6998114
Description
Created by Maxim Korvatskyy
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Created by Maxim Korvatskyy
almost 10 years ago
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| Question | Answer |
| temporary | temporary2 |
| V = U+at u=initial, v=final, s=distance, a=accel., t=sec. | S = (V^2 - U^2) /2a u=initial, v=final, s=distance, a=accel., t=sec. |
| s = ut +½at^2 u=initial, v=final, s=distance, a=accel., t=sec. | o s = vt - ½at^2 u=initial, v=final, s=distance, a=accel., t=sec. |
| It's easier to look at particles on a slope, by tilting the slope image to look like flat ground (Gravity force will seem to be acting at an angle in some direction) | R= result force upwards R= sum of all downwards --sum of all upwards. |
| momentum = mass x velocity | F=ma m=mass, a=acceleration |
| Impulse = mu-mv u=initial, v=final, m=mass | Impulse = force x time |
| Fmax = µR µ = friction (0 < X < 1) R= result force upwards R= sum of all downwards - sum of all upwards. | when mass is given in Kilograms 78kg, force is found 9.8N per kg 78 x 9.8 often written as (78G) (78 Gravity) |
| S= t/2 x (v-u) | G (gravity) 9.81 |
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