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991105
preparar 250 mL de solución de NaOH 0,3 mol/L
Description
cálculo de masa de soluto a partir de au molaridad
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paula rey
, updated more than 1 year ago
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Created by
paula rey
over 10 years ago
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Resource summary
preparar 250 mL de solución de NaOH 0,3 mol/L
¿ QUÉ MASA DE NaOH NECESITO?
1 mol de NaOH = 40 g
0,3 mol = ?
( 0,3 mol x 40g ) / 1 = 12 g de NaOH
masa de soluto en 1 litro de solución
para 0,25L se necesitan 3 g
M = n/V
MxV =n
n= m /masa molar
despejo m
0,075 mol x 40 g/mol = 3g
0,3 mol/L x 0,25mL= 0,075 mol
prof. Paula Rey
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