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Strategy of Mathematical Proof :)

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Strategy of Mathematical Proof :)
Direct Proof
- • The most straightforward approach
- Description of each step
- Description of each step: 1. Identify p and q of the question. 2. Relate p and q using connective symbol 3. Solve the question using Direct proof outline
- 1. Identify p and q of the question.
- 2. Relate p and q using connective symbol
- 3. Solve the question using Direct proof outline
- 2. Relate p and q using connective symbol
- remarkably simple
- • Simple way to prove theorems or propositions that have the form of conditional statements.
- • To understand direct proof works, suppose we have some proposition in the form ;
- o Proposition If P, then Q.
- o This proposition is a conditional statement of form P=>Q. Our goal is to show that this conditional statement is true. To see how to proceed look at the truth table.
- o We must show that the condition of P being true forces Q to be true also, means the second line of the table cannot happen.
- o This proposition is a conditional statement of form P=>Q. Our goal is to show that this conditional statement is true. To see how to proceed look at the truth table.
- o Proposition If P, then Q.
- outline
Contradiction
- Assume that the statement we want to prove is false,
- then show that this assumption leads to nonsense
- We are then led to conclude that we were wrong to assume the statement was false
- so the statement must be true.
- We are then led to conclude that we were wrong to assume the statement was false
- BASIC IDEA
- then show that this assumption leads to nonsense
- The rules:
- p --> q is logically equivalent to ~p --> q
- ~(p --> q) is logically equivalent to p^ ~q
- p --> q is logically equivalent to ~p --> q
- Prove that if 7x + 9 is even, then x is odd by using the method of proof by contradiction
- Example
- Solution: Step 1: Write the statement in symbol Step 2: Use Proof by Contradiction outline to prove the statement
- If 7x + 9 is even, then x is odd
- 1. p : 7x + 9 is even
- q : x is odd
- ~q : x is even
- Suppose ~(p→q) = p^~q ( By using the rules )
- = If 7x + 9 is even, then x is even
- This contradict from what we assume which was 7x + 9 is even. So, If 7x + 9 is even, then x is a true statement.
- ∴Contradiction
- This contradict from what we assume which was 7x + 9 is even. So, If 7x + 9 is even, then x is a true statement.
- = If 7x + 9 is even, then x is even
- If 7x + 9 is even, then x is odd
- - It’s best to use proof by contradiction only when the direct and contrapositive approaches do not seem to work
- - A proof by contradiction can often have hidden in it a simpler contrapositive proof, and if this is the case it’s better to go with the simpler approach.
- Assume that the statement we want to prove is false,
Contrapositive Proof
- Imagine that you need to prove a proposition of the following form. Proposition If P, then Q.
- Our goal is to show that this conditional statement is true
- We knew that P -> Q is logically equivalent to ~Q-> ~P based on the truth table.
- Hence, we know that The expression to ~Q -> ~P is called the contrapositive form of P->Q.
- We knew that P -> Q is logically equivalent to ~Q-> ~P based on the truth table.
- Our goal is to show that this conditional statement is true
- Setup for contrapositive proof
- 1) first line of the proof is the sentence “Suppose Q is not true.”
- 2) The last line is the sentence “Therefore P is not true.”
- 3) Between the first and last line we use logic and definitions to transform the statement »Q to the statement » P
- Imagine that you need to prove a proposition of the following form. Proposition If P, then Q.
Mathematical Induction
- powerful proof technique
- used to proof a conjecture
- two steps' technique
- Fibonacci sequence
- Leonardo Pisano a.k.a. Fibonacci describe this sequence. The first two numbers are 1 and 1, and thereafter any entry is the sum of the previous two entries.
- Proposition: The Fibonacci sequence obeys F2n+1-Fn+1Fn-F2n=(-1)n. For all positive integer n element of Natural numbers, Ɐn Ꞓ N
- 1. Basis step: P(1): F21+1-F1+1F1-F21=(-1)1 1-1(1)-1=-1 proven
- 1. Basis step: P(1): F21+1-F1+1F1-F21=(-1)1 1-1(1)-1=-1 proven
- Proposition: The Fibonacci sequence obeys F2n+1-Fn+1Fn-F2n=(-1)n. For all positive integer n element of Natural numbers, Ɐn Ꞓ N
- appears with surprising frequency filled with mysterious patterns and hidden structures
- Leonardo Pisano a.k.a. Fibonacci describe this sequence. The first two numbers are 1 and 1, and thereafter any entry is the sum of the previous two entries.
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- Mind Map on Strategy of Mathematical Proof :), created by mckk4147a on 13/07/2016.
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