Test
Physics 2.1 Forces and their effects
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Preguntas del test (30)
1What is acceleration?
- AA measure of how quickly velocity is changing
- BHow fast something is moving
2What is the resultant force?
- AThe single force that represents all the forces acting at a point and has the same effect on its motion as all the other individual forces.
- BA strong force that acts on an object
3If a non-zero resultant force acts on a stationary object?
- AThe object will accelerate in the direction of the resultant force
- BIt will float
- CIt will move
4If a resultant force acting on a stationary object is zero it will remain stationary?
- AVerdadero
- BFalso
5If the resultant force acting on a moving object is zero?
- AIt will continue to move at the same velocity
- BIt will slow down
- CIt will stop moving
6If the resultant force acting on an object is non-zero, it will accelerate in the direction of the resultant force?
- AVerdadero
- BFalso
7When the resultant force acts on an object, the object can experience 5 forms of acceleration: [blank_start]speeding up,[blank_end] [blank_start]slowing down[blank_end], [blank_start]starting[blank_end], [blank_start]stopping[blank_end] and [blank_start]changing direction[blank_end]
- Aspeeding up,
- Bstopping
- Cchanging direction
- Dslowing down
- Estarting
8How do you calculate the acceleration produced by a resultant force?
- AA=F/M or F=MXA
- BA=(V-U)/T
- CCHANGE IN VERTICAL/CHANGE IN HORIZONTAL
9When two objects interact, they exert forces on each other that are [blank_start]equal[blank_end] and [blank_start]opposite[blank_end]
- Aequal
- Bopposite
10On the surface of the planet, gravity makes everything [blank_start]accelerate[blank_end] towards the [blank_start]ground[blank_end] and gives everything a [blank_start]weight[blank_end]
- Aaccelerate
- Bground
- Cweight
11To calculate the weight of an object using its mass and gravitational field strength: [blank_start]W=mxg.[blank_end]
W is [blank_start]weight in N[blank_end]
M is [blank_start]mass in Kg[blank_end]
G is [blank_start]gravitational field strength in N/KG[blank_end]- AW=mxg.
- Bweight in N
- Cmass in Kg
- Dgravitational field strength in N/KG
12For a vehicle to travel at a steady speed...
- AThe driving force (provided by the engine) balances the resistive/frictional forces acting on the vehicle
- BThe driving force is greater than friction
- CFriction is grater than the driving force
13The [blank_start]frictional[blank_end] forces that oppose the motion of an object moving through a fluid [blank_start]increase[blank_end] with the objects [blank_start]speed[blank_end].
- Aincrease
- Bfrictional
- Cspeed
14Ways of increasing a vehicle's top speed include:
* [blank_start]Reducing drag[blank_end]: by altering the [blank_start]shape[blank_end] of a vehicle to make it more [blank_start]streamlined[blank_end].
* Increasing the [blank_start]power of the vehicle's engine[blank_end]: meaning the [blank_start]driving force[blank_end] becomes [blank_start]larger[blank_end] so the drag force on the vehicle will [blank_start]equal the driving force[blank_end] at a [blank_start]higher[blank_end] speed.- AReducing drag
- Bshape
- Cstreamlined
- Dpower of the vehicle's engine
- Edriving force
- Flarger
- Gequal the driving force
- Hhigher
15What is terminal velocity?
- AThe velocity at which the resistive forces (drag) acting on the object match the force due to gravity (weight)
- BThe fastest rate something travels
- CWhere the gravity is greater than the resistive forces
16When an object falls through a fluid it initially [blank_start]accelerates[blank_end] due to the force of [blank_start]gravity[blank_end] being [blank_start]greater[blank_end] than the [blank_start]frictional[blank_end] forces. As the object moves [blank_start]faster[blank_end], the [blank_start]frictional forces[blank_end] that act on it [blank_start]increase[blank_end]. This gradually [blank_start]reduces[blank_end] the [blank_start]acceleration[blank_end] until the [blank_start]frictional[blank_end] force is [blank_start]equal[blank_end] to the [blank_start]accelerating[blank_end] force so it wont [blank_start]accelerate[blank_end] anymore. It will have reached its [blank_start]maximum speed[blank_end] ([blank_start]terminal velocity[blank_end]) and will fall at a [blank_start]steady rate[blank_end].
- Aaccelerates
- Bgravity
- Cgreater
- Dfrictional
- Efaster
- Ffrictional forces
- Gincrease
- Hreduces
- Iacceleration
- Jfrictional
- Kequal
- Laccelerating
- Maccelerate
- Nmaximum speed
- Oterminal velocity
- Psteady rate
17The terminal velocity of falling objects depends on their [blank_start]shape[blank_end] and [blank_start]area[blank_end]. The accelerating force acting on all objects is [blank_start]gravity[blank_end] and if it were not for [blank_start]air resistance[blank_end], everything would fall at the [blank_start]same[blank_end] rate (like on the [blank_start]moon[blank_end]). The terminal velocity of objects is determined by its [blank_start]drag[blank_end] in comparison to its [blank_start]weight[blank_end]. The frictional force depends on its shape and area.
- Ashape
- Barea
- Cgravity
- Dair resistance
- Esame
- Fmoon
- Gdrag
- Hweight
18A parachute helps to reduce a diver's terminal velocity because it [blank_start]increases[blank_end] the surface area which increases the [blank_start]air resistance[blank_end] acting on the diver. This causes the diver to [blank_start]slow down[blank_end], which [blank_start]reduces[blank_end] his speed and therefore the [blank_start]terminal velocity[blank_end].
- Aincreases
- Bair resistance
- Cslow down
- Dreduces
- Eterminal velocity
19What is the stopping distance?
- AThe sum of how fast your going and how long it takes for the brakes to work
- BThe sum of the thinking distance and stopping distance
- CThe sum of the thinking distance and braking distance
20Thinking distance is the distance the vehicle travels during the driver's [blank_start]reaction[blank_end] time
Braking distance is the [blank_start]distance[blank_end] the vehicle travels after the [blank_start]brakes[blank_end] are applied until it comes to a complete [blank_start]stop[blank_end]- Areaction
- BBraking
- Cbrakes
- Dseat belts
- Ereactions
- Fdistance
- Gmetres
- Hstop
- Islow down
- Jdeceleration
21For a given braking force... what happens to the stopping distance?
- AThe faster a vehicle is moving, the greater the stopping distance and the braking force needed
- BThe slower the vehicle is moving, the greater the stopping distance, and the less braking force is needed
22Factors that affect thinking distance:
* How [blank_start]fast[blank_end] you're going - the faster you go, the [blank_start]longer[blank_end] the stopping distance
* How [blank_start]quick[blank_end] to [blank_start]respond[blank_end] you are - this can be affected by [blank_start]tiredness[blank_end], [blank_start]drugs[blank_end] and [blank_start]alcohol[blank_end]
* Bad [blank_start]visibility[blank_end]
*[blank_start]Distractions[blank_end] (e.g. rain, noise)- Afast
- Blonger
- Cquick
- Drespond
- Etiredness
- Fdrugs
- Galcohol
- Hvisibility
- IDistractions
23What does NOT affect braking distance.
- AHow fast you're going - it takes further to stop
- BHow good you're brakes are - worn or faulty brakes will not have as much force as reliable, new brakes
- CHow good the tyres are- should have a minimum tread depth of 1.6mm to get rid of water in wet conditions
- DHow good the grip of road surface is due to weather conditions (e.g. water, ice, snow, diesel spills) * You don't have as much grip, so travel further before stopping
- EThe make of the car and type of metal it is used from - the stronger the metal frame, the slower the breaking distance
24Braking and kinetic energy transfer:
To slow down a car, [blank_start]kinetic[blank_end] energy needs to be [blank_start]converted[blank_end] into other types of [blank_start]energy[blank_end]. (e.g.thermal and a little sound)
When the brakes of a car are applied, the [blank_start]friction[blank_end] between the [blank_start]wheels[blank_end] and the [blank_start]brakes[blank_end] converts kinetic energy into thermal energy, which causes the temperature of the brakes to [blank_start]increase[blank_end].
So, work is done by the [blank_start]braking[blank_end] force to convert the kinetic energy into thermal energy and a little [blank_start]sound[blank_end] energy.- Akinetic
- Bthermal
- Cgravitational
- Dconverted
- Eswapped
- Fchanged
- Genergy
- Hfuel
- Imaterials
- Jfriction
- Kcompression
- Lacceleration
- Mwheels
- Nbonnet
- Obrakes
- Pheadlights
- Qincrease
- Rdecrease
- Sbraking
- Tstopping
- Usound
- Vnoise
- Welastic
25What will NOT happen to an object when a force is applied to it?
- AStretch
- BChange in shape
- CFold
26Is an elastic object one that can change shape under an applied force, and then return to its original shape after the force has been removed?
- AVerdadero
- BFalso
27When a force does work to change the shape of an elastic object, the object [blank_start]stretches[blank_end] and stores [blank_start]elastic potential energy[blank_end]. The [blank_start]elastic potential energy[blank_end] is then [blank_start]converted[blank_end] to [blank_start]kinetic[blank_end] energy when the force is [blank_start]removed[blank_end] and the object returns to its [blank_start]original[blank_end] shape.
- Astretches
- Belastic potential energy
- Celastic potential energy
- Dconverted
- Ekinetic
- Fremoved
- Goriginal
28When a spring is supported at the top then a weight is attached to the bottom, it stretches. What is the formula for calculating the force applied to an object, given its extension and spring constant?
- AF=KXE
F=force applied (N)
K=spring constand (N/M)
E=extension (m - metres) - BJ=EXG
J=joules
E=energy
G=gravity - CU=FXP
U=U-value
F=Friction
P= Pendulum
- AF=KXE
29Hooke's law:
The extension of an elastic object is [blank_start]directly proportional[blank_end] to the [blank_start]force applied[blank_end] until the [blank_start]limit of proportionality[blank_end] is suceeded- Adirectly proportional
- Bthe same as
- Cless than
- Dforce applied
- Eenergy applied
- Fheat applied
- Glimit of proportionality
- HWeight
- ILength
30Is the limit of proportionality the point in which the an elastic object will no longer extend proportionally with the applied force?
- AVerdadero
- BFalso
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