Genetics Final Exam

Question

The full chemical name of DNA is [blank_start]deoxyribonucleic acid[blank_end] .

Answer 1

deoxyribonucleic acid

Answer 2

Okazaki fragments

Answer 3

restriction

Answer 4

bacteriophage

Answer 5

single-stranded DNA

Answer 6

It is acidic.

Answer 7

It contains deoxyribose.

Answer 8

It is found in cell nuclei.

Answer 9

It contains phosphate.

Answer 10

It contains proteins.

Answer 11

carbohydrate

Answer 12

none of the above

Answer 13

phosphodiesters

Answer 14

nucleotides

Answer 15

nucleosides

Answer 16

cell membrane

Answer 17

endoplasmic reticulum

Answer 18

chromosomes

Answer 19

None of the above

Answer 20

a deoxyribose sugar

Answer 21

a nitrogenous base

Answer 22

a phosphate

Answer 23

A and B only

Answer 24

All of the above

Answer 25

none of the above

Answer 26

none of the above

Answer 27

guanine to adenine

Answer 28

adenine to thymine

Answer 29

cytosine to adenine

Answer 30

uracil to cytosine

Answer 31

none of the above

Answer 32

2.0 angstroms.

Answer 33

3.4 angstroms.

Answer 34

20 angstroms.

Answer 35

34 angstroms.

Answer 36

none of the above

Answer 37

2.0 angstroms.

Answer 38

3.4 angstroms.

Answer 39

20 angstroms.

Answer 40

34 angstroms.

Answer 41

none of the above

Answer 42

Electro-ionic

Answer 43

none of the above

Answer 44

conservative

Answer 45

semiconervative

Answer 46

dispersive

Answer 47

transferal

Answer 48

none of the above

Answer 49

Phosphodiester

Answer 50

Electrostatic

Answer 51

None of the above

Answer 52

a single continuous linear double helix.

Answer 53

a double helix replicated semiconservatively.

Answer 54

a double helix replicated conservatively.

Answer 55

single-stranded DNA.

Answer 56

None of the above

Answer 57

a single continuous linear double helix.

Answer 58

a double helix replicated semiconservatively.

Answer 59

a double helix replicated conservatively.

Answer 60

a triple helix replicated semiconservatively.

Answer 61

None of the above

Answer 62

Initiation

Answer 63

Elongation

Answer 64

Termination

Answer 65

Translation

Answer 66

Translocation

Answer 67

Initiation

Answer 68

Elongation

Answer 69

Termination

Answer 70

Translation

Answer 71

Translocation

Answer 72

Elongation

Answer 73

Termination

Answer 74

Translation

Answer 75

Translocation

Answer 76

Topoisomerases

Answer 77

none of the above

Answer 78

Topoisomerase

Answer 79

Telomerase

Answer 80

methylases

Answer 81

capping proteins

Answer 82

telomerases

Answer 83

single-stranded binding proteins

Answer 84

redundancy

Answer 85

repair enzymes

Answer 86

precision of replication machinery

Answer 87

DNA polymerase proofreading mechanism

Answer 88

Restriction endonucleases

Answer 89

Translation

Answer 90

Transcription

Answer 91

Recombination

Answer 92

Transformation

Answer 93

None of the above

Answer 94

Allelic exchange

Answer 95

Gene conversion

Answer 96

Crossing over

Answer 97

Recombination

Answer 98

DNA replication

Answer 99

homologous nonsister chromatids

Answer 100

homologous sister chromatids

Answer 101

heterologous nonsister chromatids

Answer 102

heterologous sister chromatids

Answer 103

None of the above

Answer 104

instruction from normal cell-cycle program

Answer 105

Chemical change

Answer 106

Physical change

Answer 107

phosphorous

Answer 108

none of the above

Answer 109

5' AATTCGCTTA 3'

Answer 110

3' AATTCGCTTA 5'

Answer 111

5' TAACGCTTAA 3'

Answer 112

5' TAAGCGAATT 3'

Answer 113

3' TAAGCGAATT 5'

Answer 114

abc, aBc, AbC, aBC

Answer 115

abc, abc, ABC, ABC

Answer 116

aBc, aBc, AbC, AbC

Answer 117

abC, abc, ABc, ABC

Answer 118

Abc, Abc, aBC, aBC

Answer 119

interphase

Answer 120

none of the above

Answer 121

homoduplex

Answer 122

heteroduplex

Answer 123

homotriplex

Answer 124

heterotriplex

Answer 125

none of the above

Answer 126

chromosome length will gradually increase

Answer 127

chromosome length will gradually decrease

Answer 128

chromosome length will stay constant

Answer 129

chromosomes will fail to dissociate after replication

Answer 130

none of the above

Answer 131

Methylases

Answer 132

Recombinases

Answer 133

Topoisomerases

Answer 134

radioactivity

Answer 135

gel filtration

Answer 136

ion exchange

Answer 137

centrifugation

Answer 138

none of the above

Answer 139

radiolabeled phosphate

Answer 140

calcium chloride

Answer 141

radiolabeled nitrogen

Answer 142

sodium acetate

Answer 143

cesium chloride

Answer 144

leading strand

Answer 145

Okazaki fragment

Answer 146

RNA primer

Answer 147

polymerase

Answer 148

lagging strand

Answer 149

genetic linkage

Answer 150

chi squared

Answer 151

terminalization

Answer 152

chromosomal interference

Answer 153

non-parental

Answer 154

15 map units

Answer 155

35 map units

Answer 156

Either 15 map units or 35 map units, depending on the order of the genes

Answer 157

The map distance between A and C can not be predicted from this data

Answer 158

0.5 > p > 0.1

Answer 159

spindle fiber

Answer 160

synaptic junction

Answer 161

synaptomnemal complex

Answer 162

none of the above

Answer 163

D and E are on different pairs of chromosomes.

Answer 164

D and E are linked and exactly 50 map units apart.

Answer 165

D and E are linked and at least 50 map units apart.

Answer 166

either A or B

Answer 167

either A or C

Answer 168

The crossover would have to occur between the A locus and the centromere and involve two homologous (non-sister) chromatids.

Answer 169

The crossover would have to occur between the A locus and the end of the chromosome and involve two homologous (non-sister) chromatids.

Answer 170

The crossover would have to occur on the same chromosome arm as the A locus and involve two homologous (non-sister) chromatids.

Answer 171

The crossover would have to occur on the same chromosome as the A locus and involve two homologous (non-sister) chromatids.

Answer 172

The crossover would have to occur between the A locus and the centromere and involve two sister chromatids (not homologous) chromatids.

Answer 173

The crossover would have to occur between the A locus and the centromere locus and involve two homologous (non-sister) chromatids.

Answer 174

The crossover would have to occur between the A locus and the B locus locus and involve two homologous (non-sister) chromatids.

Answer 175

The crossover would have to occur between the B locus and the end of the chromosome locus and involve two homologous (non-sister) chromatids.

Answer 176

A double crossover would have to occur, with one crossover between the A locus and the centromere and a second crossover between the A and B loci locus and both crossovers would have to involve two homologous (non-sister) chromatids.

Answer 177

No crossover in a somatic cell could generate a twin spot.

Answer 178

Two homologous chromatids break and rejoin at random sites along the chromosome.

Answer 179

The genetic information on one chromatid is replaced by copying genetic information from a homologous chromatid without there being any physical exchange between the chromosomes.

Answer 180

Two homologous chromatids break and rejoin at precisely the same site along the chromosome so that there is no loss or gain of material on either product.

Answer 181

It is not known what occurs during crossing over.

Answer 182

Chiasmata are randomly distributed along chromosomes.

Answer 183

All chromosome pairs have the same number of chiasmata.

Answer 184

A single chromosome pair always has the same number of chiasmata in every meiotic cell.

Answer 185

Chiasmata are spaced along a chromosome arm more regularly than would be expected by chance.

Answer 186

Chiasmata are spaced more irregularly along a chromosome arm than would be expected by chance.

Answer 187

If the allele frequencies in a population are given by p and q, the genotype frequencies are given by p2, 2 pq and q2.

Answer 188

The allele frequencies in a population will not change over time.

Answer 189

If the allele frequencies in a population are given by p and q, the genotype frequencies are given by p2 and q2. d. The first and third answers are correct.

Answer 190

The first and second choices are correct.

Answer 191

In populations with high selection pressure, the allele frequency is low.

Answer 192

the allele is recessive and deleterious.

Answer 193

The first and second choices are correct.

Answer 194

in populations with a high frequency of the allele, selection pressure is relatively low.

Answer 195

Allele frequencies will tend to move towards fixation or loss.

Answer 196

Allele frequencies will tend to move toward a stable equilibrium.

Answer 197

Allele frequencies may initially hover at an unstable equilibrium, but will eventually change.

Answer 198

the frequency of the allele will stay high for a long time, then decline slowly.

Answer 199

the allele declines in frequency until it is eliminated.

Answer 200

the frequency of the allele will be unchanged;

Answer 201

the population will remain in Hardy-Weinberg equilibrium. the frequency of the allele will decline rapidly, and then stabilize at very low frequency.

Answer 202

both alleles are maintained at a frequency different from that predicted by Hardy-Weinberg principles based on the strength of selection against the recessive allele.

Answer 203

the selective advantage enjoyed by the deleterious allele in the heterozygote exactly

Answer 204

genetic diversity in the population can be maintained indefinitely, in spite of selection acting against the allele. balances the selective disadvantage suffered by homozygous recessive individuals.

Answer 205

The first two choices are both correct.

Answer 206

The first three choices are correct.

Answer 207

genetic variation among populations will decline.

Answer 208

the most common outcome will be that the most common allele will become fixed (will increase to a frequency of 1) in the population.

Answer 209

both alleles are maintained in the population at frequencies different from those predicted by Hardy-Weinberg principles.

Answer 210

the genetic variation within a population is maintained over time

Answer 211

The mutation rate for new loss-of-function mutations in the CFTR gene is too low for the prevalence of the disease to be explained by mutation/selection balance.

Answer 212

Pier and his colleagues have found, in 11 European countries, an association between the severity of typhoid fever outbreaks and the frequency of the delta-F508 allele (the most common loss-of-function mutation) a generation later.

Answer 213

Pier et al. engineered cells homozygous for functional CFTR alleles, homozygous for a common loss-of-function allele, and heterozygous for the two. The loss-of-function homozygotes were virtually impervious to invasion by typhoid fever-causing bacteria; heterozygotes were more vulnerable, but accumulated 86% fewer bacteria than did the dominant homozygotes.

Answer 214

All of the choices above are correct.

Answer 215

Salmonella typhi bacteria manipulate their host cells, causing them to express more CFTR protein on their membranes.

	Criado por Engela Zalmy mais de 7 anos atrás

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