34785842
Description
Flashcards by Malachy Moran-Tun, updated more than 1 year ago
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Created by Malachy Moran-Tun
over 2 years ago
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| Question | Answer |
| What's the Benefit of Simplifying Boolean Expressions? | > Uses less components > More reliable > Faster > Generates less heat > Cheaper |
| *sigh*... What are the General Rules of Boolean Algebra? (8 of them) | 1. X ∧ 0 = 0 2. X ∧ 1 = 1 3. X ∧ X = X 4. X ∧ ¬X = 0 5. X ∨ 0 = X 6. X ∨ 1 = 1 7. X ∨ X = X 8. X ∨ ¬1 = 1 |
| What are the Commutative Rules of Boolean Algebra? (yes they are REALLY obvious) | 1. X ∧ Y = Y ∧ X 2. X ∨ Y = Y ∨ X |
| What are the Associative Rules of Boolean Algebra? | 1. X ∧ (Y ∧ Z) = (X ∧ Y) ∧ Z 2. X ∨ (Y ∨ Z) = (X ∨ Y) ∨ Z |
| What are the Distributive Rules of Boolean Algebra? (yes they're really damn long) | 1. (X ∧ Y) ∨ (X ∧ Z) = X ∧ (Y ∨ Z) 2. oh god... (X ∨ Y) ∧ (W ∨ Z) = (X ∧ W) ∨ (X ∧ Z) ∨ (Y ∧ W) ∨ (Y ∧ Z) :( |
| What are the Absorption Rules of Boolean Algebra? | 1. X ∨ (X ∧ Y) = X 2. X ∧ (X ∨ Y) = X |
| What is the Extremely Obvious, Hopefully Logically Oblivious, Extraordinarily Clear Double Negation Rule of Boolean Algebra? | 1. X = ¬¬X |
| What are de Morgan's Laws of Boolean Algebra? | 1. ¬(A ∧ B) = ¬A ∨ ¬B 2. ¬(A ∨ B) = ¬A ∧ ¬B |
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