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Chemistry exam

Brianna Kolman English 10 cards

Chemistry exam

Cards in this deck (10)

  1. 1Define solvent and soluteSolvent: The major component of the mixture, which provides stabilizing interactions.
    Solute: The minor Component Of The mixture, which is “dissolved” in the solvent.
  2. 2Define solutionA homogeneous mixture, where a solute is dissolved in a solvent.
    - Solutions aren’t always necessarily made by dissolving a solid in a liquid
  3. 3Define homogenousHomogenous: the components that make up the mixture are uniformly distributed throughout the mixture.
  4. 4Define saturated and supersaturated solutionSaturated Solution: A saturated solution is a solution which is in equilibrium with respect to dissolution and recrystallization of a given solute substance.
    - In dynamic equilibrium
    Supersaturation: A solution that contains more dissolved substance per litre than a saturated solution (i.e. not at equilibrium, but “metastable”)
    - Disturbing the system (adding seed crystal or crystallizing surface) usually results in precipitation (formation of solid from a liquid solution).
    - Crystallization is spontaneous, but there is an “activation energy barrier” to that happening
    - The System Is Kinetically Stable, but thermodynamically unstable.
  5. 5Define dilute and concentrated solutionDilute solution: containing small quantities of solute relative to the amount of solvent
    Concentrated solution: containing large quantities of solute relative to the amount of solvent
  6. 6Define molarity and how to calculateMolarity (M): moles of solute per liter of solution (simple solvent term, but volume of solvent isT dependent) - moles/L
    M = moles solute / litres of solution
    Define molarity and how to calculate
  7. 7Define molality and how to calculate- Molality (m): moles of solute per kilogram of solvent (removes change in volume with temperature effect) - moles/kg
    m = moles solute / mass of solvent
    Define molality and how to calculate
  8. 8Define and calculate mass percentMass Percent: mass of solute per mass of solution x 100% (simple, but no mole mole relations for solutes) - (g/g) x100%
    mass % = mass of solute / mass of solution
  9. 9Define and calculate Mole fraction and mole percentMole Fraction (xA): moles of A per total moles in solution (more calculations, but preserves mole mole relations) - moles/moles
    Mole percent (xAx100%): same as mole fraction, but easier to read
    xA = moles of solute A / moles of solution
  10. 10Define and calculate modified mass fractionDefine and calculate modified mass fraction

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Flashcards on Chemistry exam , created by Brianna Kolman on 15/12/2021.
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Brianna Kolman
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