# GCSE Maths: Understanding Pythagoras' Theorem

Slide Set by , created almost 4 years ago

## GCSE Maths: Pythagoras theorem - info, visuals, quizzes and applications to help you get to grips with one of the most famous theorems in all of mathematics.

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 Created by Landon Valencia almost 4 years ago Copied by Micheal Heffernan almost 4 years ago
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### Slide 1

Understanding Pythagoras' Theorem
Pythagoras was a famous Greek mathematician and philosopher, and his theorem - known to us simply as "Pythagoras' Theorem" - is his most famous contribution to mathematics.In essence, the theorem concerns triangles containing a right angle (where two perpendicular lines intersect to create an angle of 90 degrees).Over the next few slides, we'll deal with Pythagoras' Theorem in greater detail, looking at what it states, how it is represented as an equation, and how it may be applied to find a missing value.To complete the slide set, there will also be related quizzes and flashcards to further consolidate your understanding of this hugely important mathematical relation.

### Slide 2

Pythagoras' Theorem
How Do I Use it?The Pythagoras theorem deals with the lengths of the sides of a right triangle. It is used any time we have a right triangle, know the length of two sides, and want to find the third side. It is often written in the form of the equation: a2 + b2 = c2 The theorem states that:The sum of the squares of two legs of a right triangle ('a' and 'b' in the triangle shown opposite) is equal to the square of the length of the hypotenuse ('c').

### Slide 3

Is Pythagoras' theorem right?
Let's start by looking at a square whose side length is (a+b). Inside the blue square let's construct a yellow square of side length c. Its corners must touch the sides of the blue square. The remainder of the space will consist of four blue congruent abc triangles. Here it is for our example squares:In each case, the area of the larger blue square is equal to the sum of the areas of the blue triangles and the area of the yellow square. Since the area of a square is (sidelength)2 and the area of a triangle is 1/2(base)(height), we can write the equation: (a+b)2 = c2 + 4[(1/2)ab]        Simplifying:(a+b)2 = c2 + 4[(1/2)ab](a+b)(a+b) = c2 + 2aba2 + 2ab + b2 = c2 + 2ab     Now subtract the 2ab from both sides of the equation, and we have the Pythagorean theorem:  a2 + b2 = c2
Caption: : Pythagoras theorem

### Slide 4

What do you know about Pythagoras theorem?