Rectilinear Kinematics: Continuous 12Motion

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12.2
Eduardo Ramos
Mind Map by Eduardo Ramos, updated more than 1 year ago
Eduardo Ramos
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Rectilinear Kinematics: Continuous 12Motion
  1. Rectilinear Kinematics
    1. The kinematics of a particle is characterized by specifying, at any given instant, the particle’s position, velocity, and acceleration.
    2. Position
      1. The straight-line path of a particle will be defined using a single coordinate axis s, Fig. 12–1a. The origin O on the path is a fixed point, and from this point the position coordinate s is used to specify the location of the particle at any given instant. The magnitude of s is the distance from O to the particle, usually measured in meters (m) or feet (ft), and the sense of direction is defined by the algebraic sign on s.
      2. Displacement
        1. The displacement of the particle is defined as the change in its position. For example, if the particle moves from one point to another, Fig. 12–1b, the displacement is s = s - s
        2. Velocity
          1. If the particle moves through a displacement s during the time interval t, the average velocity of the particle during this time interval is vavg = s t If we take smaller and smaller values of t, the magnitude of s becomes smaller and smaller. Consequently, the instantaneous velocity is a vector defined as v = lim tS0 (s>t), or (S+ ) v = ds dt
          2. Acceleration
            1. Provided the velocity of the particle is known at two points, the average acceleration of the particle during the time interval t is defined as aavg = v t Here v represents the difference in the velocity during the time interval t, i.e., v = v - v, Fig. 12–1e. The instantaneous acceleration at time t is a vector that is found by taking smaller and smaller values of t and corresponding smaller and smaller values of v, so that a = lim tS0 (v>t), or (S+ ) a = dv dt
            2. Constant Acceleration, a = ac .
              1. Velocity as a Function of Time. Integrate ac = dv>dt, assuming that initially v = v0 when t = 0. L v v0 dv = L t 0 ac dt
                1. Position as a Function of Time. Integrate v = ds>dt = v0 + act, assuming that initially s = s0 when t = 0. L s s0 ds = L t 0 (v0 + act) dt
                  1. Velocity as a Function of Position. Either solve for t in Eq. 12–4 and substitute into Eq. 12–5, or integrate v dv = ac ds, assuming that initially v = v0 at s = s0 . L v v0 v dv = L s s0 ac ds
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