Bazinga Cards

Question	Answer
Image: Bazinga Design (binary/octet-stream)	Multiply by 15
Image: Bazinga Design (binary/octet-stream)	Restart with 100. (everyone)
Image: Bazinga Design (binary/octet-stream)	My score x3 and other team's score x0.5
Image: Bazinga Design (binary/octet-stream)	Take away half of each team's score and add it to my team.
Image: Bazinga Design (binary/octet-stream)	Divide my score by 3.
Image: Bazinga Design (binary/octet-stream)	Multiply my score by 3.
Image: Bazinga Design (binary/octet-stream)	My score x5 and other teams score x2
Image: Bazinga Design (binary/octet-stream)	x15
Image: Bazinga Design (binary/octet-stream)	1000 points.
Image: Bazinga Design (binary/octet-stream)	Multiply your score by 10.
Image: Bazinga Design (binary/octet-stream)	Swap my points with the team that has the highest score.
Image: Bazinga Design (binary/octet-stream)	Give me 500 points from each team..
Image: Bazinga Design (binary/octet-stream)	Add 500 points to the lowest team from the team that has the highest score.
Image: Bazinga Design (binary/octet-stream)	Divide my score by 10
Image: Bazinga Design (binary/octet-stream)	Add 1/2 points of the team with the highest score to my team.
Image: Bazinga Design (binary/octet-stream)	Equal points.
Image: Bazinga Design (binary/octet-stream)	Multiply my score by 5.
Image: Bazinga Design (binary/octet-stream)	Spin the wheel to add other team's scores to my team. (don't deduct)
Image: Bazinga Design (binary/octet-stream)	Multiply my score by 20.
Image: Bazinga Design (binary/octet-stream)	Divide my score by 5.

Image: Bazinga Design (binary/octet-stream)

Multiply by 15

Image: Bazinga Design (binary/octet-stream)

Restart with 100. (everyone)

Image: Bazinga Design (binary/octet-stream)

My score x3 and other team's score x0.5

Image: Bazinga Design (binary/octet-stream)

Take away half of each team's score and add it to my team.

Image: Bazinga Design (binary/octet-stream)

Divide my score by 3.

Image: Bazinga Design (binary/octet-stream)

Multiply my score by 3.