blank_start]real[blank_end] images and negative for [blank_start]virtual[blank_end] images.
    Bild zu Frage 9
    1. Afocal
    2. Bobject
    3. Cimage
    4. Dreal
    5. Evirtual
    6. Fconverging
    7. Gdiverging
    8. Haxis
    9. Ifocus
  10. 10The Lens Equation:Bild zu Frage 10
    1. A1/f = 1/u + 1/v
    2. B1/f = 1/u - 1/v
    3. COnly works for thin lenses
    4. DOnly works for thick lenses
    5. EPlotting 1/v against 1/u will produce a straight line graph. If you apply the lens equation to y = mx + c you will find that the intercepts on the graph are represented by 1/f.
    6. FPlotting 1/v against 1/u will produce a straight line graph. If you apply the lens equation to y = mx + c you will find that the gradient of the line is represented by 1/f.

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Beschreibung
AS - Level Sally's Physics (Waves and Particle Nature of Light) Quiz am Lenses, erstellt von Sally Lancaster am 20/04/2016.
Sprache
English
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