Chapter 9

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Note on Chapter 9, created by trentm80 on 05/05/2014.
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Note by trentm80, updated more than 1 year ago
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I can- I.D/ graph quadratic functions in the form on y=ax²+ bx+c  *All quadratic functions have a domain of 0  Zero of a Function- the value (x,y) at which function crosses the x-axis      EX1         y=(x+2) (x-2)                      0= (x+2) (x-2)                      (x+2)=0   (x-2)=0                        x=-2        x=2                       (-2,0)      (2,0)              (evil)Axis of symmetry- vertical line that divides the parabola in half (always passes threw the vertex)           x= -b/29                  *Axis of symmetry tells middle x value to graph*     y= 2x²+16x-9     y= ax²+bx+c- get it in this form    x= -16/2(2)= -16/4= -4 

Significant points are: vertex (min/max)                                         y-intercept                                          x-inercept y=ax²+bx+c  y=x²-4                      x=-b/2a                    x= -(0)/ 2(1)=0 y=(0)²-4 y=-4                Step1- vertex: find the axis of               symmetry to get the x-term &               substitute back into the function for y                Step 2- x-intercept: sub in 0 for y                then factor your quadratic! solve each               factored term                Step 3- y-intercept: sub in 0 for x                (your c value)                     

9-2 quadratic functions

9-3 Graphing Quadratic Functions

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