preparar 250 mL de solución de NaOH 0,3 mol/L

Description

cálculo de masa de soluto a partir de au molaridad
paula rey
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paula rey
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Resource summary

preparar 250 mL de solución de NaOH 0,3 mol/L
  1. ¿ QUÉ MASA DE NaOH NECESITO?
    1. 1 mol de NaOH = 40 g
      1. 0,3 mol = ?
        1. ( 0,3 mol x 40g ) / 1 = 12 g de NaOH
          1. masa de soluto en 1 litro de solución
            1. para 0,25L se necesitan 3 g
      2. M = n/V
        1. MxV =n
          1. n= m /masa molar
            1. despejo m
              1. 0,075 mol x 40 g/mol = 3g
            2. 0,3 mol/L x 0,25mL= 0,075 mol
        2. prof. Paula Rey
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