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Percentages

John Doaks 4 questions

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Questions in this quiz (4)

  1. 1How would you set up the equation to solve the following problem:

    If M% of 135 is 54, then M = ?
    1. AM/54 = 100/135
    2. BM/100 = 54/135
    3. CM/135 = 54/100
    4. DM/100 = 135/54
  2. 2Which equation would you choose to solve the following problem:

    At a car show, exactly 1,148 of the 3,280 cars on display are convertibles. What percentage of the cars are not convertibles?
    1. Ax/100 = 2,132 / 3,280
    2. B1,148/100 = x / 3,280
    3. Cx/100 = 1,148 / 3,280
  3. 3Solve the following problem:

    If 80% of x + 1 is 2, then x =?
    1. A2
    2. B1
    3. C2.5
    4. D1.5
  4. 4Solve the following sample problem:

    A poll of 400 registered voters was taken for the election for the sheriff of Oaktown. 80 voters planned to vote for Humphreys, while 140 voters planned to vote for Jones. How would you set up the equation to find the percentage of voters planning to vote for Jones?
    1. A140/400 = p/100
    2. B80/140 = p/400
    3. C80/400 = p/100

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Description
Quiz on Percentages, created by John Doaks on 23/02/2017.
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English
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