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Flashcards

calculating power

Farha Idrees Physics GCSE Inglês 16 flashcards

Flashcards do conjunto (16)

  1. 1define power ratingthe rate at which an appliance transfers energy, measured in joules per second or watts
  2. 21 Watt, W == 1 joule per second, j/s
  3. 3Give the formula for powerP = energy / time
  4. 4A 40W light bulb is switched on for 30 mins. Calculate the energy it transfers.time = 30 * 60s = 1800s
    energy = power * time
    = 40 * 1800
    = 72000 --> 72 kJ
  5. 5Give the formula for power, using currentpower = current x potential difference
  6. 6Calculate the normal current through a 500W , 230V heater + which fuse you need.current = power / p.d.
    = 500 / 230
    = 2.2 A
    you will need a 3A fuse
  7. 7Describe how a resistor workswork is being done by the battery, to make the ions pass through the resistor
    ↓
    each electron collides with the vibrating metal ions of the resistor
    ↓
    this transfers energy to the ions in the resistor
    ↓
    the ions gain kinetic energy so vibrate more
    ↓
    the resistor becomes hotter
    +
    heats the surroundings
    ↓
    the energy supplied to it is dissipated to the surroundings
  8. 8Give the formula for power supplied to a resistorpower = current^2 * resistance
  9. 9Give the formula for chargecurrent * time
  10. 10What happens when charge flows through a resistor?energy is transferred to the resistor, so the resistor becomes hotter
  11. 11Give the formula for energy transferred to a component.E = V * Q
  12. 12What is the energy from the battery transferred to?1. to the component
    2. to the resistor
  13. 13Give the formula for energyenergy = power * time
  14. 14How is the efficiency of a device calculated?from the power supplied to it and the useful energy it transfers
  15. 15efficiency == output / input (x100%)
  16. 16A 230V, 12A electric motor, has an efficiency of 60%, calculate the: a) power supplied to it b) output c) energy wasteda) power = current * voltage
    = 12 * 230
    = 2760W
    b) efficiency = 60% = 0.6
    output = efficiency * input
    output = 0.6 * 2760
    = 1660W
    c) energy wasted = total - output
    = 2760 - 1660
    = 1100W

Informações

Descrição
• 5.3: electrical power and potential difference • 5.4: electric currents and electrical transfers • 5.5: appliances and efficiency
Criado por
Farha Idrees
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