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Fragen in diesem Quiz (186)
1762m converted into feet is:
- A2 500 ft
- B25000 ft
- C2 400 ft
- D232.3 ft
2The pressure on the threshold of the runway in use is expressed as:
- AQFE
- BQNE
- CQNH
- DSTD
3Magnetic variation is:
- AThe acute angle between the meridian and the magnetic meridian.
- BThe acute angle between the direction of the Earth's magnetic vector and the plane tangent to its surface.
- CThe acute angle between the magnetic meridian and the meridian of the magnetic compass, as measured by the semi-circular direction measurement system.
- DLine connecting points of equal inclination value.
4Compass deviation is:
- AThe acute angle between the magnetic meridian and the meridian of the magnetic compass, as measured by the semi-circular direction measurement system.
- BThe acute angle between the meridian and the magnetic meridian.
- CThe acute angle between the direction of the Earth's magnetic vector and the plane tangent to its surface.
- DLine connecting points of equal inclination value.
5 Longitude is:
- AThe dihedral angle between the prime meridian plane and the plane of the meridian passing through the given point on Earth's surface.
- BThe arc connecting the two geographical poles of the Earth, which is an intersection of the surface
of the Earth with the plane passing through the axis of rotation of the Earth. - CThe arc formed by the intersection of the Earth's surface with the plane perpendicular to Earth's axis, passing through its center.
- DThe angle between the equator plane and the vertical (radius) of the given point.
6 In order to determine the three-dimensional GPS position of the object, one requires:
- AReceiving the signal from four satellites.
- BReceiving the signal from two satellites.
- CTwo receivers.
- DThree receivers.
7Operation of which device is based on the impact of Earth's magnetic field?
- AMagnetic Compass.
- BBank indicator cross level.
- CVOR / ILS
- DVertical speed indicator.
8 0100 hours local time in Poland in the summer time corresponds to:
- A2300 UTC the previous day.
- B2400 UTC the previous day.
- C0100 UTC.
- D1100 UTC.
90300 hours local time in Poland in the summer time corresponds to:
- A0100 UTC.
- B0400 UTC.
- C0200 UTC.
- D1500 UTC.
100300 hours local time in Poland in the winter time corresponds to:
- A0200 UTC.
- B0400 UTC.
- C0100 UTC.
- D1500 UTC.
111300 hours local time in Poland in the winter time corresponds to:
- A1200 UTC.
- B1400 UTC.
- C0100 UTC.
- D1100 UTC.
122300 hours local time in Poland in the summer time corresponds to:
- A2100 UTC.
- B0100 UTC next day.
- C2200 UTC.
- D1100 UTC.
13How long in centimeters on a map scaled 1: 500,000 is a section equal to 105 km on the ground:
- A21 cm.
- B42 cm.
- C25 cm.
- D10.5 cm.
14What is the value of the inclination of the North Magnetic Pole?
- A90 degrees.
- B0 degrees.
- C60 degrees.
- D45 degrees.
15 Magnetic inclination is:
- AThe angle between the direction of the Earth's magnetic vector and the plane tangent to the surface.
- BThe angle between the meridian and the magnetic meridian.
- CThe angle between the meridian and the meridian of the magnetic. compass, as measured by the semi-circular direction measurement system.
- DLine connecting points of equal value declination.
16 Isogon is:
- AThe line connecting points of equal magnetic variation value.
- BThe angle between the meridian and the magnetic meridian.
- CThe angle between the meridian and the meridian of the magnetic compass, as measured by the semi-circular direction measurement system.
- DThe angle between the direction of the Earth's magnetic vector and the plane tangent to its surface.
17What is the value of the inclination on the South Magnetic Pole?
- A90 degrees;
- B0 degrees;
- C60 degrees;
- D45 degrees;
18 Which direction is defined as NE?
- A045°;
- B095°;
- C135°;
- D345°;
19Which direction is defined as NW?
- A315°;
- B295°;
- C335°;
- D205°;
20Which direction is referred to as the SE?
- A135°;
- B095°;
- C315°;
- D045°;
21 Which direction is referred to as SW?
- A225°;
- B295°;
- C335°;
- D205°;
22One degree of arc of great circle of the Earth corresponds to the distance of:
- A60 NM.
- B1 NM.
- C60 km.
- D100 km.
23 One nautical mile [NM 1] is equal:
- A1852m.
- B1620m.
- C1820m.
- D1013m.
24 One minute of arc of great circle of the Earth corresponds to the distance of:
- A1 NM.
- B1 km.
- C60 km.
- D2 km.
25 The time is 1200 UTC. Air traffic controller at the Lodz-Lublinek airport looks straight to the South. He sees the sun:
- AOn the right side.
- BOn the left side.
- CStraight ahead.
- DDuring summertime on the right, during wintertime on the left.
26If the altimeter setting window the pressure value corresponding to QNH is selected, the altimeter will indicate:
- AAltitude.
- BAbsolute altitude.
- CHeight.
- DFlight level.
27If the magnetic variation and compass deviation are positive, the compass heading will be:
- ALower than the true heading.
- BHigher than the true heading.
- CEqual to the magnetic heading.
- DEqual to the true heading.
28 If the magnetic variation and compass declination is negative, the compass heading will be:
- AHigher than the geopgraphical rate.
- BLower than the true heading.
- CEqual to the magnetic heading.
- DEqual to the true heading.
29 If the wind vector is perpendicular to the true track and blows from the left, the drift angle will be:
- AMaximum.
- BZero.
- CPositive, but not at the maximum.
- DNegligibly low.
30Dihedral angle between the Greenwich meridian plane and the plane of the meridian passing through the given point on Earth's surface is:
- ALongitude.
- BEarth's meridian.
- CThe equator.
- DLatitude.
31Dihedral angle between the Greenwich meridian plane and the plane of the meridian passing through the given point on Earth's surface is:
- AInclination.
- BDeclination.
- CDeviation.
- DIsogon.
32The angle between the equator and the vertical (radius) of the given point is:
- ALatitude.
- BMeridian.
- CThe equator.
- DLongtitude.
33The angle between the meridian and the magnetic meridian is:
- ADeclination.
- BInclination.
- CThe true heading.
- DThe magnetic heading.
34The angle between the meridian and the magnetic compass meridian, measured in accordance with the semi-circular direction measurement system is:
- AMagnetic Variation.
- BDeclination.
- CMagnetic heading.
- DCompass heading.
35 Drift angle is:
- AThe angle between the longitudinal axis of the aircraft and the desired track.
- BThe angle between the northern direction of the meridian and desired track.
- CThe angle between the direction of "where the wind blows" and the magnetic north.
- DThe angle between the longitudinal axis of the aircraft and the direction of "where the wind blows".
36Direction 045 ° is defined as:
- ANE;
- BSE;
- CSW;
- DNW;
37Direction 135 ° defined as:
- ASE;
- BNE;
- CSW;
- DNW;
38 Direction 225 ° is defined as:
- ASW
- BSE
- CNE
- DNW
39Direction 315 °is defined as:
- ANW
- BSE
- CSW
- DNE
40The shorter arc of great circle designating the shortest distance between two points on Earth's surface is:
- AOrthodrome.
- BRhumb line.
- CThe curve connecting these points, comprising a number of rhumb lines.
- DIsohips.
41 The heading of the aircraft is the angle measured to the right from 0° to 360 ° between:
- AThe northern direction of the meridian and the longitudinal axis of the aircraft.
- BThe northern direction of the meridian and the desired track of the aircraft.
- CThe northern direction of the meridian and the transverse axis of the aircraft.
- DThe northern direction of the meridian and the runway direction.
42During the summer in Poland, Coordinated Universal Time (UTC) will be calculated by:
- ASubtracting 2 hours from the local time (LMT) [UTC = LMT-2h].
- BAdding one hour to the local time (LMT) [UTC = LMT+1h].
- CAdding two hours to the local time (LMT) [UTC = LMT+2h].
- DSubtracting one hour from the local time (LMT) [UTC = LMT-1h].
43The line connecting points of equal declination values is:
- AIsogon.
- BDeclination.
- CDeviation.
- DInclination.
44The line on the surface of the Earth crosses the meridians at the same angles are:
- ARhumb line
- BOrthodrome.
- CIsogon.
- DIsobar.
45The arc between the two geographical poles of the Earth, which is the intersection of the surface of the Earth plane with the plane passing through the axis of rotation of the Earth, is:
- AEarth's meridian.
- BThe equator.
- CLongitude.
- DLatitude.
46 The arc formed by intersecting the Earth's surface with a plane perpendicular to the axis of the Earth, passing through its center, is:
- AThe equator.
- BEarth's meridian.
- CLongitude.
- DLatitude.
47Given the following data: true heading 200 degrees, declination 10 degrees W, magnetic variation -4 degrees, provide the compass heading:
- A214 degrees
- B186 degrees
- C206 degrees
- D194 degrees
48 On the aeronautical chart scaled 1: 1,000,000 a 20 cm section corresponds to the actual ground distance of:
- A200 km
- B50 km
- C100 km
- D20 km
49 On the aeronautical chart scaled 1: 200,000 a 20 cm section corresponds to the actual ground distance of:
- A40 km
- B20 km
- C80 km
- D100 km
50On the aeronautical chart scaled 1: 500,000 a 20 cm section corresponds to the actual ground distance of:
- A100 km
- B50 km
- C10 km
- D200 km
51 On the aeronautical chart scaled 1: 500,000 the distance between points is 27 cm. What is the actual distance between those points?
- A73 NM
- B54 NM
- C108 NM
- D135 NM
52Setting the altimeter scale so that it indicates terrain elevation, when on the ground (at the aerodrome) is denoted as:
- AQNH
- BQNE
- CQFE
- DQDM
53 True track = 259°, Magnetic track = 255° , Magnetic deviation = 2°. The values of declination and compass heading are, respectively
- A4°E, 253°
- B2°W, 255°
- C4°W, 251°
- D2°E, 249°
54 True track = 358 °, magnetic variation = 5 °, compass deviation = 4°. Magnetic track and compass heading values are, respectively
- A003°, 359°
- B359°, 003°
- C007°, 010°
- D360°, 359°
55The distance between 10 and 11 ° west longitude on the equator is:
- A111 km
- B60 km
- C60 statute Miles
- D111 NM
56 The distance between 29 and 30 degrees east longitude on the equator is:
- A111 km
- B60 km
- C60 Statute miles
- D111 NM
57The distance between 45 and 46 ° N latitude is:
- A111 km
- B60 km
- C60 Statute miles.
- D111 NM
58The term "knot" [kt] means:
- ANM/h
- BSM/h
- Ckm/h
- Dm/h
59 Provide the length of Earth's equator:
- A21 600 NM
- B21 600 km
- C12 714 NM
- D6 865 NM
60Earth's meridian is:
- AThe arc connecting the two geographical poles of the Earth, which is the intersection of the surface of the Earth plane with the plane passing through the axis of rotation of the Earth.
- BThe arc formed by the intersection of the Earth's surface with a plane perpendicular to Earth's axis, passing through its center.
- CThe dihedral angle between the prime meridian plane and the plane of the meridian passing through the given point on Earth's surface.
- DThe angle between the equator and the vertical (radius) of the given point.
6115 m/s converted into knots are:
- A30
- B27
- C24
- D34
62180 km/h converted into m/s is:
- A50
- B30
- C60
- D90
63 20 m/s converted into km/h are
- A72
- B24
- C88
- D100
64 Ground speed is:
- AThe speed of the aircraft relative to the ground.
- BCAS with taking wind into consideration.
- CIAS with taking wind into consideration.
- DMach number.
65When calculating azimuths (track) on the ICAO map smallest measurement error is achieved when:
- AThe protractor is applied to the meridian closest to the center of the flight route.
- BThe protractor is applied to the departure point of the flight route.
- CThe protractor is applied to the point of intersection of the extension of the track section with the meridian of the map frame.
- DThe protractor is applied to the destination point of the flight route.
66 Points A and B are at the distance of approx. 15 km from each other. The distance on the map is 6 cm. What is the scale of this map?
- A1: 250 000
- B1: 300 000
- C1: 400 000
- D1: 500 000
67 Points A and B are at the distance of approx. 25 km from each other. The distance on the map is 10 cm. What is the scale of this map?
- A1: 250 000
- B1: 300 000
- C1: 400 000
- D1: 500 000
68Points A and B are at the distance of approx. 45 km from each other. The distance on the map is 9 cm. What is the scale of this map?
- A1: 500 000
- B1: 250 000
- C1: 400 000
- D1: 300 000
69QFE is:
- AAtmospheric pressure at the airport or the runway threshold.
- BThe pressure at mean sea level.
- CStandard pressure.
- DFactory setting of the altimeter.
70 QNH is:
- AAltimeter setting indicating a hill when on the ground (at the aerodrome).
- BAtmospheric pressure at the airport or the runway threshold.
- CStandard pressure.
- DFactory setting of the altimeter.
71 Earth's equator is:
- AThe arc formed by the intersection of the Earth's surface with a plane perpendicular to the Earth's axis, passing through its center.
- BThe arc connecting the two geographical poles of the Earth, which is the intersection of the surface of the Earth with the plane passing through the Earth's axis of rotation.
- CThe dihedral angle between the prime meridian plane and the plane of the meridian passing through the given point on Earth.
- DThe angle between the equator and the vertical (radius) of the given point.
72Earth's equator creates with all meridians the angle of:
- A90°
- B60°
- C45°
- D180°
73Latitude is:
- AThe angle between the equator's plane and the vertical (radius) of the given point.
- BThe arc formed by the intersection of the Earth's surface with a plane perpendicular to the Earth's axis, passing through its center.
- CThe dihedral angle between the prime meridian plane and the plane of the meridian passing through the given point on Earth.
- DThe arc connecting the two geographical poles of the Earth, which is the intersection of the surface of the Earth with the plane passing through the Earth's axis of rotation .
74The average cruising speed of the aircraft is 60 km / h. Within 18 minutes the aircraft will fly the distance of:
- A18 km
- B12 km
- C3 km
- D23 km
75VSI shows a value of 500 ft / min. Converted into m/s the value will be:
- A2.5 m/s
- B3.5 m/s
- C5.0 m/s
- D15 m/s
76VSI shows the value of 750 ft / min.Converted into m/s the value will be:
- A3.8 m/s
- B2.5 m/s
- C5.0 m/s
- D7.5 m/s
77The altitude is:
- AThe height measured from mean sea level.
- BThe height from the ground level, over which the aircraft flying at a time.
- CThe height measured from any surface (level), e.g. the level of the runway threshold.
- DNone of the above.
78 The true altitude is:
- AThe height from the ground level, over which the aircraft is flying at the time.
- BThe height measured from mean sea level.
- CThe height measured from any surface (level), e.g. the level of the runway threshold.
- DNone of the above.
79The height is:
- AThe height measured from any surface (level), e.g. the level of the runway threshold.
- BThe height from the ground level, over which the aircraft is flying at the time.
- CThe height measured from mean sea level.
- DNone of the above.
80 From the list below select a linear landmark:
- ARailway tracks.
- BA sharp meander of the river.
- CHigh radio mast
- DBridge.
81 From the list below select a surface landmark:
- AA large city.
- BVillage.
- CSea shore.
- DIntersection of main roads.
82 From the list below select a point landmark:
- ABridge.
- BA large city.
- CRailroad tracks.
- DForest block.
83 In the Winter in Poland, the Coordinated Universal Time (UTC) is calculated by:
- ASubtracting one hour from the local time (LMT), [UTC = LMT-1h].
- BAdding one hour to the local time (LMT), [UTC +1 h = LMT]
- CAdding two hours to the local time (LMT) f [UTC + 2 h = LMT].
- DSubtracting two hours from the local time (LMT) [UTC = LMT-2h].
84Compass deviation = -3° , Variation = 2°E, Compass heading = 127°. Magnetic track and true track values are respectively:
- A124°, 126°
- B126°, 128°
- C124°, 124°
- D126°, 124°
85Variation = 3° E, Magnetic track = 188 °, Compass heading = 190 °. True track and Compass deviation values are respectively:
- A191°, -2°
- B185°, -2°
- C194°, +4°
- D189°, -3°
86To calculate the distance provided in kilometers into nautical miles we apply the following principle:
- A(km : 2) + 10%
- B(km × 2) - 20%
- C(km : 2) - 10%
- D(km × 2) - 10 %
87To calculate the distance provided in meters into feet, we apply the following principle:
- A(m × 3) + 10%
- Bm × 0.3
- C(m : 10) × 3
- D(m × 3) : 10
88ADF (Automatic Direction Finder) is:
- ARadio compass.
- BVHF radio ranger.
- COnboard response device.
- DSecondary surveillance radar.
89 Inertial navigation system operates on the principle of:
- ASumming up the location changes in space and the accelerations of the aircraft.
- BMeasuring the difference in depth of modulation.
- CMeasuring the difference in distance.
- DComparing the IAS and TAS.
90 Standard pressure is denoted as:
- AQNE
- BQFE
- CQNH
- DQDM
91Standard pressure expressed in inches of mercury is:
- A29.92 inHg
- B32.10 inHg
- C28.50 inHg
- D10.13 inHg
92The time used in the GPS is:
- ASystem's own system time correlated with the UTC.
- BSystem's own time completely independent of UTC.
- CThe time of satellite and system clocks corresponds exactly to the UTC.
- DThe time of satellite and system clocks corresponds exactly to the UTC + 6.5h.
93An aircraft that took off from the EPWA airport with heading 300 degrees, flying in windless conditions according to the rhumb line. Where will the aircraft fly to:
- AFlying on a spiral it will move towards the North Pole attempting to reach it.
- BFollowing the heading of 300 degrees it will be running along the latitude and return to the place of departure.
- CCorrecting the heading, it will reach the place of departure.
- DIt will follow the meridian towards the South Pole.
94Tuning up the on-board VOR/DME set is followed by:
- AAdjustment of VOR frequency.
- BSetting the current QFE pressure.
- CSelecting the DME channel.
- DNone of the above.
95 When an aircraft is flying over the Northern Hemisphere heading East and accelerates, the acceleration error will cause the compass:
- ATo indicate a turn towards North.
- BTo indicate the heading of 090.
- CTo indicate a turn towards South.
- DTo slow down the indicated turning speed.
96 When an aircraft is flying over the Northern Hemisphere heading West and accelerates, the acceleration error will cause the compass:
- ATo indicate a turn towards North.
- BTo indicate the heading of 270.
- CTo indicate a turn towards South.
- DTo slow down the indicated turning speed.
97 The main reason for installing the magnetic field detector of the magnetic compass on the wing tip is:
- ALocating the device in a place without any electrical circuitry causing deviations.
- BFacilitating the access to the devices and increasing the susceptibility to the influence of Earth's magnetic field.
- CPlacing the device in a position where it would not be damaged in the event of a lightning strike.
- DNone of above.
98 How many centimeters on the map scaled 1: 10,000 has a section corresponding to a distance of 2 km of the area:
- A20 cm
- B40 cm
- C5 cm
- D10.5 cm
99What speed do we see on the DME indicator?
- AGround speed(GS).
- BIndicated airspeed (IAS).
- CTrue airspeed (TAS).
- DMach number.
100What frequencies does the VOR system use?
- A108.00-117.95 MHz
- B107.95-117.95 MHz
- C108.00-117.00 kHz
- D112.05-118.00 MHz
101What will be the DME indication in the cockpit at the time of flight of the aircraft directly over the VOR/DME beacon?
- AIndication equal to the altitude of the flight.
- B0 (zero).
- CThere will be no indication, because the aircraft will be in the cone of confusion of device.
- DNone of the above.
102One nautical mile [1 NM] is (in round figures):
- A6000 ft
- B5000 ft
- C4500 ft
- D8000 ft
103One hPa of pressure change on ground level corresponds to the change of altitude by approximately:
- A30 ft
- B40 ft
- C10 ft
- D50 ft
104The angle between the heading of the aircraft and its relative direction towards Earth is called:
- ADrift angle.
- BAngle track error.
- CAngular complementary correction.
- DWind angle.
105The angle between the longitudinal axis of the plane and the direction towards the NDB beacon is:
- ARelative bearing.
- BQDR
- CQDM
- DQFE
106 Angle between the longitudinal axis of the aircraft and the desired track is:
- ADrift angle.
- BWind angle.
- CTrack.
- DRadial.
107The angle between the northern direction of the magnetic meridian passing through the NDB and the direction towards the airplane is:
- AQDR
- BQDM
- CRadial
- DQFE
108The angle between the northern direction of the magnetic meridian passing through the airplane and the direction towards the NDB is:
- AQDM
- BQDR
- CRadial
- DQFE
109 Mach number is the ratio:
- ATAS to the speed of sound at the given altitude.
- BIAS to the speed of sound at the given altitude.
- CThe speed of sound at the given altitude to IAS.
- DThe speed of sound at the given altitude to TAS.
110The number of possible transponder codes is:
- A4096
- B10 000
- C9999
- D7700
111Given the following data: the airport elevation is 1,000 ft and QNH = 988 hPa, determine the current pressure altitude of the airport (assuming that 1 hPa = 27 ft):
- A320 ft
- B1680 ft
- C- 320 ft
- D680 ft
112 The Earth model for the GPS system is:
- AWGS84.
- BWGPS.
- CGPS84.
- DNAVSTAR.
113 On the aeronautical chart scaled 1: 10,000 2 cm section corresponds to the actual ground distance of:
- A200 m
- B50 m
- C100 m
- D20 m
114On the aeronautical chart scaled 1: 500,000 a 10.8 cm section was covered within a 20 minute flight. The ground speed of the flight was:
- A162 km/h
- B200 MPH
- C162 kts
- D200 km/h
115 On the map scaled 1: 10,000 a 20 cm section corresponds to the actual ground distance of:
- A2 km
- B5 km
- C10 km
- D20 km
116DME distance indicator provides the following distance from the ground station:
- ADiagonal.
- BVertical.
- CHorizontal.
- DNone of above.
117On VOR indicator full CDI deflection indicates at least … degrees from preselected radial:
- A10
- B5
- C2
- D12
118VOR transmitters are oriented towards:
- AMagnetic North.
- BTrue North.
- CCompass North.
- DNone of above.
119The most precise measurement of GS is possible with the use of:
- ADME station situated on the flight route.
- BVOR station located across the flight route.
- CDME stations located across the flight route.
- DNDB beacon located on the flight route.
120 In windless conditions at 0830UTC Pilot read radial = 315 degrees. Continuing flight with true track heading = 180 degrees at 0840UTC he reads radial = 270 degrees. Assuming his ground speed is 240 kt, calculate distance to NDB at 0840 UTC:
- A40 NM
- B32 NM
- C48 NM
- D38 NM
121The volume of 20 US gallons is an equivalent of:
- A76 L
- B92 L
- C20 L
- D53 L
122The volume of 27 US gallons is an equivalent of:
- A102 L
- B92 L
- C15 L
- D53 L
123The volume of 34 L replies:
- A9 US gal
- B12 US gal
- C18 US gal
- D13 US gal
124The volume of 65 L is an equivalent of:
- A17 US gal.
- B12 US gal.
- C20 US gal.
- D13 US gal.
125 DME receiver provides data in:
- ANM, kt, min
- Bkm, km/h, min
- CDepending on the setting.
- DNone of above.
126 DME distance readout in the aircraft at FL120 flying vertically above the VOR/DME (MSL) station will be:
- AApprox. 2 NM.
- BNot more than 1 NM.
- CDepends on the type of transmitter DME, but never more than 1.2 NM.
- D0 NM (+-0.1 NM).
127 Regarding the radar, it is true that:
- AThe primary radar operates on the principle of reflecting electromagnetic waves from the plane, the secondary is based on the response of the on-board transponder.
- BOnly primary radar is installed in aircraft, ground stations exclusively secondary radar systems.
- CThe primary radar is always less accurate than the secondary radar.
- DOnly secondary radars are installed on aircraft.
128Pilot activates IDENT mode on the transponder:
- AAt the order of the radar controller.
- BWhen switching the radio frequency.
- CDuring a radio communication.
- DAlways after setting a new code (squawk).
129The pilot plans to fly from the aerodrome in Jelenia Gora (N50° 53'57.8" E015° 47' 7.8") to the aerodrome in Zamosc (N50° 42"6.5" E023° 12' 15.3") and land before sunset. During the navigational preparation for the flight the pilot takes into consideration:
- ASunsets in Zamosc approx. 30 minutes earlier.
- BThat the Sun sets in Zamosc approx. 1 hour earlier.
- CThat the Sun sets at the same time over the departure and arrival airport .
- DThat the Sun sets in Zamosc approx. 30 minutes later.
130 The pilot plans to fly from the aerodrome in Zamosc (N50° 42' 6.5" E023° 12' 15.3") to the aerodrome in Jelenia Góra (N50° 53' 57.8" E015° 47' 7.8") and to land before sunset. During the navigational preparation for the flight the pilot takes into consideration:
- AThat the Sun sets in Jelenia Góra 30 minutes later.
- BThat the Sun sets in Jelenia Gora approximately 1 hour earlier.
- CThat the Sun sets at the same time over the departure and arrival airport.
- DThat the Sun sets in Jelenia Góra approx. 30 minutes earlier.
131Prior to take-off the pilot received from TWR the following information about the wind at the Earth surface level: 260 degrees/34kt. What is the transverse wind velocity component for runway 30?
- A23 kt
- B17 kt
- C29 kt
- D34 kt
132The ground speed of the aircraft is 90 knots. In 18 minutes the aircraft will cover the distance of:
- A27 NM
- B18 NM
- C33 NM
- D45 NM
133TAS (True Air Speed) and wind speed is:
- AGround speed (GS).
- BMach number.
- CIndicated air speed (IAS).
- DCalibrated air speed (CAS).
134 Before landing the pilot received the following information from TWR on the wind at the ground level: 260 /34kt. What is crosswind velocity component for runway 22?
- A23 kt
- B17 kt
- C29 kt
- D21 kt
135Assuming that the magnetic CRS course from LDZ to JED is 159° and from JED to LDZ 339 °, the aircraft that flew in the direction from LDZ to JED in windless conditions is:
- AAt the 159 ° radial from the VOR LDZ, heading 159 °.
- BAt the radial of 339° from the VOR LDZ, heading 159°.
- CAt the radial of 159° VOR LDZ, heading 339°.
- DNone of above.
136Assuming that the magnetic CRS course from RUDKA to SIE is 233° and from SIE to RUDKA 053°, then the aircraft passing through RUDKA heading towards SIE in windless conditions is flying:
- AWith the heading 233°, magnetic CRS course 233°, at the radial of 053° from VOR SIE.
- BWith the heading 233°, magnetic CRS course 053°, at the radial of 053° VOR SIE.
- CWith the heading 233°, magnetic CRS course 233°, at the radial of 233° from a VOR SIE.
- DNone of above.
137The point with the following coordinates; 120° 45'N, 23° 15'E is located in the quarter:
- ANE
- BSE
- CSW
- DNW
138 The point with the following coordinates: 120° 45'W, 23° 15'N is located in the quarter:
- ANW
- BNE
- CSW
- DSE
139 The point with the following coordinates: 120° 45'E; 23° 15'S is located in the quarter:
- ASE
- BNE
- CSW
- DNW
140 The point with the following coordinates: 120° 45'S; 23° 15'W is located in the quarter:
- ASW
- BNE
- CSE
- DNW
141The distance between points A and B is 600 m. On the map this section has a length of 6 cm. What is the scale of this map?
- A1 : 10 000
- B1 : 150 000
- C1 : 20 000
- D1 : 100 000
142The primary radar operates mostly on the basis of:
- APulse technique.
- BPhase comparison.
- CInterrogating transponder.
- DContinuous carrier wave.
143 Radial in Q code is designated as:
- AQDR
- BQDM
- CQUJ
- DQTE
144 ADF can receive frequencies in the range:
- AFrom 150 kHz to 1800 kHz.
- BFrom 200 kHz to 600 kHz.
- CFrom 188 MHz to 413 MHz.
- DAbove 500 MHz.
145NDB beacon emits radio waves:
- ANon-directionally.
- BIn certain sectors
- CDirectionally.
- DEvery 10 degrees.
146GPS system beacons are:
- AGPS satellites
- BGPS receivers.
- CControl stations.
- DVHF stations.
147 NDB beacons operate in the frequency band:
- A200-1750 kHz
- B200-1750 MHz
- C200-600 kHz
- D200-800 kHz
148VDF direction finder is located on:
- AThe ground.
- BThe aircraft.
- CGPS satellite
- DNone of the above.
149VDF direction finders operate on frequencies:
- A130 MHz i 122.7 MHz
- BFrom 108 MHz to 136.975 MHz.
- CFrom 88 MHz to 108 MHz
- DAbove 140 MHz.
150After flying for 20 NM the airplane is 2 NM to the right of the planned route. By what value must the airplane correct its heading in order to reach the planned route after another 20 NM?
- A12 degrees to the left
- B6 degrees to the right
- C12 degrees to the right
- D20 degrees to the left
151After flying for 25 km the airplane is 5 km to the left of the planned route. By what value must the airplane correct its heading in order to reach the planned route after another 25 km?
- A25 degrees to the right
- B5 degrees to the left
- C12 degrees to the right
- D15 degrees to the left
152 After flying for 30 km the airplane is 4 km to the left of the planned route. By what value must the airplane correct its heading in order to reach the planned route after another 30 km?
- A16 degrees to the right;
- B13 degrees to the left;
- C12 degrees to the right;
- D8 degrees to the left;
153After flying for 40 NM the airplane 2 NM to the right of the planned route. By what value must the airplane correct its heading in order to reach the planned route after another 40 NM?
- A6 degrees to the left'
- B3 degrees to the right.
- C12 degrees to the right;
- D9 degrees to the left;
154The airplane flies passively in the direction of the beacon (maintaining radial = 0). If the magnetic heading of the airplane decreases, then the airplane:
- AIs drifting to the right.
- BIs drifting to the left.
- CIs under influence of western wind.
- DThe drift angle is 0°.
155 The abbreviation "RVR" means:
- ARunway visual range - the visibility on the runway
- BRadar vectors Requested - please radar vectoring.
- CRunway visibility report - a report runway visibility
- DRecleared via route ... - a new permit to fly a different route.
156 The abbreviation "SSR" means:
- ASecondary surveillance radar .
- BSearch and surveillance radar.
- CSurface strength of runway.
- DStandard Snow report - a standard report on precipitation and snow accumulations.
157DME station is situated at an altitude of 1000 ft AMSL. QNH = 1013.25 hPa. The aircraft flies at FL370, 15 NM DME from the station. DME readout will be:
- A16 NM
- B15 NM
- C18 NM
- D37 NM
158An aircraft flying in a windless conditions with the heading 320 crosses the 195 radial from the VOR JED. The aircraft will be:
- ATo the west of the VOR-a JED.
- BTo the east of the VOR-a JED.
- COver the VOR-em JED.
- DNone of above.
159The aircraft flies with the heading of 330 degrees in windless conditions and crosses the 120 radial from the VOR / DME LIN within 30 NM from DME. The aircraft will be flying:
- AOn the eastern side of the VOR / DME LIN.
- BOn the west side of the VOR / DME LIN.
- CExactly the VOR / DME LIN.
- DNone of the above.
160The aircraft plans to descent at a constant GS. Within 5 minutes the pilot plans to descend from FL 100 to FL050. What should be the descent rate on the VSI?
- A1000 ft/min
- B2000 ft/min
- C1500 ft/min
- D500 ft/min
161The aircraft is moving at a speed of 120 km/h. Wind speed is 30 km/h. The maximum value of drift angle in these conditions is:
- A15°
- B12°
- C30°
- D40°
162The aircraft is moving at a speed of 150 km/h. Wind speed is 30 km/h. The maximum value of the drift angle in these conditions is:
- A12°
- B15°
- C30°
- D40°
163The aircraft is moving at a ground speed of 150 km / h. In 14 minutes it will cover the distance of:
- A35 km
- B14 km
- C27 km
- D45 km
164The aircraft is moving at a ground speed of 180 km/h. In 18 minutes it will cover the distance of:
- A54 km
- B36 km
- C18 km
- D68 km
165The aircraft takes off from the airport located at 1500 ft MSL and climbs vertically at a speed of 600 ft / min. Its average GS is 90 knots and the pressure = 1013.2 hPa QNH. How far from the airport will FL 75 be reached?
- A15 NM
- B18 NM
- C20 NM
- D12 NM
166 The aircraft takes off from the airport elevation 500 ft MSL and rises vertically at a speed of 500 ft / min. Its average cruising speed of 100 knots, and the pressure = 1013.2 hPa QNH. How far from the airport FL 80 is reached?
- A25 NM
- B18 NM
- C21 NM
- D12.5 NM
167The aircraft maintains the magnetic heading of 060 degrees. The declination is 8°W, the drift angle is +4°. What is the true track heading of the aircraft?
- A72
- B56
- C64
- D48
168The GPS system operates in the band ... on the basis of:
- AUHF, measuring the reception delay (distance) on the receiver - satellite path.
- BSHF, similar to the secondary surveillance radar, i.e. query-response.
- CSHF, measuring the distance to a minimum of 24 satellites.
- DHF, information on the distance to at least 4 satellites.
169The average GS of the aircraft is 150 km/h. In 18 minutes it will fly the distance of:
- A45 km
- B18 km
- C27 km
- D35 km
170 Sunrise and sunset tables in AIP Poland are provided in chapter
- AGEN
- BENR
- CAD
- DRAC
171The on-board device cooperating with the NDB beacon is:
- AADF
- BMW station
- CVHF direction finder
- DTransponder
172The on-board device cooperating with VDF direction finder is:
- AVHF communication radio.
- BSecondary surveillance radar.
- CDME radio range-finder.
- DADF.
173VOR is radionavigation system:
- AAngular.
- BDistance - anglular.
- CDistance.
- DHyperbolic.
174VOR provides the bearing angle for the beacon:
- ARelative to the magnetic meridian of the airplane.
- BRelative to the longitudinal axis of the aircraft.
- CRelative to the airplane meridian.
- DRelative to the compass meridian.
175What is the use of the squawk IDENT?
- AAs an impulse for identifying aircraft.
- BAs a code alarm pulse.
- CAs an pulse suppressing interference.
- DNone of above.
176In what mode is the altitude query sent?
- A"C" mode.
- B"3/A" mode.
- C"D" mode.
- D"B" mode.
177In case where the transmitter and receiver move relative to each other (relative motion) there occurs a phenomenon of:
- AThe change in frequency proportional to the velocity in relative motion.
- BInterference, allowing the measurement of speed.
- CThe dispersion - the changing audible communication.
- DThe change in frequency inversely proportional to the velocity in relative motion.
178The standard pressure value is:
- A760 mmHg
- B750 mmHg
- C1000 mmHg
- D1013 mmHg
179The pressure standard is:
- A1014 hPa
- B760 hPa
- C1000 hPa
- D750 hPa
180The cooperation between the on-board DME with the ground beacons requires:
- ATwo radio frequencies.
- BOne radio frequency.
- CThree frequencies.
- DFour radio frequencies.
181Assuming that air is incompressible and the location of pressure transmitters on the airplane cause no errors in speedometer indication, TAS is equal to:
- AIAS in windless conditions.
- BIAS corrected with the air density correction.
- CGround speed (GS), taking into account the impact of the wind.
- DMach number (Ma).
182The frequency range of the DME radio range-finder is:
- AFrom 960 MHz to 1215 MHz.
- BFrom 118.0 MHz to 137.9 MHz.
- CFrom 500 MHz to 1.8 GHz.
- DFrom 112 MHz to 117.900 MHz.
183Range, from which you can receive signals from a ground station NDB is:
- AHigher over the sea than over land.
- BLower over the sea than over land.
- CThe same over sea and land.
- DNone of above.
184Breaking of the wave on the shore (sea/land):
- ACan be minimized by taking bearings on the stations, whose signal crosses the coast at right angle when reaching the receiver.
- BOccurs only at the time of sunrise and sunset.
- CCan be minimized by taking bearings on the stations located as far inland as possible.
- DOccurs mainly at night.
185 The descent is planned from the altitude of 7,000 ft so as to reach 1,000 ft AMSL within 6 NM away from the VOR / DME. GS is 180kt and the rate of descent is 1,000ft/min. The distance from the station at the start of descent is:
- A24 NM
- B18 NM
- C60 NM
- D13 NM
186Time source in the GPS are:
- ASatellite's own atomic clocks.
- BDCF-77 radio station in Frankfurt.
- CThe internal quartz clock of the receiver.
- DNone of above.
Informationen
- Beschreibung
- Passed Exams Quiz am Navigation, erstellt von Roman Eidia am 20/08/2018.
- Autor
- Roman Eidia
- Sprache
- English
- Aufrufe
- 61
- Schlagwörter
- Bewertung
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