Quiz
test of revision 1 G9
Questions in this quiz (7)
1The GCD of 360 and 48 is
- A24
- B18
- C28
2(3×10³×3.6×(10²)^3)/(2.7×10⁻⁴)=
- A4×10¹⁰
- B4×10¹³
- C4×10¹⁶
3If x=(a+b)² and y=(a-b)² then x-y=
- A2ab
- B3ab
- C4ab
4If A=4√5-4 and B=5√5 then
- AA=B
- BA<B
- CA>B
5Given the numbers:
A=8/3+5÷(1-2/5) ; B=(55×10³×2¹⁰)/(10⁴×2⁹) ; C=(4+√5)(4-√5) ; D=2√45+√81-3√20+2
then A=B=C=D- ATrue
- BFalse
6Given: X=3√27+√48+√75 and Y=√12-2√48+√192.
1) Write X and Y in the form of a√b.
2) Compare X and Y.
3) Rationalize the denominator of: X/(Y+1)
4) Assume that the dimensions of the rectangle ABCD are U and V where U=√XY and V=X+Y.
Calculate U and V, then evaluate the area of ABCD.- A1) X=18√3 ; Y=2√3
2) X>Y
3) X/(Y+1)=(18√3(2√3-1))/11
4) U=√XY=6√3 ; V=20√3
Area=XY=360. - B1) Y=18√3 ; X=2√3
2) X>Y
3) X/(Y+1)=(18√3(2√3-1))/11
4) U=√XY=3√3 ; V=2√3
Area=XY=12.
- A1) X=18√3 ; Y=2√3
7 1) Rationalize the expression: √3/(3√2+√3)
2) Deduce that: √3/(3√2+√3)-(√6-11)/5 is an integer.- A) √3/(3√2+√3)=(√6+1)/5
2) √3/(3√2+√3)-(√6-11)/5=12/5 - B1) √3/(3√2+√3)=(√6-1)/5
2) √3/(3√2+√3)-(√6-11)/5=2
- A) √3/(3√2+√3)=(√6+1)/5
Information
- Description
- revision: fractions, radical, scientific notation
- Author
- Zeinab Zeineddine
- Language
- English
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