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photoelectric effect

abbie Fitzpatrick 5 questions

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  1. 1if you shine [blank_start]electromagnetic[blank_end] waves, eg light, of a high [blank_start]frequency[blank_end] onto a surface of a metal, it will instantaneously [blank_start]eject[blank_end] [blank_start]electrons[blank_end]. for most metals, this frequency falls in the [blank_start]UV[blank_end] range.
    1. [blank_start]free elecrons[blank_end] on the surface of the metal [blank_start]absorb energy[blank_end] from the light.
    2. if an electron abo=sorbs enough [blank_start]energy[blank_end], the [blank_start]bonds[blank_end] holding it to the metal [blank_start]break[blank_end] and it is [blank_start]emitted[blank_end] from the surface.
    3. this is called the [blank_start]photoelectric effect[blank_end] and the electrons are called [blank_start]photoelectrons[blank_end].
    1. Aelectromagnetic
    2. Bfrequency
    3. Ceject
    4. Delectrons
    5. EUV
    6. Ffree elecrons
    7. Gabsorb energy
    8. Henergy
    9. Ibonds
    10. Jbreak
    11. Kemitted
    12. Lphotoelectric effect
    13. Mphotoelectrons
  2. 2to demonstrate the [blank_start]photoelectric effect[blank_end], we can use a [blank_start]gold-leaf electroscope[blank_end].
    1. the [blank_start]electroscope plate[blank_end], made of [blank_start]zinc[blank_end], is [blank_start]negatively[blank_end] charged, so the gold leaf is [blank_start]repelled[blank_end].
    2. the [blank_start]zinc plate[blank_end] is then exposed to [blank_start]ultraviolet light[blank_end] and the photoelectric effect causes its [blank_start]free[blank_end] electrons to be [blank_start]ejected[blank_end]. this causes it to [blank_start]lose[blank_end] it negative charge and so the gold leaf is no longer repelled and [blank_start]drops down[blank_end].
    1. Aphotoelectric effect
    2. Bphotoelectric
    3. Ceffects of uv
    4. Dgold-leaf experiment
    5. Egold-leaf electroscope
    6. Fgold-leaf
    7. Ggold-leaf electrospine
    8. Huv light source
    9. Ielectroscope plate
    10. Jplate
    11. Kelectroscopic plate
    12. Lelectroscope dish
    13. Mzinc
    14. Ncopper
    15. Oiron
    16. Pgold
    17. Qnegatively
    18. Rnot
    19. Sneutrally
    20. Tpositively
    21. Urepelled
    22. Vattracted
    23. Wrepulsed
    24. Xdrawn in
    25. Yzinc plate
    26. Zcopper plate
    27. AAiron plate
    28. ABgold plate
    29. ACultraviolet light
    30. ADultraviolet waves
    31. AEan EM light source
    32. AFa gold leaf
    33. AGfree
    34. AHmoving
    35. AIinternal
    36. AJexposed
    37. AKejected.
    38. ALrepelled .
    39. AMattracted .
    40. ANrepulsed .
    41. AOlose
    42. APgain
    43. AQrespond to
    44. ARmove
    45. ASdrops down
    46. ATfalls down
    47. AUloses its charge
    48. AVrepels itself
  3. 3no photoelectrons are emitted if the radiation has a frequency above a certain value called it threshold frequency.
    1. ATrue
    2. BFalse
  4. 4for a given metal, no [blank_start]photoelectrons[blank_end] are [blank_start]emitted[blank_end] if the [blank_start]radiation[blank_end] has a frequency [blank_start]below[blank_end] a certain value, this is called the [blank_start]threshold frequency[blank_end].
    the photoelectrons are emitted with a [blank_start]variety[blank_end] of [blank_start]kinetic energies[blank_end] ranging from zero to some [blank_start]maximum value[blank_end]. this value of [blank_start]maximum kinetic energy[blank_end] increases with [blank_start]frequency[blank_end] of the radiation, but is unneffected by the [blank_start]intensity[blank_end] of the radiation.
    the number of photoelectrons emitted per second is proportional to the intensity of the radiation.

    these two conclusions cant be explained using [blank_start]wave theory[blank_end].
    1. Aphotoelectrons
    2. Bemitted
    3. Cradiation
    4. Dbelow
    5. Ethreshold frequency
    6. Fvariety
    7. Gkinetic energies
    8. Hmaximum value
    9. Imaximum kinetic energy
    10. Jfrequency
    11. Kintensity
    12. Lwave theory
  5. 5according to the [blank_start]photon model[blank_end]...
    when [blank_start]light[blank_end] hits the surface, the metal is [blank_start]bombarded[blank_end] by [blank_start]photons[blank_end]
    if one of the photons is [blank_start]absorbed[blank_end] by a free electron, the electron will [blank_start]gain[blank_end] energy equal to [blank_start]hf[blank_end]
    before an electron [blank_start]leaves[blank_end] the surface of a metal, it needs [blank_start]enough energy[blank_end] to break the [blank_start]bonds[blank_end] holding it there. this energy is called the [blank_start]work function[blank_end], its symbol is [blank_start]phi[blank_end] and its value depends on the metal.

    if the [blank_start]surface[blank_end] electron gains energy from a [blank_start]photon[blank_end] that is [blank_start]greater[blank_end] than its work function, the electron is [blank_start]emitted[blank_end].
    if it isn't then no electrons will be emitted by the metal will [blank_start]heat up[blank_end].
    since, for [blank_start]electrons[blank_end] to be released, hf must be greater [blank_start]than phi[blank_end], the [blank_start]threshold frequency[blank_end] must be
    [blank_start]f=phi/h[blank_end]
    h stands for [blank_start]plancks constant[blank_end].
    the energy [blank_start]transferred to an electron[blank_end] is hf. also known as work function.
    the [blank_start]kinetic energy[blank_end] that it will be carrying when it leaves the metal will be [blank_start]hf-any energy[blank_end] its lost on its way out.
    the [blank_start]minimum Ek[blank_end] an electron can lose is the work function [blank_start]energy[blank_end] so the maximum Ek is given by [blank_start]Einsteins photoelectric[blank_end] equation...
    [blank_start]hf=phi+Ekmax[blank_end] where [blank_start]Ekmax=1/2m vmax^2[blank_end]
    the kinetic energy of the electrons is [blank_start]independent[blank_end] of the [blank_start]intensity[blank_end] of the radiation because they can only [blank_start]absorb[blank_end] one photon at a time. a [blank_start]higher intensity[blank_end] means [blank_start]more photons[blank_end] hit a given area per second.

    on a graph of [blank_start]Ekmax Vs frequency[blank_end],
    [blank_start]y=mc+c[blank_end]
    so [blank_start]y=Ekmax[blank_end] which is the energy [blank_start]left over[blank_end] after electrons are [blank_start]liberated[blank_end]
    [blank_start]mx=hf[blank_end] where h[blank_start]=plancks constant[blank_end] and this equals [blank_start]6.63X10^-34Js[blank_end] and f=frequency
    hf= the energy [blank_start]given by a photon[blank_end]
    and [blank_start]+c = -phi[blank_end] where phi is the energy needed to [blank_start]liberate[blank_end]. also known as the work function.

    therefore, when [blank_start]Ekmax=0[blank_end]
    [blank_start]0=hf-phi[blank_end]
    so
    [blank_start]f0=phi/h[blank_end]
    1. Aphoton model
    2. Blight
    3. Cbombarded
    4. Dphotons
    5. Eabsorbed
    6. Fgain
    7. Ghf
    8. Hleaves
    9. Ienough energy
    10. Jbonds
    11. Kwork function
    12. Lphi
    13. Msurface
    14. Nphoton
    15. Ogreater
    16. Pemitted
    17. Qheat up
    18. Relectrons
    19. Sthan phi
    20. Tthreshold frequency
    21. Uf=phi/h
    22. Vplancks constant
    23. Wtransferred to an electron
    24. Xkinetic energy
    25. Yhf-any energy
    26. Zminimum Ek
    27. AAenergy
    28. ABEinsteins photoelectric
    29. AChf=phi+Ekmax
    30. ADEkmax=1/2m vmax^2
    31. AEindependent
    32. AFintensity
    33. AGabsorb
    34. AHhigher intensity
    35. AImore photons
    36. AJEkmax Vs frequency
    37. AKy=Ekmax
    38. ALliberated
    39. AMleft over
    40. ANy=mc+c
    41. AO6.63X10^-34Js
    42. AP=plancks constant
    43. AQmx=hf
    44. ARgiven by a photon
    45. AS+c = -phi
    46. ATliberate
    47. AUEkmax=0
    48. AV0=hf-phi
    49. AWf0=phi/h

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Description
AS level AS PHYSICS Quiz on photoelectric effect, created by abbie Fitzpatrick on 10/07/2017.
Language
English
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