PHYS 200 Unit 10: Rotational Motion and Angular Momentum

Question	Answer
uniform circular motion	-motion with constant angular velocity -ω = Δθ / Δt
angular acceleration	-rate of change of angular velocity with time -α = Δω / Δt
linear/tangential acceleration	-acceleration in direction tangent to circle at point of interest in circular motion -a_t = Δv / Δt
linear and angular displacement	-x = θr -θ = x/r
linear and angular velocity	-v = rω -ω = v/r
tangential and angular acceleration	-a_t = rα -α = a_t/r
Rotational Kinematic Equations	-θ = ωt -ω = ω_0 + αt -θ = ω_0t + 1/2 αt^2 -ω^2 = ω_0^2 + αθ
moment of inertia	-mass times the square of perpendicular distance from the rotation axis -I = mr^2 (particle)
moment arm	perpendicular distance to axis of rotation
torque, angular acceleration, and moment of inertia	- τ = (m^2 r)α -net τ = Iα
force and angular acceleration	-F = mrα
rotational kinetic energy	-KE_rot = 1/2 I ω^2
mechanical energy with rotational motion	1/2 m v_1^2 + 1/2 I ω^2 + mgh_1 = 1/2 m v_2^2 + 1/2 I ω_0^2 + mgh_2
Work-Energy Theorem with Rotational Motion	net W = 1/2 I ω^2 - 1/2 I ω_0^2
angular momentum	L = I ω
torque and angular momentum	net τ = ΔL / Δt
law of conservation of angular momentum	-L = constant -L = L'

Resource summary

	Created by Adriana Vincelli-Joma about 3 years ago