58131
Description
Flashcards by anthonyjwheeler, updated more than 1 year ago
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Created by anthonyjwheeler
over 12 years ago
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| Question | Answer |
| 1/Tan θ= | Cot θ |
| Cot²θ-Cosec²θ= | -1 |
| Cot²θ= | Cosec²θ-1 |
| -Tan²θ= | 1-Sec²θ |
| Tan²θ-Sec²θ= | -1 |
| Sec²θ-Tan²θ= | 1 |
| Tan²θ= | Sec²θ-1 |
| -Sin²θ= | Cos²θ-1 |
| Sin²θ= | 1-Cos²θ |
| Cos²θ-1= | Sin²θ |
| Cos²θ= | 1-Sin²θ |
| Sin² θ+Cos² θ= | 1 |
| 1/Cos θ= | Sec θ |
| 1/Sin θ= | Cosec θ |
| Cosec θ= | 1/Sin θ |
| Sec θ= | 1/Cos θ |
| Cot θ= | 1/Tan θ |
| Cos θ/Sin θ= | Cot θ |
| Sin θ/Cos θ= | Tan θ |
| Tan θ= | Sin θ/Cos θ |
| Cot²+1= | Cosec² θ |
| Tan² θ+1= | Sec² θ |
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