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2.1

Lucia Elliott Englisch

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2.1

  • 2.1.1.1 Atomic structure and isotopes: •Atomic number= proton number •Mass number= protons+neutrons (nucleon number) •Isotopes are atoms of the same element with different numbers of neutrons and therefore different masses •The existence of isotopes was confirmed using mass spectrometers which deflect ions in a magnetic field. •4 stages of mass spectrometry:1- ionisation (a sample is bombarded with electrons to produce a positive ion) 2- acceleration (the ion is accelerated by an electric field) 3- deflection ( the ion passes through a magnetic field to deflect it. The higher the mass the less deflection) 4- detection (a sensor then detects and records the ions reaching it) •Mass spectra: this is what is produced by the spectrometer, it shows the abundance against mass/charge (m/z). The number of peaks is the number of isotopes. The height of each peak is the % abundance. The m/z is equal to the relative mass of the atom as the charge is normally 1.
  1. 2.1.1.1 Atomic structure and isotopes

    • Atomic number=proton number
    • Mass number= nucleon number(protons and neutrons)
    • Isotopes are atoms of the same element with a different number of neutrons and therefore masses
      • The existence of isotopes was confirmed by mass spectroscopy which deflects ions in a magnetic field
      • Mass spectroscopy has 4 stages
        • 1-IONISATION: a sample is bombarded with electrons to produce a positive ion
        • 2-ACCELERATION: the ions is accelerated through and electric field
        • 3-DEFLECTION: the ion passes through a magnetic field to deflect it. Higher mass=less deflection.
        • 4-DETECTION: a sensor detects and records the ions reaching it
          • This stage produces a mass spectra graph. It shows the abundance against the m/z (mass/charge)
            • The number of peaks=the number of isotopes present
            • The height of each peak=percentage abundance
  2. 2.1.1.2 Relative masses

    • Relative mass is not a way of measuring the mass of an atom as they are too small but a way of comparing them.
    • We compare the mass of atoms to 1/12th of the mass of a carbon-12 isotope which is taken to be exactly 12
      • Carbon-12 has 12 nucleons so 1-12 of this could be either a proton or a neutron
        • H had 1 proton so a relative mass of 1
        • Li has 7 nucleons (3p,4n) so a RM of 7
    • Relative isotopic mass: the mass of an isotope compared to 1/12 of the mass of an atom of carbon-12
    • Relative atomic mass: the weighted mean mass of an atom of an element compared to 1/12 of the mass of an atom of carbon-12
      • It is the weighted mean mass due to the presence of isotopes, it takes in to account the mass each isotope provides.
  3. 2.1.2.1 formulae and equations

    • The charge of the ion is determined by the number of valance electrons that it can loose or gain
      • G1= 1 outer shell electron so +1
    • Common molecular ions: nitrate=NO3(-) Carbonate=CO3(2-) Sulfate=SO4(2-) Hydroxide=OH(-) Ammonium=NH4(+) Zinc=Zn(2+) Silver=Ag+
    • Stoichiometry is a balanced chemical equation that shows the quantitative relationship between each chemical
      • When ionic substances react, often, only a few ions are involved so an ionic equation is used instead
        • E.g. HCl+NaOH>NaCl+H2O
          • Only the hydrogen and hydroxide ions react. The others are spectator ions
            • H++OH->H2O
  4. 2.1.3.1 moles and Stoichiometry

    • One mole is the amount of substance that contains as many particles as there are atoms in exactly 12g of carbon-12
      • The mass of a carbon-12 atom is approximately 1.99264*10^-23g
        • So the number of carbon atoms in 12g is X12 this much. Which is 6.022*10^23 atoms
          • This is Avogadro's constant. So one mole contains this many particles. No matter what substance it is
    • Molar mass: one mole of any substance will have a mass equal to the value of its molar mass due to the reletionship
      • Stoichiometric relationships: Stoichiometry can be used to determine the mole so/mass of a substance needed/formed during a reaction
  5. Percentage yield and atom economy

    • Percentage yield
      • Stoichiometric relationships can be used to determine the theoretical amount of product formed during a reaction.
      • The % yield shows how much product actually formed compared to the theoretical amount
      • % yield=(product obtained/theoretical amount of product)X100
      • The higher the % yield the more efficient the reaction
    • Atom economy
      • This is becoming more important to industry as it considers the amount of waste being produced
      • Atom economy= (Mr of desired products/sum of Mr of all products)X100
        • Atom economy can be improved by finding uses for the unwanted products that are formed, thus making it more sustainable
  6. 2.1.3.3 empirical and molecular formulae

    • Empirical formula is the simplest whole number ratio of elements within a substance
      • Molecular formulae shows the exact number of each element that is present within a substance
  7. 2.1.3.3 water of crystallisation

    • It is the water contained within salt crystals
    • Hydrous salts contain water of crystallisation E.g. FeCl2•6H2O
      • Anhydrous salts lack water of crystallisation E.g.FeCl2
  8. 2.1.3.5 Molar volumes

    • One mole of any gas at RTP will occupy a volume of 24p dm3
      • At standard conditions (STP 273K,100kPa) a One mole of gas will occupy a volume of 22.7dm3
  9. 2.1.3.5 ideal gas equation

    • Ideal gases
      • They are gases that have molecules in random motion, no intermolecular forces present, elastic collisions so no exchange of kinetic energy and particles of zero volume
        • Real gases don't follow these conditions exactly but do get close at high temp or low pressures, but all gas equations assume they do
    • Gas volumes are directly linked to
      • Avogadro's law: higher moles=higher volume
      • Charles' law: higher temperature=higher volume
        • The ideal gas equation is PV=nRT
          • R is calculated at standard conditions to give 8.134Jmol-1K-1
            • p=101.32kPa
            • V=22.414dm3
            • N=1mol
            • T=273K
      • Boyle's law: higher pressure=lower volume
        • Combining these laws and adding the constant of proportionality you get the ideal gas equation
  10. 2.1.3.7 Concentration

    • The concentration of a solution is a measure of the amount of solute dissolved within a volume of solvent
      • Solute-substance that has dissolved
      • Solvent-substance other chemicals dissolve in, usually water
      • The relationship between concentration and moles is: moles=concentration *volume, where v is in dm3 and c is in mol dm-3
      • Dilution
        • Dilution is often required so working out the dilution factor is needed
          • Dilution=original conc./diluted conc.
            • Once the dilution has been calculated the volume of original stock that is required can be determined
              • The remaining volume needed is given with distilled water
                • Original stock volume=total volume needed/ dilution
  11. 2.1.4.1 Acids, bases, alkalis and neutralisation

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Mind Map on 2.1, created by Lucia Elliott on 15/04/2018.
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