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Created by leonie.examtime
over 11 years ago
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Copied by ed.wilson89
over 11 years ago
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Moving source and moving observer
A bat emits ultrasonic waves with a frequency of 56 kHz, and the bat is travelling at 15m/s. If the bat is travelling towards a moth that is flying away at 5m/s, what frequency would the moth observe? Take the speed of sound in air to be 340 m/s.
Solution
Vo = 5m/s - use the minus sign because it's moving away from the source - smaller apparent frequency
Vs = 15 m/s - use minus because it's moving towards the observer - will create a bigger apparent frequency
f'=v±vov±vsf
f'=340−5340−1556 = 57.7 kHz
Example 3
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