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Ordinary Differential Equations
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Q1 - ODE's
Introduction
The relationship between independent variable 'x' and dependent variable 'y'.
The derivative, dy/dx is the rate of change of something (first order differential equation)
The second derivative, d2y/dx2 is the rate of change of the rate of change (second order differential equation)
dy/dx is also written as y'
d2y/dx2 is also written as y"
Direct Integration
When the differential equation can be written as dy/dx = f(x) it can be solved directly by integrating both sides with respect to x
This approach can also be used to solve equations of the form d2y/dx2 = f(x)
If an additional condition is known, then the integration constant can be determined
This means the particular equation can be obtained
Variable Separable Method
When the differential equation must be written as dy/dx = f(x)g(y) [where f(x) is a function of x and g(y) is a function of y] it must be solved by separation of variables, first rearranging so that all the y terms are on the left hand side and all the x terms are on the right hand side
The general solution (equation containing constants such as 'c') can then be obtained by integrating both sides with respect to x
If an additional condition (eg y(2) = 0) is given, it can be used to determine the constant 'c' to obtain the particular solution
To answer a question, follow these steps:
Separate the variables (get all the x and all the y on separate sides)
Integrate, then rearrange to obtain the general solution 'y = ...'
Use the given condition to find the particular solution
Integration Factor
When the differential equation can be written as dy/dx + p(x)y = q(x) where p(x) and q(x) are different functions of x, it can be solved using the integration factor
Both sides of the equation are multiplied by a specially chosen function which allows the left hand sixe to be integrated analytically
The integration factor α(x) is such that dα(x)/dx = α(x)p(x)
α(x) = e ^ ∫ p(x) dx
To answer a question follow these steps:
Find the integration factor
Multiply both sides of the differential equation by the integration factor
Use the product rule to re-write the left hand side
Integrate both sides with respect to x, then rearrange to obtain the general solution
Use the given condition to obtain the particular solution
Second order linear differential equations Many problems in engineering result in second order differential equations in the form:
a d2y/dx2 + bdy/dx + cy =f(x)
Where a, b and c are all constant coefficients and f(x) is a function in terms of the variable x only
There are two types of second order differential equations:
Homogeneous equations
Inhomogeneous equations
Homogeneous equations
When f(x) =0, the equation is known as a homogeneous equation
if y = u(x) and y=v(x) are solutions of the equation then y = u + v is also a solution
To find the solution to an ODE in the form shown above, the auxiliary equation method is used
This is when the equation takes the form where "am2 + bm + c" forms a part. This is called the auxiliary equation and solutions can be found using the quadratic equation
When solving a second order ODE using the auxiliary equation, there are three cases to consider:
Distinct real roots (b2 > 4ac)
Complex roots (b2
Repeated (real) roots (b2 = 4ac)
To answer a question, use the following method:
Identify the auxiliary equation
Obtain the values of m
determine if the solution is real, complex or distinct and construct the general solution
Use the given conditions to obtain the particular solution
Inhomogeneous Equations
When f(x) does not = 0, the equation is an inhomogeneous second order ODE
The general solution to an inhomogeneous equation consists of two parts - the complimentary solution (solution to the homogeneous equation) and the particular integral. y = yc + yi
Choosing the particular integral:
If f(x) is exponential, choose yi to be exponential with the same growth rate as f(x)
If f(x) is polynomial, choose yi to be polynomial to the same degree
If f(x) contains sine/cosine choose yi to contain sine/cosine with the same period
To answer a question use the following method:
find the complimentary solution (yc)
Select an appropriate particular integral (yi)
substitute the particular integral into the equation
combine the complimentary function and particular integral to obtain the general solution
Use the given conditions to obtain the particular solution
Informationen
- Beschreibung
- Degree level Further Mathematics for Engineers (Ordinary Differential Equations) Notiz am Ordinary Differential Equations, erstellt von rhiannonsian am 09/04/2015.
- Erstellt von
- rhiannonsian · Apr 2015
- Aktualisiert
- 16 Aug 2017
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