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Created by Tech Wilkinson
over 11 years ago
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Question | Answer |
f(x)=sinkx | f′(x)=kcoskx |
f(x)=coskx | f′(x)=−ksinkx |
f(x)=tankx | f′(x)=ksec2kx |
∫coskxdx | 1ksinkx+c |
∫sinkxdx | −1kcoskx+c |
∫f′(g(x))g′(x)dx | f(g(x))+c |
|xi+yj+zk| | √x2+y2+z2 |
(ai+bj+ck)∗(xi+yj+zk) | ax+by+cz |
a*b | |a|∗|b|cosθ |
Equation of line through a parallel to b | r=a+tb |
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