test of revision 1 G9

Beschreibung

revision: fractions, radical, scientific notation
Zeinab Zeineddine
Quiz von Zeinab Zeineddine, aktualisiert more than 1 year ago
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Zusammenfassung der Ressource

Frage 1

Frage
The GCD of 360 and 48 is
Antworten
  • 24
  • 18
  • 28

Frage 2

Frage
(3×10³×3.6×(10²)^3)/(2.7×10⁻⁴)=
Antworten
  • 4×10¹⁰
  • 4×10¹³
  • 4×10¹⁶

Frage 3

Frage
If x=(a+b)² and y=(a-b)² then x-y=
Antworten
  • 2ab
  • 3ab
  • 4ab

Frage 4

Frage
If A=4√5-4 and B=5√5 then
Antworten
  • A=B
  • A<B
  • A>B

Frage 5

Frage
Given the numbers: A=8/3+5÷(1-2/5) ; B=(55×10³×2¹⁰)/(10⁴×2⁹) ; C=(4+√5)(4-√5) ; D=2√45+√81-3√20+2 then A=B=C=D
Antworten
  • True
  • False

Frage 6

Frage
Given: X=3√27+√48+√75 and Y=√12-2√48+√192. 1) Write X and Y in the form of a√b. 2) Compare X and Y. 3) Rationalize the denominator of: X/(Y+1) 4) Assume that the dimensions of the rectangle ABCD are U and V where U=√XY and V=X+Y. Calculate U and V, then evaluate the area of ABCD.
Antworten
  • 1) X=18√3 ; Y=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=6√3 ; V=20√3 Area=XY=360.
  • 1) Y=18√3 ; X=2√3 2) X>Y 3) X/(Y+1)=(18√3(2√3-1))/11 4) U=√XY=3√3 ; V=2√3 Area=XY=12.

Frage 7

Frage
1) Rationalize the expression: √3/(3√2+√3) 2) Deduce that: √3/(3√2+√3)-(√6-11)/5 is an integer.
Antworten
  • ) √3/(3√2+√3)=(√6+1)/5 2) √3/(3√2+√3)-(√6-11)/5=12/5
  • 1) √3/(3√2+√3)=(√6-1)/5 2) √3/(3√2+√3)-(√6-11)/5=2
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