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Standing Waves

Sally Lancaster 18 preguntas

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Preguntas del test (18)

  1. 1Nodes:Imagen de la pregunta 1
    1. AZero amplitude
    2. BPoints of (total) destructive interference
    3. COccur at fixed ends
    4. DAmplitude zero => String not moving => No energy absorbed => Pattern not disturbed if touched
    5. EPoints of constructive interference
    6. FMaximum (positive/negative) amplitude
    7. GOccur at free ends
  2. 2Antinodes:Imagen de la pregunta 2
    1. AZero amplitude
    2. BPoints of (total) destructive interference
    3. COccur at fixed ends
    4. DMaximum (positive/negative) amplitude
    5. EPoints of constructive interference
    6. FOccur at free ends
  3. 3Speed of Standing/Stationary Waves:
    - [blank_start]Node to node[blank_end] or [blank_start]antinode to antinode[blank_end] is equal to [blank_start]1/2 λ[blank_end].
    - To calculate speed use [blank_start]v = fλ[blank_end] where [blank_start]λ[blank_end] is [blank_start]2 x[blank_end] the [blank_start]distance[blank_end] from node to node or antinode to antinode.
    Imagen de la pregunta 3
    1. ANode to node
    2. Bantinode to antinode
    3. C1/2 λ
    4. Dλ
    5. E2 x
    6. Fv = fλ
    7. Gdistance
  4. 4Coherence:
    - Coherent = [blank_start]constant[blank_end] [blank_start]phase[blank_end] [blank_start]relationship[blank_end].
    - Therefore, if the relationship isn't constant (i.e. source not [blank_start]coherent[blank_end]) then [blank_start]interference[blank_end] varies - a point could sometimes be [blank_start]constructive[blank_end] and sometimes be [blank_start]destructive[blank_end].
    Imagen de la pregunta 4
    1. Aconstant
    2. Bphase
    3. Crelationship
    4. Dcoherent
    5. Einterference
    6. Fconstructive
    7. Gdestructive
  5. 5Phase Difference:
    - Antiphase = [blank_start]180°/π radians[blank_end] out of phase with another wave.
    - In phase = [blank_start]0/360°/2π radians[blank_end] phase difference.
    Both waves need to have the same [blank_start]frequency[blank_end] to see [blank_start]interference[blank_end] (constructive and destructive) and for waves to be [blank_start]in phase or in antiphase[blank_end].
    Imagen de la pregunta 5
    1. A0/360°/2π radians
    2. B180°/π radians
    3. C180°/π radians
    4. D0/360°/2π radians
    5. Efrequency
    6. Fphase difference
    7. Ginterference
    8. Hwaves
    9. Iin phase or in antiphase
    10. Jcoherent
  6. 6To produce a standing wave you need (for the 2 waves):
    1. Same f[blank_start]requency[blank_end].
    2. Same a[blank_start]mplitude[blank_end].
    3. Same m[blank_start]edium[blank_end].
    4. Waves travelling in [blank_start]opposite[blank_end] directions.
    Imagen de la pregunta 6
    1. Arequency
    2. Bmplitude
    3. Cedium
    4. Dopposite
  7. 7Increasing Frequency of a Standing Wave:
    - As frequency increases, wavelength [blank_start]decreases[blank_end].
    - At [blank_start]most[blank_end] frequencies there is [blank_start]no standing wave[blank_end].
    - The [blank_start]higher[blank_end] the frequency, the more [blank_start]nodes and antinodes[blank_end] of the standing wave.
    - [blank_start]Amplitude[blank_end] decreases as number of nodes [blank_start]increases[blank_end].
    Imagen de la pregunta 7
    1. Ano standing wave
    2. Bmost
    3. Cnodes and antinodes
    4. Dhigher
    5. Edecreases
    6. Fincreases
    7. GAmplitude
  8. 8What are the lengths of the harmonics?Imagen de la pregunta 8
    1. AL = 1/2 λ
    2. BL = λ
    3. CL = 3/2 λ
    4. DL = 2 λ
  9. 9Open and Closed Pipes:
    E.g. for the fundamental frequency/first harmonic.
    - You need an [blank_start]antinode[blank_end] at the [blank_start]open[blank_end] end to hear maximum amplitude.
    - The closed end is a [blank_start]fixed[blank_end] end so it will be a [blank_start]node[blank_end].
    - Going from open to closed the frequency h[blank_start]alves[blank_end] because the [blank_start]closed[blank_end] end becomes a node making the length go from [blank_start]1/2[blank_end] λ to 1/4 λ (fundamental frequency only).
    In general, the other [blank_start]harmonics[blank_end] can be formed from the various overtones by using open and closed pipes. You can calculate the f[blank_start]requency[blank_end] and w[blank_start]avelength[blank_end] of each overtone in each type of pipe.
    Imagen de la pregunta 9
    1. Aantinode
    2. Bopen
    3. Cfixed
    4. Dnode
    5. Eclosed
    6. F1/2
    7. Gharmonics
    8. Hrequency
    9. Iavelength
    10. Jalves
  10. 10Strobe Lamp:
    - A strobe lamp needs to [blank_start]capture[blank_end] the string [blank_start]twice[blank_end] per [blank_start]cycle[blank_end] in order to see the [blank_start]2[blank_end] positions of the standing wave (at maximum and minimum [blank_start]amplitude[blank_end] preferably).
    - Therefore maximum frequency of the strobe lamp must be [blank_start]2[blank_end] x f[blank_start]requency[blank_end] of vibration generator.
    - There is a maximum because any higher frequency will [blank_start]capture[blank_end] the string at points [blank_start]other[blank_end] [blank_start]than[blank_end] the maximum amplitude.
    Imagen de la pregunta 10
    1. Atwice
    2. Bcapture
    3. Ccycle
    4. D2
    5. Eamplitude
    6. F2
    7. Gother
    8. Hthan
    9. Icapture
    10. Jrequency

Información

Descripción
AS - Level (Waves and Particle Nature of Light) Sally's Physics Test sobre Standing Waves, creado por Sally Lancaster el 11/03/2016.
Idioma
English
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