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MCDB 101B: Midterm 2 (Lec 11-19)

Phil Nosrat English 37 cards

Cards in this deck (37)

  1. 1Mendel's Laws violations1) The principle of segregation
    Each member of a gene pair (allele) is equally likely to be found in a gamete
    2) The principle of independent assortment In the formation of gametes, segregation of any pair of alleles is independent of the segregation of other pairs of alleles
    -Linkage is violation of #2
  2. 2Closely-linkedNO CROSSING OVER
    (no indep assortment (violate 2nd law))
    Same gametes as parental
  3. 3Completely unlinkedObeys 2nd law
    equal distribution of ALL gametes
    on different chrom or sufficiently far apart on same chrome so at least one crossover occurs between them in every meiosis
  4. 4Partially linked what causes it?parental gametes are more frequent
    recombinant less frequent than parental
    Caused by meiotic recombination during meiosis 1 (2 genes on same chrom)
    violates 2nd, not 1st law
  5. 5RecombinationCrossing over between chromosomes during meiosis I produces recombinant gametes
    Crossing over - exchange of DNA between chromosomes
    "cutting and pasting"
  6. 6Parental / recomb gametesparental - same as parents
    recomb - not present in parents, alleles swapped
  7. 7Calculate linkage X linked / autosomalanalyze gametes from dihybrid
    Cross true breeding P ==> F1 - dihybrid
    X-linked:
    cross dihybrid with male and examine male offspring
    M progeny - see X inherited from F
    If crossing over occurs, seen in M b/c get X from F
    M parental get doesn't matter b/c M offspring gets Y from M
    Autosomal:
    perform TESTCROSS with homoz recessive at both genes
  8. 8Syntenictwo genes on same chromosome
  9. 9Recombination FrequencyMeasure of distance between two genes
    RF = # recomb / total progeny
    Larger dist = higher chance of recombination during meiosis
    max = 50%
  10. 10Three point crossFaster, more accurate than two point cross for mapping genes
    make trihybrid
    x-linked: cross to male
    autosomal: testcross to homoz rec
  11. 11Three point cross steps1) determine parental gen by looking at parental progeny (most frequent)
    2) determine gene in middle by looking at DCO (which one changed from parental?)
    3) dist = DCO + SCO / total
    -for SCO, cross occurred btwn genes in which dist is being analyzed
    4) outside dist = SCO(1) + SCO(2) + 2*DCO / total
    *w/o correction RF doesn't include DCO
  12. 12Chromosomal interferenceOccurrence of one crossover reduces the likelihood of another crossover nearby
    (fewer DCOs than expected)
    Recomb in 1 blocks 2nd crossover
  13. 13Expected DCO FrequencyProb of crossover in Region 1 (RF 1) * Prob of crossover in Region 2 (RF 2)
  14. 14Coefficient of coincidenceobserved DCO frequency / expected DCO frequency
    CoC = 1 ==> equal
    = 0 ==> no observed DCOs
    expected = prob of crossover in region 1 * region 2
    observed = # DCO / total
  15. 15Interference1 - Coefficient of Coincidence
    Int = 0 ==> expected = observed
    Int = 1 ==> no DCOs
  16. 16Correspondence btw genetic and physical map exception?physical map = DNA seq
    unit of physical dist = DNA base pair
    Approximate linear relationship btw genetic distance (m.u.) and physical distance (bp) btwn any two genes
    EXCEPTION: recombination hotspots
  17. 17linkage groupgenes chained together by linkage relationships
    ex: chromosome
    human chrome - 270 mu
  18. 18Chi Square testsee if genes are linked/unlinked
    null hyp - obs and exp data are not different (possible genes are unlinked)
    alternate hyp - obs diff from exp (linked)
    x^2 = (obs-exp)^2 / exp
    **do this for each class and add for x^2
    df = n (# categories) - 1
    p value - probability that obs data arose by change under null hyp
  19. 19reject / can't reject nullp>0.05 ==> can't reject (possible unlinked)
    p<0.05 ==> reject null (linked)
  20. 20ratio of gametic types for chi squareif unlinked, parental = recomb, so all gametic types should be equal
  21. 21chi square value effect on p value?higher chi square # = lower p value
    (if same degrees of freedom)
  22. 22Lecture 13 Human Chromosomes and Organelle InheritanceX
  23. 23Karyotype def, how are they dividedStained and photographed preparation of METAPHASE chromosomes arranged according to size and position of centromeres
    Each chrome divided into two regions (arms) separated by centromere
    p - short arm (petit)
    q - long arm
  24. 24FISHfind locations of specific DNA seq on chromosomes
    Attach fluorescent tag to DNA probe that hybridizes to a specific sequence (probe compl to target seq)
    4 spots - undergoing mitosis and divided DNA
  25. 25Change in nucleotidessingle base pair substitution
    Frameshift mutation (insertion/deletion)
  26. 26Chromosome abnormalitieschange large sections of DNA (eg millions of nucleotides)
    whole genes, sections of chrom, or whole chromosomes are added, deleted, or moved
    ex: deletions, inversions, translations, duplications, extra chromosomes
  27. 27Relocation of genetic materialtranslocation
    (addn from another chrome)
    inversion
    (two sections switch around)
  28. 28Loss of genetic materialdeletion
    missing chromosome
  29. 29gain of genetic materialduplication
    extra chromosome
  30. 30recombination vs chromosomal rearrangementsboth involve cutting and rejoining of DNA
    Meiotic recomb - exchange homologous regions of homologous chromosomes
    -no loss/gain of DNA
    rearrangements - occur in meiosis or mitosis w/in or btwn any chrome
    -can lead to loss or gain or reordering of DNA
    -triggered by DNA damage
  31. 31gene mapping using deletion analysis1) deletion uncovers a recessive mutation
    2) deletions can be used to identify a gene's location
  32. 32Aneupolidyunbalanced set of chromosomes
    relative gene dosage upset
    (imbalance with one chromosome and all other chromosomes)
    monosomy-loss of a single chromosome copy
    trisomy-extra copy of one of the chromosomes
    pregnancy complications - Aneu in 1/2 cases of spontaneous abortions (miscarriage)
    trisomy 13, 18, 21 only viable. rest die
  33. 33euploidbalanced set of chromosomes (2n)
    normal
  34. 34nullisomymissing both chromosomes in homologous pair
  35. 35polyploidymore than two complete sets of chromosomes
    duplicated whole genome
    ex: Humans - 4n = 92 chromosomes
    tetraploid = four sets of chromosomes, 4n
    hexaploid = 6n
    not necessarily lethal because dosage is "balanced"
  36. 36Lec 16 Modern Experimental Geneticsx
  37. 37Loss of Function mutationmutant gene product hass less or no function
    hypomorphic - less function
    null mutation - no function

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Flashcards on MCDB 101B: Midterm 2 (Lec 11-19), created by Phil Nosrat on 15/02/2016.
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