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Description
Flashcards by ronnie barker, updated more than 1 year ago
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Created by ronnie barker
over 8 years ago
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| Question | Answer |
| The AND gate gives a high output (1) only if all its inputs are high. A dot (.) is used to show the AND operation i.e. A.B. | The OR gate gives a high output (1) if one or more of its inputs are high. A plus (+) is used to show the OR operation. |
| inverted version of the input . It is also known as an inverter. | The outputs of all NAND gates are high if any of the inputs are low. The symbol is an AND gate with a small circle on the output. The small circle represents inversion. |
| The outputs of all NOR gates are low if any of the inputs are high. The symbol is an OR gate with a small circle on the output. | give a high output if either, but not both, of its two inputs are high. An encircled plus sign (+) is used to show the EOR (EXOR) operation. |
| does the opposite to the EOR gate (EXOR). It will give a low output if either, but not both, of its two inputs are high. The symbol is an EXNOR gate with a small circle on the output. | Now to Binary |
| binary to denary for example 11001 into denary is 25 1 + 8 +16 | Now to Hexadecimal |
| These are the 16 hexadecimal digits : 0 1 2 3 4 5 6 7 8 9 A B C D E F. | Each hex digit reflects a 4-bit binary sequence. |
| B4 (hex) to Denary (example) 11 and 4 | B4 (hex) to Binary 1011 0100 |
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