13978046
Description
Flashcards by Thays Bach , updated more than 1 year ago
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Created by Thays Bach
almost 6 years ago
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| Question | Answer |
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Image:
Cones (binary/octet-stream)
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G² = H² + R² |
| Cone de revolução | |
| Área da Base | Ab = πR² |
| Área Lateral | Al = πRG |
| Área Total | At = πR² + πRG |
| Volume | V = πR²H/3 |
| Secção Transversal |
r/R=h/H=g/G=k
Ab/AB=(r/R)²=(h/H)²=(g/G)²=k²
v/V=(r/R)³=(h/H)³=(g/G)³=k³
Image:
B (binary/octet-stream)
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| Secção Meridiana |
Image:
Zz (binary/octet-stream)
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| Tronco do Cone |
Al = πG(R+r)
At = πR² + πr² +πG(R+r)
V = πH/3(R²+r²+Rr)
Image:
Tr (binary/octet-stream)
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| Relação métrica no tronco |
G² = (R-r)² + H²
Image:
Tr2 (binary/octet-stream)
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