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Flashcards

Arc length and Sector area

Doc Boff Maths AS level Inglês 10 flashcards

0.5 (8)^2 (0.430) = 13.76cm^2 20 - 13.76 = 6.24cm^2 (area) 8 x 0.430 = 3.44cm (length)

Flashcards do conjunto (10)

  1. 1Define 1 radianThe size of the angle formed at the centre of a circle by 2 radii which join the ends of an arc equal in length to the radius
  2. 2π^c (π radians) is equal to how many degrees?180 degrees
  3. 3How do we calculate arc length?l = rθ
  4. 4How do we calculate sector area?A = 0.5 r^2 θ
  5. 5What is the sine rule for angle / length?a/sinA = b/sinB = c/sinC
  6. 6What is the cosine rule?a^2 = b^2 + c^2 - 2bcCosA
    OR
    cosA = (b^2 + c^2 - a^2) / 2bc
  7. 7What is the sine rule for area?A = 0.5 ab sinC
  8. 8What is the area of a triangle?1/2 b x h
  9. 9—0.5 (8)^2 (0.430) = 13.76cm^2
    20 - 13.76 = 6.24cm^2 (area)
    8 x 0.430 = 3.44cm (length)
    0.5 (8)^2 (0.430) = 13.76cm^2 20 - 13.76 = 6.24cm^2 (area) 8 x 0.430 = 3.44cm (length)
  10. 10IMPORTANT NOTE:Ensure when working with trigonometric functions that your calculator is in radians when working with arc lengths and sector areas!

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Arc length and Sector area
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Doc Boff
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