16471532
Beschreibung
Karteikarten von Yara Habash, aktualisiert more than 1 year ago
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Erstellt von Yara Habash
vor fast 7 Jahre
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| Frage | Antworten |
| lowest value and highest value as its variance among the distributions | Bernoulli has variance = p(1-p) = 4%*96 = 0.0384 Binomial has variance = p(1-p)n = 2%*98%*50 = 0.980 Standard normal has, by definition, mean = 0 and variance = 1.0 Student's t has variance = df/(df-2) = 10/8 = 1.25 Poisson has lambda = variance = mean = 5 |
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