Changing the way you learn

Question	Answer
Standard Form	$Ax+By=C$
Slope	M= $\frac{y_2-y_1}{x_2-x_1}$
Slope-Intercept Form	$y=mx+b$
Point-Slope Form	$y-y_1=m(x-x_1)$
Distance on a Number Line	D= $\|a-b\|$
Distance on a Coordinate Plane	D= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
Distance in Space (3D)	D= $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$
Distance Arc Length	L= $\frac{N}{360}·2\pi·r$
Midpoint on a Number Line	M= $\frac{a+b}{2}$
Midpoint on a Coordinate Plane	M= $\frac{x_1+x_2}{2},$ $\frac{y_1+y_2}{2}$
Midpoint in Space (3D)	M= $\frac{x_1+x_2}{2},$ $\frac{y_1+y_2}{2},$ $\frac{z_1+z_2}{2}$
Perimeter of a Square	P= $4s$ (s=side)
Perimeter of a Rectangle	P= $2l+2w$ (l=length, w=width)
Circumference of a Circle	C= $2\pi·r,\pi·d$
Area of a Square	A= $s^2, lw$
Area of a Rectangle	A= $lw, bh$
Area of a Parallelogram	A= $bh$
Area of a Trapezoid	A= $\frac{1}{2}h(b_1+b_2)$
Area of Rhombus	A= $\frac{1}{2}d_1d_2, bh$
Area of Triangle	A= $\frac{1}{2}bh$
Area of Regular Polygon	A= $\frac{1}{2}Pa$
Area of a Circle	A= $\pi·r^2$
Area of Sector of a Circle	A= $\frac{N}{360}\·pi·r^2$
Quadratic Formula	$\frac{-b±√b^2-4ac}{2a}$
Lateral Surface Area of Prism	L= $Ph$
Lateral Surface Area of a Cylinder	L= $2\pi·r·h$
Lateral Surface Area of a Pyramid	L= $\frac{1}{2}Pl$
Lateral Surface Area of a Cone	L= $\pi·r·l$
Total Surface Area of a Sphere	SA= $4\pi·r^2$
Total Surface Area of a Hemisphere	SA= $3\pi·r^2$
Volume of a Pyramid	V= $\frac{1}{3}Bh$
Volume of a Rectangular Prism	V= $Bh$
Volume of a Right Circular Cylinder	V= $2\pi·r^2+2\pi·r·h$
Volume of a Right Circular Cone	V= $\frac{1}{3}·pi·r^2·h$
Volume of a Sphere	SA= $\frac{3}{4}·pi·r^3$
Surface Area of a Regular Prism or Cylinder (2-based)	SA= $Ph+2B$ *If you are finding the surface area of a cylinder, replace P (perimiter) with Circumfrance.
Surface Area of a Regular Pyramid or Cone (1-based)	A= $\frac{1}{2}Pl+B$ If you are finding the surface area of a cone, replace P (perimiter) with Circumfrance *l= slanted height
Pythagorean Theorem	$a^2+b^2=c^2$
Image: right_triangle.JPG (image/JPG)	$\sin A=$ $\frac{a}{c}$
Image: right_triangle.JPG (image/JPG)	$\cos A=$ $\frac{b}{c}$
Image: right_triangle.JPG (image/JPG)	$\tan A=$ $\frac{a}{b}$
Sum of Degree Measures of the Interior Angles of a Polygon	$180(n-2)$ (n=number of sides)
Degree Measure of an Interior Angle of a Regular Polygon	$\frac{180(n-2)}{n}$
⊥	is perpendicular to
\|\|	is parallel to
≅	is congruent to
∼	is similar to
≈	is approximately equal to
∆ABC	triangle ABC
∠ABC	angle ABC
m∠ABC	the degree measure of angle ABC
Circle O	circle with center point O

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	Created by Selam H over 11 years ago