X intercept: y=0 , 0=2x+1 , 2x=-1, x=-1/2
Y intercept: x=0 , y=1/-5 , y=-1/5
Vertical asymptope: x-5 = 0 , x=5
Horizontal asymptope: y=2+1/x / 1-5/x , as x heads to infinity, 1/x heads to 0, so the horizontal asymptope is 2/1, which is y=2
Slightly to left: f(4.99) = 2(4.99)+1 / 4.99 - 5 = -1098, which explains that to the left of the asymptope, the graph tends to the left
Slightly to the right: f(5.01) = 2(5.01)+1 / 5.01 - 5 = 1102 which explains to the right of the asymptope, the graph tends to the right
We can multiply both sides by (x+3)^2 to get x^2+8x+15 > 2x^2+12x+18 , 0 > x^2+4x+3 , 0 > (x+1)(x+3) so x=-1 or -3, therefore -3<x≤-1.
Also we can use a graph to find this, we can see that y=2 intersects with the function at (-1,2) and the functions vertical asymptope is at x=-3, so -3<x≤-1.