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M = F.d.sen(alfa)
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Barra em Equilíbrio (Mh = Mah)
250N , 3m ; 1.5m , F=?
Ma = 250*3 => 750 NM
Mb = Ma
Mb = F*1.5 => 750/1.5 = F => 500 N
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Barra em Equilíbrio
25 cm , 10 N ; 75 cm , F = ?
Ma = 0,25*10 = 2,5 Nm
2,5 = F * 0,75 => 2,5/0,75 => F = 3,33 N
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- Note on Untitled, created by Italo Matos on 21/06/2024.
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- Italo Matos
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