Changing the way you learn

Question	Answer
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\begin{array}{*{20}c} {\sin{(x-y)} =}\\ \end{array}	\begin{array}{*{20}c} {\sin{x}\cdot\cos{y}-\cos{x}\cdot\sin{y}}\\ \end{array}
\begin{array}{*{20}c} {\cos{(x-y)} =}\\ \end{array}	\begin{array}{*{20}c} { \cos{x}\cdot\cos{y}+\sin{x}\cdot\sin{y}}\\ \end{array}
\begin{array}{*{20}c} {\tan{(x+y)} =}\\ \end{array}	\begin{array}{*{20}c} {\frac{\tan{x}+\tan{y}}{1-\tan{x}\cdot\tan{y}}}\\ \end{array}
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Image: Afbeelding1 (binary/octet-stream)	Image: Afbeelding2 (binary/octet-stream)

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