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saso70 86 perguntas 4,0 (2 avaliações)

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  1. 1Reporting from a Star schema is simpler than reporting from a normalized online
    transactional processing (OLTP) schema. What are the reasons for wanting simpler
    reporting? (Choose all that apply.)
    1. AA Star schema typically has fewer tables than a normalized schema. Therefore,
      queries are simpler because they require fewer joins.
    2. BStar schema has better support for numeric data types than a normalized rela-
      tional schema; therefore, it is easier to create aggregates.
    3. CThere are specific Transact-SQL expressions that deal with Star schemas.
    4. DA Star schema is standardized and narrative; you can find the information you
      need for a report quickly.
  2. 2You are creating a quick POC project. Which schema is the most suitable for this kind
    of a project?
    1. AStar schema
    2. BNormalized schema
    3. CSnowflake schema
    4. DXML schema
  3. 3A Star schema has two types of tables. What are those two types? (Choose all that
    apply.)
    1. ALookup tables
    2. BDimensions
    3. CMeasures
    4. DFact tables
  4. 4You implement a Type 2 solution for an SCD problem for a specific column. What do
    you actually do when you get a changed value for the column from the source system?
    1. AAdd a column for the previous value to the table. Move the current value of the
      updated column to the new column. Update the current value with the new value
      from the source system.
    2. BInsert a new row for the same dimension member with the new value for the
      updated column. Use a surrogate key, because the business key is now duplicated.
      Add a flag that denotes which row is current for a member.
    3. CDo nothing, because in a DW, you maintain history, you do not update dimen-
      sion data.
    4. DUpdate the value of the column just as it was updated in the source system.
  5. 5Which kind of a column is not a part of a dimension?
    1. AAttribute
    2. BMeasure
    3. CKey
    4. DMember property
    5. EName
  6. 6How can you spot natural hierarchies in a Snowflake schema?
    1. AYou need to analyze the content of the attributes of each dimension.
    2. BLookup tables for each dimension provide natural hierarchies.
    3. CA Snowflake schema does not support hierarchies.
    4. DYou should convert the Snowflake schema to the Star schema, and then you would
      spot the natural hierarchies immediately.
  7. 7Over which dimension can you not use the SUM aggregate function for semi-additive
    measures?
    1. ACustomer
    2. BProduct
    3. CDate
    4. DEmployee
  8. 8Which measures would you expect to be non-additive? (Choose all that apply.)
    1. APrice
    2. BDebit
    3. CSalesAmount
    4. DDiscountPct
    5. EUnitBalance
  9. 9Which kind of a column is not part of a fact table?
    1. ALineage
    2. BMeasure
    3. CKey
    4. DMember property
  10. 10Which database objects and object properties can you use for autonumbering?
    (Choose all that apply.)
    1. AIDENTITY property
    2. BSEQUENCE object
    3. CPRIMARY KEY constraint
    4. DCHECK constraint

Informações

Descrição
Implementing a Data Warehouse with Microsoft SQL Server 2012
Autor
saso70
Idioma
English
Visualizações
858
Avaliação
4,0 de 5 · 2 avaliações
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