Test
GEGE2001 Weeks 05 & 06 (L09, L10, L11, L12)
Este test tiene tipos de pregunta que se abren en el reproductor de siempre.
Preguntas del test (8)
1A population is polymorphic for a particular trait when the population has [blank_start]________[blank_end] phenotypes for that trait (each being >1%, so not ‘rare’).
- Amore than 2
- B2 or more
2True or false:
The frequency of an allele is determined [at least in part] by its dominance?- AVerdadero
- BFalso
3Based on the image above, what are the [at least expected] allele frequencies:
- AB = 0.2
- BB = 0.8
- Cb = 0.2
- Db = 0.8
- EB = 0.04
- Fb = 0.04
- GB = 0.64
- Hb = 0.64
4Based on the image above, what are the [at least expected] gene frequencies:
- ABB = 0.04
- BBb = 0.16
- CbB = 0.16
- Dbb = 0.64
- EBlack = 0.36
- FBlack = 0.64
- GYellow = 0.64
- HYellow = 0.36
- IB = 0.2
- Jb = 0.8
5Based on the image above, what are the [at least expected] phenotype frequencies:
- AB_ = 0.36
- Bbb = 0.64
- CBlack = 0.36
- DBlack = 0.64
- EYellow = 0.64
- FYellow = 0.36
- Gbb = 0.36
- HB_ = 0.64
6True or False:
Inbreeding results in the frequency of heterozygotes halving each generation.- AVerdadero
- BFalso
7True or False:
Self-fertilisation results in the frequency of heterozygotes halving each generation.- AVerdadero
- BFalso
8The inbreeding coefficient (F) adjusts genotype frequencies of ( A1A1 : A1A2 : A2A2 ) from ( p^2 : 2pq : q^2 ) to ( p^2 + Fpq : 2pq – 2Fpq : q^2 + Fpq ). Thus if a population expected to be ( 9 : 42 : 49 ) is observed at ( 20 : 20 : 60 ), what is F?
(...assume the only reason for the departure from expecteds is inbreeding)- A0.524
- B0.2
- C0.22
- D20
- E22
- F11
- G0.11
Información
- Descripción
- L09,L10,L11,L12 – Population Genetics
- Autor
- Michael Jardine
- Idioma
- English
- Visitas
- 91
- Historial
- Creado el 29 jun 2018 · actualizado el 29 jun 2018
- Etiquetas
- Valoración
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